我有一个对话框与EditText进行输入。当我单击对话框上的“是”按钮时，它将验证输入，然后关闭对话框。但是，如果输入错误，我希望保持在同一对话框中。每次无论输入是什么，当我单击“否”按钮时，对话框都会自动关闭。如何禁用此功能？顺便说一句，我在对话框中使用了PositiveButton和NegativeButton。
当前回答
可以添加builder.show（）；在返回之前的验证消息之后；
这样地
public void login()
{
final AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setView(R.layout.login_layout);
builder.setTitle("Login");
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
dialog.cancel();
}
});// put the negative button before the positive button, so it will appear
builder.setPositiveButton("Ok", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
Dialog d = (Dialog) dialog;
final EditText etUserName = (EditText) d.findViewById(R.id.etLoginName);
final EditText etPassword = (EditText) d.findViewById(R.id.etLoginPassword);
String userName = etUserName.getText().toString().trim();
String password = etPassword.getText().toString().trim();
if (userName.isEmpty() || password.isEmpty())
{
Toast.makeText(getApplicationContext(),
"Please Fill all fields", Toast.LENGTH_SHORT).show();
builder.show();// here after validation message before retrun
// it will reopen the dialog
// till the user enter the right condition
return;
}
user = Manager.get(getApplicationContext()).getUserByName(userName);
if (user == null)
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
if (password.equals(user.getPassword()))
{
etPassword.setText("");
etUserName.setText("");
setLogged(1);
setLoggedId(user.getUserId());
Toast.makeText(getApplicationContext(),
"Successfully logged in", Toast.LENGTH_SHORT).show();
dialog.dismiss();// if every thing is ok then dismiss the dialog
}
else
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
}
});
builder.show();
}
其他回答
超简单的Kotlin方法
with(AlertDialog.Builder(this)) {
setTitle("Title")
setView(R.layout.dialog_name)
setPositiveButton("Ok", null)
setNegativeButton("Cancel") { _, _ -> }
create().apply {
setOnShowListener {
getButton(AlertDialog.BUTTON_POSITIVE).setOnClickListener {
//Validate and dismiss
dismiss()
}
}
}
}.show()
受汤姆的回答启发，我认为这里的想法是：
在创建对话框期间将onClickListener设置为null然后在显示对话框后设置onClickListener。
您可以像Tom一样重写onShowListener。或者，您可以
调用AlertDialog的show（）后获取按钮按如下方式设置按钮的onClickListener（我认为稍微可读一些）。
代码：
AlertDialog.Builder builder = new AlertDialog.Builder(context);
// ...
final AlertDialog dialog = builder.create();
dialog.show();
// now you can override the default onClickListener
Button b = dialog.getButton(AlertDialog.BUTTON_POSITIVE);
b.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Log.i(TAG, "ok button is clicked");
handleClick(dialog);
}
});
可以添加builder.show（）；在返回之前的验证消息之后；
这样地
public void login()
{
final AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setView(R.layout.login_layout);
builder.setTitle("Login");
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
dialog.cancel();
}
});// put the negative button before the positive button, so it will appear
builder.setPositiveButton("Ok", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
Dialog d = (Dialog) dialog;
final EditText etUserName = (EditText) d.findViewById(R.id.etLoginName);
final EditText etPassword = (EditText) d.findViewById(R.id.etLoginPassword);
String userName = etUserName.getText().toString().trim();
String password = etPassword.getText().toString().trim();
if (userName.isEmpty() || password.isEmpty())
{
Toast.makeText(getApplicationContext(),
"Please Fill all fields", Toast.LENGTH_SHORT).show();
builder.show();// here after validation message before retrun
// it will reopen the dialog
// till the user enter the right condition
return;
}
user = Manager.get(getApplicationContext()).getUserByName(userName);
if (user == null)
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
if (password.equals(user.getPassword()))
{
etPassword.setText("");
etUserName.setText("");
setLogged(1);
setLoggedId(user.getUserId());
Toast.makeText(getApplicationContext(),
"Successfully logged in", Toast.LENGTH_SHORT).show();
dialog.dismiss();// if every thing is ok then dismiss the dialog
}
else
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
}
});
builder.show();
}
科特林
val dialogView = LayoutInflater.from(requireContext()).inflate(R.layout.dialog_userinput, null)
val dialogBuilder = MaterialAlertDialogBuilder(requireContext(), R.style.AlertDialogTheme)
dialogBuilder.setView(dialogView)
dialogBuilder.setCancelable(false)
dialogBuilder.setPositiveButton("send",null)
dialogBuilder.setNegativeButton("cancel") { dialog,_ ->
dialog.dismiss()
}
val alertDialog = dialogBuilder.create()
alertDialog.show()
val positiveButton = alertDialog.getButton(AlertDialog.BUTTON_POSITIVE)
positiveButton.setOnClickListener {
val myInputText = dialogView.etxt_userinput.text.toString().trim()
if(myInputText.isNotEmpty()){
//Do something
}else{
//Prompt error
dialogView.etxt_userinput.error = "Please fill this"
}
}
我们只需使用dialogBuilder创建一个AlertDialog，然后根据需要设置肯定按钮
防止对话框在单击时关闭，并且仅在internet可用时关闭
我也在尝试做同样的事情，因为我不希望对话框在互联网连接之前关闭。
这是我的代码：
AlertDialog.Builder builder=new AlertDialog.Builder(MainActivity.this); builder.setTitle("Internet Not Connected");
if(ifConnected()){
Toast.makeText(this, "Connected or not", Toast.LENGTH_LONG).show();
}
else{
builder.setPositiveButton("Retry", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
if(!ifConnected())
{
builder.show();
}
}
}).setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
finish();
}
});
builder.show();
}
这是我的连接管理器代码：
private boolean ifConnected()
{
ConnectivityManager connectivityManager= (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo networkInfo=connectivityManager.getActiveNetworkInfo();
return networkInfo!=null && networkInfo.isConnected();
}
推荐文章
- PreferenceManager getDefaultSharedPreferences在Android Q中已弃用
- 在Android Studio中创建aar文件
- 修改抽射超时时间
- 如何通过数据从第二个活动到第一个活动时按回?——安卓
- 如何在android中获得当前前景活动上下文?
- 如何在Android中获取当前日期?
- 获取Android设备名称
- 在WebView中上传文件
- 加载HTML文件到WebView
- Android:为什么视图没有maxHeight ?
- 如何获得具有已知资源名称的资源id ?
- 在Android上将字符串转换为整数
- 为什么“System.out。”println“工作在Android?
- WebView显示err_cleartext_not_allowed尽管站点是HTTPS
- 禁用在角材质对话框区域外单击以关闭对话框(angular 4.0+版本)
