我发现了一个新的解决方案，可以将视图呈现为字符串，而不必与当前HttpContext的Response流(它不允许您更改响应的ContentType或其他报头)混淆。

基本上，你所要做的就是为视图创建一个伪HttpContext来渲染它自己:

/// <summary>Renders a view to string.</summary>
public static string RenderViewToString(this Controller controller,
                                        string viewName, object viewData) {
    //Create memory writer
    var sb = new StringBuilder();
    var memWriter = new StringWriter(sb);

    //Create fake http context to render the view
    var fakeResponse = new HttpResponse(memWriter);
    var fakeContext = new HttpContext(HttpContext.Current.Request, fakeResponse);
    var fakeControllerContext = new ControllerContext(
        new HttpContextWrapper(fakeContext),
        controller.ControllerContext.RouteData,
        controller.ControllerContext.Controller);

    var oldContext = HttpContext.Current;
    HttpContext.Current = fakeContext;

    //Use HtmlHelper to render partial view to fake context
    var html = new HtmlHelper(new ViewContext(fakeControllerContext,
        new FakeView(), new ViewDataDictionary(), new TempDataDictionary()),
        new ViewPage());
    html.RenderPartial(viewName, viewData);

    //Restore context
    HttpContext.Current = oldContext;    

    //Flush memory and return output
    memWriter.Flush();
    return sb.ToString();
}

/// <summary>Fake IView implementation used to instantiate an HtmlHelper.</summary>
public class FakeView : IView {
    #region IView Members

    public void Render(ViewContext viewContext, System.IO.TextWriter writer) {
        throw new NotImplementedException();
    }

    #endregion
}

这适用于ASP。NET MVC 1.0，以及ContentResult, JsonResult等(改变原始HttpResponse上的报头不会抛出“发送HTTP报头后服务器无法设置内容类型”异常)。

更新:在ASP。NET MVC 2.0 RC，代码有一点变化，因为我们必须传入用于将视图写入ViewContext的StringWriter:

//...

//Use HtmlHelper to render partial view to fake context
var html = new HtmlHelper(
    new ViewContext(fakeControllerContext, new FakeView(),
        new ViewDataDictionary(), new TempDataDictionary(), memWriter),
    new ViewPage());
html.RenderPartial(viewName, viewData);

//...

这对我来说很管用:

public virtual string RenderView(ViewContext viewContext)
{
    var response = viewContext.HttpContext.Response;
    response.Flush();
    var oldFilter = response.Filter;
    Stream filter = null;
    try
    {
        filter = new MemoryStream();
        response.Filter = filter;
        viewContext.View.Render(viewContext, viewContext.HttpContext.Response.Output);
        response.Flush();
        filter.Position = 0;
        var reader = new StreamReader(filter, response.ContentEncoding);
        return reader.ReadToEnd();
    }
    finally
    {
        if (filter != null)
        {
            filter.Dispose();
        }
        response.Filter = oldFilter;
    }
}

对我来说最简单的方法是:

  public string GetFileAsString(string path)
  {
        var html = "";                        

        FileStream fileStream = new FileStream(path, FileMode.Open);

        using (StreamReader reader = new StreamReader(fileStream))
        {
            html += reader.ReadLine();
        }

        return html;
   }

我在电子邮件中使用这个，并确保文件只包含CSS和HTML

快速提示

对于强类型模型，只需将其添加到ViewData。Model属性，然后传递给RenderViewToString。如

this.ViewData.Model = new OrderResultEmailViewModel(order);
string myString = RenderViewToString(this.ControllerContext, "~/Views/Order/OrderResultEmail.aspx", "~/Views/Shared/Site.Master", this.ViewData, this.TempData);

这个答案不在我的路上。这最初来自https://stackoverflow.com/a/2759898/2318354，但在这里我已经展示了如何使用它与“静态”关键字，使它通用于所有控制器。

为此，你必须在类文件中创建静态类。(假设你的类文件名是Utils.cs)

这个例子是剃须刀。

Utils.cs

public static class RazorViewToString
{
    public static string RenderRazorViewToString(this Controller controller, string viewName, object model)
    {
        controller.ViewData.Model = model;
        using (var sw = new StringWriter())
        {
            var viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);
            var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
            viewResult.View.Render(viewContext, sw);
            viewResult.ViewEngine.ReleaseView(controller.ControllerContext, viewResult.View);
            return sw.GetStringBuilder().ToString();
        }
    }
}

现在你可以从你的控制器调用这个类，通过在你的控制器文件中添加命名空间，通过将“this”作为参数传递给控制器，如下所示。

string result = RazorViewToString.RenderRazorViewToString(this ,"ViewName", model);

正如@Sergey给出的建议，这个扩展方法也可以从控制器调用，如下所示

string result = this.RenderRazorViewToString("ViewName", model);

我希望这将有助于您使代码干净整洁。

这是我想到的，它对我很有用。我将以下方法添加到控制器基类中。(你可以在其他地方创建这些静态方法，接受控制器作为参数)

MVC2 .ascx样式

protected string RenderViewToString<T>(string viewPath, T model) {
  ViewData.Model = model;
  using (var writer = new StringWriter()) {
    var view = new WebFormView(ControllerContext, viewPath);
    var vdd = new ViewDataDictionary<T>(model);
    var viewCxt = new ViewContext(ControllerContext, view, vdd,
                                new TempDataDictionary(), writer);
    viewCxt.View.Render(viewCxt, writer);
    return writer.ToString();
  }
}

Razor .cshtml样式

public string RenderRazorViewToString(string viewName, object model)
{
  ViewData.Model = model;
  using (var sw = new StringWriter())
  {
    var viewResult = ViewEngines.Engines.FindPartialView(ControllerContext,
                                                             viewName);
    var viewContext = new ViewContext(ControllerContext, viewResult.View,
                                 ViewData, TempData, sw);
    viewResult.View.Render(viewContext, sw);
    viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);
    return sw.GetStringBuilder().ToString();
  }
}

编辑:添加剃刀代码。