如何渲染一个ASP。NET MVC视图作为字符串?

我想输出两个不同的视图(一个作为字符串，将作为电子邮件发送)，另一个是显示给用户的页面。

这在ASP中可能吗?NET MVC beta版?

我试过很多例子:

1. 在ASP。NET MVC Beta版

如果我使用这个例子，我会收到“HTTP后不能重定向” 报头已发送。”

2. MVC框架:捕获视图的输出

如果我使用这个，我似乎无法做一个重定向toaction，因为它试图呈现一个可能不存在的视图。如果我返回视图完全是一团糟，看起来一点都不对。

有人对我提出的这些问题有什么想法/解决方案吗?或者有什么更好的建议吗?

很多谢谢!

下面是一个例子。我要做的是创建GetViewForEmail方法:

public ActionResult OrderResult(string ref)
{
    //Get the order
    Order order = OrderService.GetOrder(ref);

    //The email helper would do the meat and veg by getting the view as a string
    //Pass the control name (OrderResultEmail) and the model (order)
    string emailView = GetViewForEmail("OrderResultEmail", order);

    //Email the order out
    EmailHelper(order, emailView);
    return View("OrderResult", order);
}

接受蒂姆·斯科特的回答(我做了一些修改和格式化):

public virtual string RenderViewToString(
    ControllerContext controllerContext,
    string viewPath,
    string masterPath,
    ViewDataDictionary viewData,
    TempDataDictionary tempData)
{
    Stream filter = null;
    ViewPage viewPage = new ViewPage();

    //Right, create our view
    viewPage.ViewContext = new ViewContext(controllerContext, new WebFormView(viewPath, masterPath), viewData, tempData);

    //Get the response context, flush it and get the response filter.
    var response = viewPage.ViewContext.HttpContext.Response;
    response.Flush();
    var oldFilter = response.Filter;

    try
    {
        //Put a new filter into the response
        filter = new MemoryStream();
        response.Filter = filter;

        //Now render the view into the memorystream and flush the response
        viewPage.ViewContext.View.Render(viewPage.ViewContext, viewPage.ViewContext.HttpContext.Response.Output);
        response.Flush();

        //Now read the rendered view.
        filter.Position = 0;
        var reader = new StreamReader(filter, response.ContentEncoding);
        return reader.ReadToEnd();
    }
    finally
    {
        //Clean up.
        if (filter != null)
        {
            filter.Dispose();
        }

        //Now replace the response filter
        response.Filter = oldFilter;
    }
}

示例使用

假设控制器通过Site调用订单确认电子邮件。主人的位置。

string myString = RenderViewToString(this.ControllerContext, "~/Views/Order/OrderResultEmail.aspx", "~/Views/Shared/Site.Master", this.ViewData, this.TempData);

当前回答

为了重复一个更未知的问题，看一下MvcIntegrationTestFramework。

它使您节省编写自己的助手流的结果，并被证明工作得足够好。我假设这将在一个测试项目中，作为奖励，一旦您获得了这个设置，您将拥有其他测试功能。主要的麻烦可能是整理依赖链。

 private static readonly string mvcAppPath = 
     Path.GetFullPath(AppDomain.CurrentDomain.BaseDirectory 
     + "\\..\\..\\..\\MyMvcApplication");
 private readonly AppHost appHost = new AppHost(mvcAppPath);

    [Test]
    public void Root_Url_Renders_Index_View()
    {
        appHost.SimulateBrowsingSession(browsingSession => {
            RequestResult result = browsingSession.ProcessRequest("");
            Assert.IsTrue(result.ResponseText.Contains("<!DOCTYPE html"));
        });
}

2010-03-31 15:58:05

其他回答

这对我来说很管用:

public virtual string RenderView(ViewContext viewContext)
{
    var response = viewContext.HttpContext.Response;
    response.Flush();
    var oldFilter = response.Filter;
    Stream filter = null;
    try
    {
        filter = new MemoryStream();
        response.Filter = filter;
        viewContext.View.Render(viewContext, viewContext.HttpContext.Response.Output);
        response.Flush();
        filter.Position = 0;
        var reader = new StreamReader(filter, response.ContentEncoding);
        return reader.ReadToEnd();
    }
    finally
    {
        if (filter != null)
        {
            filter.Dispose();
        }
        response.Filter = oldFilter;
    }
}

2009-01-27 19:48:12

对我来说最简单的方法是:

  public string GetFileAsString(string path)
  {
        var html = "";                        

        FileStream fileStream = new FileStream(path, FileMode.Open);

        using (StreamReader reader = new StreamReader(fileStream))
        {
            html += reader.ReadLine();
        }

        return html;
   }

我在电子邮件中使用这个，并确保文件只包含CSS和HTML

2021-11-19 17:59:21

asp.net CORE的额外提示:

接口:

public interface IViewRenderer
{
  Task<string> RenderAsync<TModel>(Controller controller, string name, TModel model);
}

实现:

public class ViewRenderer : IViewRenderer
{
  private readonly IRazorViewEngine viewEngine;

  public ViewRenderer(IRazorViewEngine viewEngine) => this.viewEngine = viewEngine;

  public async Task<string> RenderAsync<TModel>(Controller controller, string name, TModel model)
  {
    ViewEngineResult viewEngineResult = this.viewEngine.FindView(controller.ControllerContext, name, false);

    if (!viewEngineResult.Success)
    {
      throw new InvalidOperationException(string.Format("Could not find view: {0}", name));
    }

    IView view = viewEngineResult.View;
    controller.ViewData.Model = model;

    await using var writer = new StringWriter();
    var viewContext = new ViewContext(
       controller.ControllerContext,
       view,
       controller.ViewData,
       controller.TempData,
       writer,
       new HtmlHelperOptions());

       await view.RenderAsync(viewContext);

       return writer.ToString();
  }
}

在Startup.cs中注册

...
 services.AddSingleton<IViewRenderer, ViewRenderer>();
...

在控制器中的使用:

public MyController: Controller
{
  private readonly IViewRenderer renderer;
  public MyController(IViewRendere renderer) => this.renderer = renderer;
  public async Task<IActionResult> MyViewTest
  {
    var view = await this.renderer.RenderAsync(this, "MyView", model);
    return new OkObjectResult(view);
  }
}

2019-09-28 08:19:18

你可以用这种方法获取字符串中的视图

protected string RenderPartialViewToString(string viewName, object model)
{
    if (string.IsNullOrEmpty(viewName))
        viewName = ControllerContext.RouteData.GetRequiredString("action");

    if (model != null)
        ViewData.Model = model;

    using (StringWriter sw = new StringWriter())
    {
        ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
        ViewContext viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
        viewResult.View.Render(viewContext, sw);

        return sw.GetStringBuilder().ToString();
    }
}

我们可以用两种方式调用这个方法

string strView = RenderPartialViewToString("~/Views/Shared/_Header.cshtml", null)

var model = new Person()
string strView = RenderPartialViewToString("~/Views/Shared/_Header.cshtml", model)

2015-03-23 12:47:24

这个答案不在我的路上。这最初来自https://stackoverflow.com/a/2759898/2318354，但在这里我已经展示了如何使用它与“静态”关键字，使它通用于所有控制器。

为此，你必须在类文件中创建静态类。(假设你的类文件名是Utils.cs)

这个例子是剃须刀。

Utils.cs

public static class RazorViewToString
{
    public static string RenderRazorViewToString(this Controller controller, string viewName, object model)
    {
        controller.ViewData.Model = model;
        using (var sw = new StringWriter())
        {
            var viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);
            var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
            viewResult.View.Render(viewContext, sw);
            viewResult.ViewEngine.ReleaseView(controller.ControllerContext, viewResult.View);
            return sw.GetStringBuilder().ToString();
        }
    }
}

现在你可以从你的控制器调用这个类，通过在你的控制器文件中添加命名空间，通过将“this”作为参数传递给控制器，如下所示。

string result = RazorViewToString.RenderRazorViewToString(this ,"ViewName", model);

正如@Sergey给出的建议，这个扩展方法也可以从控制器调用，如下所示

string result = this.RenderRazorViewToString("ViewName", model);

我希望这将有助于您使代码干净整洁。

2013-09-24 09:42:01

如何渲染一个ASP。NET MVC视图作为字符串?

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