我有一个具有Nullable DateOfBirth属性的Person对象。是否有一种方法可以使用LINQ来查询Person对象列表中最早/最小的DateOfBirth值?

这是我的开场白:

var firstBornDate = People.Min(p => p.DateOfBirth.GetValueOrDefault(DateTime.MaxValue));

Null DateOfBirth值被设置为DateTime。MaxValue,以便将它们排除在Min考虑之外(假设至少有一个具有指定的DOB)。

但是所有这些对我来说都是将firstBornDate设置为DateTime值。我想要的是与之匹配的Person对象。我是否需要像这样写第二个查询:

var firstBorn = People.Single(p=> (p.DateOfBirth ?? DateTime.MaxValue) == firstBornDate);

或者有没有更精简的方法?


当前回答

另一种实现,可以使用可空的选择器键,如果没有找到合适的元素,则对于引用类型集合返回null。 例如,这对处理数据库结果很有帮助。

  public static class IEnumerableExtensions
  {
    /// <summary>
    /// Returns the element with the maximum value of a selector function.
    /// </summary>
    /// <typeparam name="TSource">The type of the elements of source.</typeparam>
    /// <typeparam name="TKey">The type of the key returned by keySelector.</typeparam>
    /// <param name="source">An IEnumerable collection values to determine the element with the maximum value of.</param>
    /// <param name="keySelector">A function to extract the key for each element.</param>
    /// <exception cref="System.ArgumentNullException">source or keySelector is null.</exception>
    /// <exception cref="System.InvalidOperationException">source contains no elements.</exception>
    /// <returns>The element in source with the maximum value of a selector function.</returns>
    public static TSource MaxBy<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector) => MaxOrMinBy(source, keySelector, 1);

    /// <summary>
    /// Returns the element with the minimum value of a selector function.
    /// </summary>
    /// <typeparam name="TSource">The type of the elements of source.</typeparam>
    /// <typeparam name="TKey">The type of the key returned by keySelector.</typeparam>
    /// <param name="source">An IEnumerable collection values to determine the element with the minimum value of.</param>
    /// <param name="keySelector">A function to extract the key for each element.</param>
    /// <exception cref="System.ArgumentNullException">source or keySelector is null.</exception>
    /// <exception cref="System.InvalidOperationException">source contains no elements.</exception>
    /// <returns>The element in source with the minimum value of a selector function.</returns>
    public static TSource MinBy<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector) => MaxOrMinBy(source, keySelector, -1);


    private static TSource MaxOrMinBy<TSource, TKey>
      (IEnumerable<TSource> source, Func<TSource, TKey> keySelector, int sign)
    {
      if (source == null) throw new ArgumentNullException(nameof(source));
      if (keySelector == null) throw new ArgumentNullException(nameof(keySelector));
      Comparer<TKey> comparer = Comparer<TKey>.Default;
      TKey value = default(TKey);
      TSource result = default(TSource);

      bool hasValue = false;

      foreach (TSource element in source)
      {
        TKey x = keySelector(element);
        if (x != null)
        {
          if (!hasValue)
          {
            value = x;
            result = element;
            hasValue = true;
          }
          else if (sign * comparer.Compare(x, value) > 0)
          {
            value = x;
            result = element;
          }
        }
      }

      if ((result != null) && !hasValue)
        throw new InvalidOperationException("The source sequence is empty");

      return result;
    }
  }

例子:

public class A
{
  public int? a;
  public A(int? a) { this.a = a; }
}

var b = a.MinBy(x => x.a);
var c = a.MaxBy(x => x.a);

其他回答

不幸的是,没有内置的方法来做到这一点,但它很容易为自己实现。以下是它的核心内容:

public static TSource MinBy<TSource, TKey>(this IEnumerable<TSource> source,
    Func<TSource, TKey> selector)
{
    return source.MinBy(selector, null);
}

public static TSource MinBy<TSource, TKey>(this IEnumerable<TSource> source,
    Func<TSource, TKey> selector, IComparer<TKey> comparer)
{
    if (source == null) throw new ArgumentNullException("source");
    if (selector == null) throw new ArgumentNullException("selector");
    comparer ??= Comparer<TKey>.Default;

    using (var sourceIterator = source.GetEnumerator())
    {
        if (!sourceIterator.MoveNext())
        {
            throw new InvalidOperationException("Sequence contains no elements");
        }
        var min = sourceIterator.Current;
        var minKey = selector(min);
        while (sourceIterator.MoveNext())
        {
            var candidate = sourceIterator.Current;
            var candidateProjected = selector(candidate);
            if (comparer.Compare(candidateProjected, minKey) < 0)
            {
                min = candidate;
                minKey = candidateProjected;
            }
        }
        return min;
    }
}

使用示例:

var firstBorn = People.MinBy(p => p.DateOfBirth ?? DateTime.MaxValue);

请注意,如果序列为空,将抛出异常,如果有多个元素,则返回第一个具有最小值的元素。

或者,你也可以在MinBy.cs中使用MoreLINQ中的实现。(当然,有一个相应的MaxBy。)

通过包管理器控制台安装:

PM>安装包morelinq

试试下面的方法:

var firstBornDate = People.GroupBy(p => p.DateOfBirth).Min(g => g.Key).FirstOrDefault();

通过IEnumerable上的扩展函数返回对象和找到的最小值的方法。它接受一个可以对集合中的对象执行任何操作的Func:

public static (double min, T obj) tMin<T>(this IEnumerable<T> ienum, 
            Func<T, double> aFunc)
        {
            var okNull = default(T);
            if (okNull != null)
                throw new ApplicationException("object passed to Min not nullable");

            (double aMin, T okObj) best = (double.MaxValue, okNull);
            foreach (T obj in ienum)
            {
                double q = aFunc(obj);
                if (q < best.aMin)
                    best = (q, obj);
            }
            return (best);
        }

例子,对象是一个机场,我们想找到最近的机场到给定的(纬度,经度)。机场有纬度(纬度、纬度)功能。

(double okDist, Airport best) greatestPort = airPorts.tMin(x => x.dist(okLat, okLon));

这是一个获取最小值和最大值的简单方法:

    `dbcontext.tableName.Select(x=>x.Feild1).Min()`
    

你可以使用现有的linq扩展,比如MoreLinq。但如果你只需要这些方法,那么你可以使用这里的简单代码:

public static IEnumerable<T> MinBys<T>(this IEnumerable<T> collection, Func<T, IComparable> selector)
{
    var dict = collection.GroupBy(selector).ToDictionary(g => g.Key);
    return dict[dict.Keys.Min()];
}
public static IEnumerable<T> MaxBys<T>(this IEnumerable<T> collection, Func<T, IComparable> selector)
{
    var dict = collection.GroupBy(selector).ToDictionary(g => g.Key);
    return dict[dict.Keys.Max()];
}