我需要一个非常非常快的方法来检查字符串是否为JSON。我觉得这不是最好的方式:

function isJson($string) {
    return ((is_string($string) &&
            (is_object(json_decode($string)) ||
            is_array(json_decode($string))))) ? true : false;
}

有没有表演爱好者想改进这种方法?


当前回答

使用PHPBench和下面的类,得到了以下结果:

<?php

declare(strict_types=1);

/**
 * @Revs(1000)
 * @Iterations(100)
 */
class BenchmarkJson
{
    public function benchCatchValid(): bool
    {
        $validJson = '{"validJson":true}';
        try {
            json_decode($validJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchCatchInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        try {
            json_decode($invalidJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchLastErrorValid(): bool
    {
        $validJson = '{"validJson":true}';
        json_decode($validJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchLastErrorInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        json_decode($invalidJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchNullValid(): bool
    {
        $validJson = '{"validJson":true}';
        return (json_decode($validJson, true) !== null);
    }

    public function benchNullInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        return (json_decode($invalidJson, true) !== null);
    }
}

6 subjects, 600 iterations, 6,000 revs, 0 rejects, 0 failures, 0 warnings
(best [mean mode] worst) = 0.714 [1.203 1.175] 1.073 (μs)
⅀T: 721.504μs μSD/r 0.089μs μRSD/r: 7.270%
suite: 1343ab9a3590de6065bc0bc6eeb344c9f6eba642, date: 2020-01-21, stime: 12:50:14
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| benchmark     | subject               | set | revs | its | mem_peak   | best    | mean    | mode    | worst   | stdev   | rstdev | diff  |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| BenchmarkJson | benchCatchValid       | 0   | 1000 | 100 | 2,980,168b | 0.954μs | 1.032μs | 1.016μs | 1.428μs | 0.062μs | 6.04%  | 1.33x |
| BenchmarkJson | benchCatchInvalid     | 0   | 1000 | 100 | 2,980,184b | 2.033μs | 2.228μs | 2.166μs | 3.001μs | 0.168μs | 7.55%  | 2.88x |
| BenchmarkJson | benchLastErrorValid   | 0   | 1000 | 100 | 2,980,184b | 1.076μs | 1.195μs | 1.169μs | 1.616μs | 0.083μs | 6.97%  | 1.54x |
| BenchmarkJson | benchLastErrorInvalid | 0   | 1000 | 100 | 2,980,184b | 0.785μs | 0.861μs | 0.863μs | 1.132μs | 0.056μs | 6.54%  | 1.11x |
| BenchmarkJson | benchNullValid        | 0   | 1000 | 100 | 2,980,168b | 0.985μs | 1.124μs | 1.077μs | 1.731μs | 0.114μs | 10.15% | 1.45x |
| BenchmarkJson | benchNullInvalid      | 0   | 1000 | 100 | 2,980,184b | 0.714μs | 0.775μs | 0.759μs | 1.073μs | 0.049μs | 6.36%  | 1.00x |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+

结论:检查json是否有效的最快方法是返回json_decode($json, true) !== null)。

其他回答

在GuzzleHttp:

/**
 * Wrapper for json_decode that throws when an error occurs.
 *
 * @param string $json    JSON data to parse
 * @param bool $assoc     When true, returned objects will be converted
 *                        into associative arrays.
 * @param int    $depth   User specified recursion depth.
 * @param int    $options Bitmask of JSON decode options.
 *
 * @return mixed
 * @throws \InvalidArgumentException if the JSON cannot be decoded.
 * @link http://www.php.net/manual/en/function.json-decode.php
 */
function json_decode($json, $assoc = false, $depth = 512, $options = 0)
{
    $data = \json_decode($json, $assoc, $depth, $options);
    if (JSON_ERROR_NONE !== json_last_error()) {
        throw new \InvalidArgumentException(
            'json_decode error: ' . json_last_error_msg());
    }

    return $data;
}

/**
 * Wrapper for JSON encoding that throws when an error occurs.
 *
 * @param mixed $value   The value being encoded
 * @param int    $options JSON encode option bitmask
 * @param int    $depth   Set the maximum depth. Must be greater than zero.
 *
 * @return string
 * @throws \InvalidArgumentException if the JSON cannot be encoded.
 * @link http://www.php.net/manual/en/function.json-encode.php
 */
function json_encode($value, $options = 0, $depth = 512)
{
    $json = \json_encode($value, $options, $depth);
    if (JSON_ERROR_NONE !== json_last_error()) {
        throw new \InvalidArgumentException(
            'json_encode error: ' . json_last_error_msg());
    }

    return $json;
}
//Tested thoroughly, Should do the job:
public static function is_json(string $json):bool
{
    json_decode($json);
    if (json_last_error() === JSON_ERROR_NONE) {
        return true;
    }
    return false;
}

我使用的最简单和最快的方法是跟随;

$json_array = json_decode( $raw_json , true );

if( $json_array == NULL )   //check if it was invalid json string
    die ('Invalid');  // Invalid JSON error

 // you can execute some else condition over here in case of valid JSON

这是因为如果输入的字符串不是json或无效json, json_decode()将返回NULL。


验证JSON的简单函数

如果您必须在多个地方验证JSON,您总是可以使用下面的函数。

function is_valid_json( $raw_json ){
    return ( json_decode( $raw_json , true ) == NULL ) ? false : true ; // Yes! thats it.
}

在上面的函数中,如果它是一个有效的JSON,则返回true。

这就是我的建议

if (!in_array(substr($string, 0, 1), ['{', '[']) || !in_array(substr($string, -1), ['}', ']'])) {
  return false;
} else {
  json_decode($string);
  return (json_last_error() === JSON_ERROR_NONE);
}

我试过其中的一些方法,但没有一种对我有效。我尝试了这么简单的事情:

$isJson = json_decode($myJSON);

if ($isJson instanceof \stdClass || is_array($isJson)) {
   echo("it's JSON confirmed");
} else {
   echo("nope");
}

我认为这是一个很好的解决方案,因为JSON解码没有第二个参数给出一个对象。

编辑:如果知道输入内容,就可以根据需要调整代码。在我的情况下,我知道我有一个Json以“{”开始,所以我不需要检查它是否是一个数组。