我正在为Oracle数据库写一些迁移脚本，并希望Oracle有类似于MySQL的IF EXISTS构造的东西。
具体来说，每当我想在MySQL中删除一个表时，我就会做这样的事情
DROP TABLE IF EXISTS `table_name`;
这样，如果表不存在，DROP也不会产生错误，脚本可以继续。
Oracle有类似的机制吗?我意识到我可以使用下面的查询来检查表是否存在
SELECT * FROM dba_tables where table_name = 'table_name';
但是把它和DROP绑定在一起的语法让我很困惑。
当前回答
最好和最有效的方法是捕获“table not found”异常:这避免了检查表是否存在两次的开销;并且不会遇到DROP因为其他原因(可能很重要)失败时仍然会向调用者抛出异常的问题:
BEGIN
EXECUTE IMMEDIATE 'DROP TABLE ' || table_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -942 THEN
RAISE;
END IF;
END;
齿顶高 作为参考，下面是其他对象类型的等效块:
序列
BEGIN
EXECUTE IMMEDIATE 'DROP SEQUENCE ' || sequence_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -2289 THEN
RAISE;
END IF;
END;
View
BEGIN
EXECUTE IMMEDIATE 'DROP VIEW ' || view_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -942 THEN
RAISE;
END IF;
END;
触发
BEGIN
EXECUTE IMMEDIATE 'DROP TRIGGER ' || trigger_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -4080 THEN
RAISE;
END IF;
END;
指数
BEGIN
EXECUTE IMMEDIATE 'DROP INDEX ' || index_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -1418 THEN
RAISE;
END IF;
END;
列
BEGIN
EXECUTE IMMEDIATE 'ALTER TABLE ' || table_name
|| ' DROP COLUMN ' || column_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -904 AND SQLCODE != -942 THEN
RAISE;
END IF;
END;
数据库链接
BEGIN
EXECUTE IMMEDIATE 'DROP DATABASE LINK ' || dblink_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -2024 THEN
RAISE;
END IF;
END;
物化视图
BEGIN
EXECUTE IMMEDIATE 'DROP MATERIALIZED VIEW ' || mview_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -12003 THEN
RAISE;
END IF;
END;
Type
BEGIN
EXECUTE IMMEDIATE 'DROP TYPE ' || type_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -4043 THEN
RAISE;
END IF;
END;
约束
BEGIN
EXECUTE IMMEDIATE 'ALTER TABLE ' || table_name
|| ' DROP CONSTRAINT ' || constraint_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -2443 AND SQLCODE != -942 THEN
RAISE;
END IF;
END;
调度程序工作
BEGIN
DBMS_SCHEDULER.drop_job(job_name);
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -27475 THEN
RAISE;
END IF;
END;
用户/架构
BEGIN
EXECUTE IMMEDIATE 'DROP USER ' || user_name;
/* you may or may not want to add CASCADE */
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -1918 THEN
RAISE;
END IF;
END;
包
BEGIN
EXECUTE IMMEDIATE 'DROP PACKAGE ' || package_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -4043 THEN
RAISE;
END IF;
END;
过程
BEGIN
EXECUTE IMMEDIATE 'DROP PROCEDURE ' || procedure_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -4043 THEN
RAISE;
END IF;
END;
函数
BEGIN
EXECUTE IMMEDIATE 'DROP FUNCTION ' || function_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -4043 THEN
RAISE;
END IF;
END;
表空间
BEGIN
EXECUTE IMMEDIATE 'DROP TABLESPACE ' || tablespace_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -959 THEN
RAISE;
END IF;
END;
同义词
BEGIN
EXECUTE IMMEDIATE 'DROP SYNONYM ' || synonym_name;
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -1434 THEN
RAISE;
END IF;
END;
其他回答
在oracle中没有'DROP TABLE IF EXISTS'，你必须执行select语句。
试试这个(我不上oracle语法，所以如果我的变量是ify，请原谅我):
declare @count int
select @count=count(*) from all_tables where table_name='Table_name';
if @count>0
BEGIN
DROP TABLE tableName;
END
只是想发布一个完整的代码，将创建一个表，并删除它，如果它已经存在使用Jeffrey的代码(赞美他，不是我!)
BEGIN
BEGIN
EXECUTE IMMEDIATE 'DROP TABLE tablename';
EXCEPTION
WHEN OTHERS THEN
IF SQLCODE != -942 THEN
RAISE;
END IF;
END;
EXECUTE IMMEDIATE 'CREATE TABLE tablename AS SELECT * FROM sourcetable WHERE 1=0';
END;
像这样的积木可能对你有用。
DECLARE
table_exist INT;
BEGIN
SELECT Count(*)
INTO table_exist
FROM dba_tables
WHERE owner = 'SCHEMA_NAME'
AND table_name = 'EMPLOYEE_TABLE';
IF table_exist = 1 THEN
EXECUTE IMMEDIATE 'drop table EMPLOYEE_TABLE';
END IF;
END;
您总是可以自己发现错误。
begin
execute immediate 'drop table mytable';
exception when others then null;
end;
过度使用它被认为是不好的实践，类似于其他语言中的空catch()。
问候 K
另一种方法是定义一个异常，然后只捕获该异常，让所有其他异常传播。
Declare
eTableDoesNotExist Exception;
PRAGMA EXCEPTION_INIT(eTableDoesNotExist, -942);
Begin
EXECUTE IMMEDIATE ('DROP TABLE myschema.mytable');
Exception
When eTableDoesNotExist Then
DBMS_Output.Put_Line('Table already does not exist.');
End;
