为了唯一地识别每个设备,我想使用IMEI(或CDMA设备的ESN号)。如何以编程方式访问它?


当前回答

使用以下代码:

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
        String[] permissions = {Manifest.permission.READ_PHONE_STATE};
        if (ActivityCompat.checkSelfPermission(this,
                Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
            requestPermissions(permissions, READ_PHONE_STATE);
        }
    } else {
        try {
            TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
            if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
                return;
            }
            String imei = telephonyManager.getDeviceId();

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

并调用onRequestPermissionsResult方法如下代码:

@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
    switch (requestCode) {
        case READ_PHONE_STATE:
            if (grantResults.length > 0
                    && grantResults[0] == PackageManager.PERMISSION_GRANTED)
                try {
                    TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
                    if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
                        return;
                    }
                    String imei = telephonyManager.getDeviceId();

                } catch (Exception e) {
                    e.printStackTrace();
                }
    }
}

在你的AndroidManifest.xml中添加以下权限:

<uses-permission android:name="android.permission.READ_PHONE_STATE" />

其他回答

试试这个(总是需要第一个IMEI)

TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
        if (ActivityCompat.checkSelfPermission(LoginActivity.this,Manifest.permission.READ_PHONE_STATE)!= PackageManager.PERMISSION_GRANTED) {

         return;
}

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
                if (mTelephony.getPhoneCount() == 2) {
                    IME = mTelephony.getImei(0);
                }else{
                    IME = mTelephony.getImei();
                }
            }else{
                if (mTelephony.getPhoneCount() == 2) {
                    IME = mTelephony.getDeviceId(0);
                } else {
                    IME = mTelephony.getDeviceId();
                }
            }
        } else {
            IME = mTelephony.getDeviceId();
        }

或者你可以使用ANDROID_ID设置从Android.Provider.Settings.System(这里描述strazerre.com)。

这样做的好处是,它不需要特殊的权限,但如果另一个应用程序具有写访问权限并更改它,则可以更改它(这显然不常见,但并非不可能)。

仅供参考,这里是来自博客的代码:

import android.provider.Settings;
import android.provider.Settings.System;   

String androidID = System.getString(this.getContentResolver(),Secure.ANDROID_ID);

实现注意:如果ID对系统架构至关重要,你需要意识到在实践中,一些非常低端的Android手机和平板电脑已经发现重用相同的ANDROID_ID (9774d56d682e549c是显示在我们的日志中的值)

TelephonyManager的getDeviceId()方法返回唯一的设备ID,例如GSM电话的IMEI, CDMA电话的MEID或ESN。如果设备ID不可用,则返回null。

Java代码

package com.AndroidTelephonyManager;

import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.telephony.TelephonyManager;
import android.widget.TextView;

public class AndroidTelephonyManager extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    TextView textDeviceID = (TextView)findViewById(R.id.deviceid);

    //retrieve a reference to an instance of TelephonyManager
    TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);

    textDeviceID.setText(getDeviceID(telephonyManager));

}

String getDeviceID(TelephonyManager phonyManager){

 String id = phonyManager.getDeviceId();
 if (id == null){
  id = "not available";
 }

 int phoneType = phonyManager.getPhoneType();
 switch(phoneType){
 case TelephonyManager.PHONE_TYPE_NONE:
  return "NONE: " + id;

 case TelephonyManager.PHONE_TYPE_GSM:
  return "GSM: IMEI=" + id;

 case TelephonyManager.PHONE_TYPE_CDMA:
  return "CDMA: MEID/ESN=" + id;

 /*
  *  for API Level 11 or above
  *  case TelephonyManager.PHONE_TYPE_SIP:
  *   return "SIP";
  */

 default:
  return "UNKNOWN: ID=" + id;
 }

}
}

XML

<linearlayout android:layout_height="fill_parent" android:layout_width="fill_parent" android:orientation="vertical" xmlns:android="http://schemas.android.com/apk/res/android">
<textview android:layout_height="wrap_content" android:layout_width="fill_parent" android:text="@string/hello">
<textview android:id="@+id/deviceid" android:layout_height="wrap_content" android:layout_width="fill_parent">
</textview></textview></linearlayout> 

许可要求 manifest文件中的READ_PHONE_STATE。

我使用以下代码获取IMEI或使用Secure。ANDROID_ID作为替代,当设备没有电话功能时:

/**
 * Returns the unique identifier for the device
 *
 * @return unique identifier for the device
 */
public String getDeviceIMEI() {
    String deviceUniqueIdentifier = null;
    TelephonyManager tm = (TelephonyManager) this.getSystemService(Context.TELEPHONY_SERVICE);
    if (null != tm) {
        deviceUniqueIdentifier = tm.getDeviceId();
    }
    if (null == deviceUniqueIdentifier || 0 == deviceUniqueIdentifier.length()) {
        deviceUniqueIdentifier = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
    }
    return deviceUniqueIdentifier;
}

你可以使用这个TelephonyManager TELEPHONY_SERVICE函数来获取唯一的设备ID, 要求权限:READ_PHONE_STATE

<uses-permission android:name="android.permission.READ_PHONE_STATE" />

例如,GSM手机的IMEI, CDMA手机的MEID或ESN。

/**
 * Gets the device unique id called IMEI. Sometimes, this returns 00000000000000000 for the
 * rooted devices.
 **/
public static String getDeviceImei(Context ctx) {
    TelephonyManager telephonyManager = (TelephonyManager) ctx.getSystemService(Context.TELEPHONY_SERVICE);
    return telephonyManager.getDeviceId();
}

如果设备ID不可用,则返回null。