为了唯一地识别每个设备,我想使用IMEI(或CDMA设备的ESN号)。如何以编程方式访问它?


当前回答

Kotlin代码获取DeviceId (IMEI)处理权限和可比性检查的所有android版本:

 val  telephonyManager = getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
    if (ContextCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE)
        == PackageManager.PERMISSION_GRANTED) {
        // Permission is  granted
        val imei : String? = if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)  telephonyManager.imei
        // older OS  versions
        else  telephonyManager.deviceId

        imei?.let {
            Log.i("Log", "DeviceId=$it" )
        }

    } else {  // Permission is not granted

    }

将此权限添加到AndroidManifest.xml:

<uses-permission android:name="android.permission.READ_PHONE_STATE"/> <!-- IMEI-->

其他回答

使用下面的代码给你IMEI号码:

TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
System.out.println("IMEI::" + telephonyManager.getDeviceId());

除了Trevor Johns的回答外,你还可以这样使用:

TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
telephonyManager.getDeviceId();

并且您应该在Manifest.xml文件中添加以下权限:

<uses-permission android:name="android.permission.READ_PHONE_STATE"/>

在模拟器中,你可能会得到一个“00000…”的值。如果设备ID不可用,getDeviceId()返回NULL。

使用以下代码:

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
        String[] permissions = {Manifest.permission.READ_PHONE_STATE};
        if (ActivityCompat.checkSelfPermission(this,
                Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
            requestPermissions(permissions, READ_PHONE_STATE);
        }
    } else {
        try {
            TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
            if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
                return;
            }
            String imei = telephonyManager.getDeviceId();

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

并调用onRequestPermissionsResult方法如下代码:

@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
    switch (requestCode) {
        case READ_PHONE_STATE:
            if (grantResults.length > 0
                    && grantResults[0] == PackageManager.PERMISSION_GRANTED)
                try {
                    TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
                    if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
                        return;
                    }
                    String imei = telephonyManager.getDeviceId();

                } catch (Exception e) {
                    e.printStackTrace();
                }
    }
}

在你的AndroidManifest.xml中添加以下权限:

<uses-permission android:name="android.permission.READ_PHONE_STATE" />

你可以使用这个TelephonyManager TELEPHONY_SERVICE函数来获取唯一的设备ID, 要求权限:READ_PHONE_STATE

<uses-permission android:name="android.permission.READ_PHONE_STATE" />

例如,GSM手机的IMEI, CDMA手机的MEID或ESN。

/**
 * Gets the device unique id called IMEI. Sometimes, this returns 00000000000000000 for the
 * rooted devices.
 **/
public static String getDeviceImei(Context ctx) {
    TelephonyManager telephonyManager = (TelephonyManager) ctx.getSystemService(Context.TELEPHONY_SERVICE);
    return telephonyManager.getDeviceId();
}

如果设备ID不可用,则返回null。

在API 26中,getDeviceId()被贬低了,所以你可以使用下面的代码来满足API 26和更早的版本

TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
String imei="";
if (android.os.Build.VERSION.SDK_INT >= 26) {
  imei=telephonyManager.getImei();
}
else
{
  imei=telephonyManager.getDeviceId();
}

不要忘记为READ_PHONE_STATE添加使用上述代码的权限请求。

更新: 从Android 10开始,用户应用程序只能获得IMEI等不可重置的硬件标识符。