为了唯一地识别每个设备,我想使用IMEI(或CDMA设备的ESN号)。如何以编程方式访问它?
当前回答
来自:http://mytechead.wordpress.com/2011/08/28/how-to-get-imei-number-of-android-device/:
下面的代码可以帮助获取android设备的IMEI号码:
TelephonyManager tm = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
String device_id = tm.getDeviceId();
Android Manifest中需要的权限:
android.permission.READ_PHONE_STATE
注意:如平板电脑或不能作为移动电话的设备 IMEI将为空。
其他回答
除了Trevor Johns的回答外,你还可以这样使用:
TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
telephonyManager.getDeviceId();
并且您应该在Manifest.xml文件中添加以下权限:
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
在模拟器中,你可能会得到一个“00000…”的值。如果设备ID不可用,getDeviceId()返回NULL。
TelephonyManager的getDeviceId()方法返回唯一的设备ID,例如GSM电话的IMEI, CDMA电话的MEID或ESN。如果设备ID不可用,则返回null。
Java代码
package com.AndroidTelephonyManager;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.telephony.TelephonyManager;
import android.widget.TextView;
public class AndroidTelephonyManager extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView textDeviceID = (TextView)findViewById(R.id.deviceid);
//retrieve a reference to an instance of TelephonyManager
TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
textDeviceID.setText(getDeviceID(telephonyManager));
}
String getDeviceID(TelephonyManager phonyManager){
String id = phonyManager.getDeviceId();
if (id == null){
id = "not available";
}
int phoneType = phonyManager.getPhoneType();
switch(phoneType){
case TelephonyManager.PHONE_TYPE_NONE:
return "NONE: " + id;
case TelephonyManager.PHONE_TYPE_GSM:
return "GSM: IMEI=" + id;
case TelephonyManager.PHONE_TYPE_CDMA:
return "CDMA: MEID/ESN=" + id;
/*
* for API Level 11 or above
* case TelephonyManager.PHONE_TYPE_SIP:
* return "SIP";
*/
default:
return "UNKNOWN: ID=" + id;
}
}
}
XML
<linearlayout android:layout_height="fill_parent" android:layout_width="fill_parent" android:orientation="vertical" xmlns:android="http://schemas.android.com/apk/res/android">
<textview android:layout_height="wrap_content" android:layout_width="fill_parent" android:text="@string/hello">
<textview android:id="@+id/deviceid" android:layout_height="wrap_content" android:layout_width="fill_parent">
</textview></textview></linearlayout>
许可要求 manifest文件中的READ_PHONE_STATE。
以下代码是为我工作。
val uid: String = Settings.Secure.getString(ctx.applicationContext.contentResolver, Settings.Secure.ANDROID_ID)
if (ContextCompat.checkSelfPermission(ctx, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
imei = when {
Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q -> {
uid
}
Build.VERSION.SDK_INT >= Build.VERSION_CODES.O -> {
telephonyManager.imei
}
else -> {
telephonyManager.deviceId
}
}
}
试试这个(总是需要第一个IMEI)
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(LoginActivity.this,Manifest.permission.READ_PHONE_STATE)!= PackageManager.PERMISSION_GRANTED) {
return;
}
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (mTelephony.getPhoneCount() == 2) {
IME = mTelephony.getImei(0);
}else{
IME = mTelephony.getImei();
}
}else{
if (mTelephony.getPhoneCount() == 2) {
IME = mTelephony.getDeviceId(0);
} else {
IME = mTelephony.getDeviceId();
}
}
} else {
IME = mTelephony.getDeviceId();
}
你需要在AndroidManifest.xml中设置以下权限:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
要获得IMEI(国际移动设备标识符),如果它高于API级别26,那么我们将telephonyManager.getImei()作为null,因此,我们使用ANDROID_ID作为唯一标识符。
public static String getIMEINumber(@NonNull final Context context)
throws SecurityException, NullPointerException {
TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
String imei;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
assert tm != null;
imei = tm.getImei();
//this change is for Android 10 as per security concern it will not provide the imei number.
if (imei == null) {
imei = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
} else {
assert tm != null;
if (tm.getDeviceId() != null && !tm.getDeviceId().equals("000000000000000")) {
imei = tm.getDeviceId();
} else {
imei = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
return imei;
}
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