可以添加builder.show（）；在返回之前的验证消息之后；

这样地

    public void login()
{
    final AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setView(R.layout.login_layout);
    builder.setTitle("Login");



    builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener()
    {
        @Override
        public void onClick(DialogInterface dialog, int id)
        {
            dialog.cancel();
        }
    });// put the negative button before the positive button, so it will appear

    builder.setPositiveButton("Ok", new DialogInterface.OnClickListener()
    {
        @Override
        public void onClick(DialogInterface dialog, int id)
        {
            Dialog d = (Dialog) dialog;
            final EditText etUserName = (EditText) d.findViewById(R.id.etLoginName);
            final EditText etPassword = (EditText) d.findViewById(R.id.etLoginPassword);
            String userName = etUserName.getText().toString().trim();
            String password = etPassword.getText().toString().trim();

            if (userName.isEmpty() || password.isEmpty())
            {

                Toast.makeText(getApplicationContext(),
                        "Please Fill all fields", Toast.LENGTH_SHORT).show();
                builder.show();// here after validation message before retrun
                               //  it will reopen the dialog
                              // till the user enter the right condition
                return;
            }

            user = Manager.get(getApplicationContext()).getUserByName(userName);

            if (user == null)
            {
                Toast.makeText(getApplicationContext(),
                        "Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
                builder.show();
                return;
            }
            if (password.equals(user.getPassword()))
            {
                etPassword.setText("");
                etUserName.setText("");
                setLogged(1);
                setLoggedId(user.getUserId());
                Toast.makeText(getApplicationContext(),
                        "Successfully logged in", Toast.LENGTH_SHORT).show();
               dialog.dismiss();// if every thing is ok then dismiss the dialog
            }
            else
            {
                Toast.makeText(getApplicationContext(),
                        "Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
                builder.show();
                return;
            }

        }
    });

    builder.show();

}

受汤姆的回答启发，我认为这里的想法是：

在创建对话框期间将onClickListener设置为null然后在显示对话框后设置onClickListener。

您可以像Tom一样重写onShowListener。或者，您可以

调用AlertDialog的show（）后获取按钮按如下方式设置按钮的onClickListener（我认为稍微可读一些）。

代码：

AlertDialog.Builder builder = new AlertDialog.Builder(context);
// ...
final AlertDialog dialog = builder.create();
dialog.show();
// now you can override the default onClickListener
Button b = dialog.getButton(AlertDialog.BUTTON_POSITIVE);
b.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        Log.i(TAG, "ok button is clicked");
        handleClick(dialog);
    }
});

这段代码对你有用，因为我有一个类似的问题，这对我有用。：）

1-重写片段对话框类中的Onstart（）方法。

@Override
public void onStart() {
    super.onStart();
    final AlertDialog D = (AlertDialog) getDialog();
    if (D != null) {
        Button positive = (Button) D.getButton(Dialog.BUTTON_POSITIVE);
        positive.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View arg0) {
                if (edittext.equals("")) {
   Toast.makeText(getActivity(), "EditText empty",Toast.LENGTH_SHORT).show();
                } else {
                D.dismiss(); //dissmiss dialog
                }
            }
        });
    }
}

对于ProgressDialogs

要防止对话框自动关闭，必须在显示ProgressDialog后设置OnClickListener，如下所示：

connectingDialog = new ProgressDialog(this);

connectingDialog.setCancelable(false);
connectingDialog.setCanceledOnTouchOutside(false);

// Create the button but set the listener to a null object.
connectingDialog.setButton(DialogInterface.BUTTON_NEGATIVE, "Cancel", 
        (DialogInterface.OnClickListener) null )

// Show the dialog so we can then get the button from the view.
connectingDialog.show();

// Get the button from the view.
Button dialogButton = connectingDialog.getButton( DialogInterface.BUTTON_NEGATIVE);

// Set the onClickListener here, in the view.
dialogButton.setOnClickListener( new View.OnClickListener() {

    @Override
    public void onClick ( View v ) {

        // Dialog will not get dismissed until you call dismiss() explicitly.

    }

});

我找到了另一种方法来实现这一点。。。

步骤1：将对话框打开代码放入方法（或C中的函数）。步骤2：在onClick of yes（您的positiveButton）中，调用此对话框打开如果条件不满足，则递归使用方法（通过使用if…else…）。如下所示：

private void openSave() {
   
    final AlertDialog.Builder builder=new AlertDialog.Builder(Phase2Activity.this);

    builder.setTitle("SAVE")
            .setIcon(R.drawable.ic_save_icon)
            .setPositiveButton("Save", new DialogInterface.OnClickListener() {
                @Override
                public void onClick(DialogInterface dialogInterface, int i) {
                    
                        if((!editText.getText().toString().isEmpty() && !editText1.getText().toString().isEmpty())){

                                createPdf(fileName,title,file);
                            
                        }else {
                            openSave();
                            Toast.makeText(Phase2Activity.this, "Some fields are empty.", Toast.LENGTH_SHORT).show();
                        }

                    
            })
            .setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialogInterface, int i) {
               dialogInterface.dismiss();
            }
        })
            .setCancelable(false)
            .create()
            .show();

}

但这将使对话框消失片刻，并立即再次出现。：）

这个链接的答案是一个简单的解决方案，它与API 3兼容。它与Tom Bollwitt的解决方案非常相似，但没有使用兼容性较差的OnShowListener。

是的，你可以。您基本上需要：使用DialogBuilder创建对话框show（）对话框在显示的对话框中查找按钮并覆盖其onClickListener

自从我扩展EditTextPreference以来，我对Kamen的代码进行了一些小的修改。

@Override
protected void showDialog(Bundle state) {
  super.showDialog(state);

  class mocl implements OnClickListener{
    private final AlertDialog dialog;
    public mocl(AlertDialog dialog) {
          this.dialog = dialog;
      }
    @Override
    public void onClick(View v) {

        //checks if EditText is empty, and if so tells the user via Toast
        //otherwise it closes dialog and calls the EditTextPreference's onClick
        //method to let it know that the button has been pressed

        if (!IntPreference.this.getEditText().getText().toString().equals("")){
        dialog.dismiss();
        IntPreference.this.onClick(dialog,DialogInterface.BUTTON_POSITIVE);
        }
        else {
            Toast t = Toast.makeText(getContext(), "Enter a number!", Toast.LENGTH_SHORT);
            t.show();
        }

    }
  }

  AlertDialog d = (AlertDialog) getDialog();
  Button b = d.getButton(DialogInterface.BUTTON_POSITIVE);
  b.setOnClickListener(new mocl((d)));
}

真有趣！