既然上面的答案对我不起作用，下面是对我有效的解决方案:

对于>19和<=19 API级别。

这个方法涵盖了从uri中获取filePath的所有情况

/**
 * Get a file path from a Uri. This will get the the path for Storage Access
 * Framework Documents, as well as the _data field for the MediaStore and
 * other file-based ContentProviders.
 *
 * @param context The activity.
 * @param uri The Uri to query.
 * @author paulburke
 */
public static String getPath(final Context context, final Uri uri) {

    // DocumentProvider
    if ( Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT && DocumentsContract.isDocumentUri(context, uri)) {
        // ExternalStorageProvider
        if (isExternalStorageDocument(uri)) {
            final String docId = DocumentsContract.getDocumentId(uri);
            final String[] split = docId.split(":");
            final String type = split[0];

            if ("primary".equalsIgnoreCase(type)) {
                return Environment.getExternalStorageDirectory() + "/" + split[1];
            }else{
                Toast.makeText(context, "Could not get file path. Please try again", Toast.LENGTH_SHORT).show();
            }
        }
        // DownloadsProvider
        else if (isDownloadsDocument(uri)) {

            final String id = DocumentsContract.getDocumentId(uri);
            final Uri contentUri = ContentUris.withAppendedId(
                    Uri.parse("content://downloads/public_downloads"), Long.valueOf(id));

            return getDataColumn(context, contentUri, null, null);
        }
        // MediaProvider
        else if (isMediaDocument(uri)) {
            final String docId = DocumentsContract.getDocumentId(uri);
            final String[] split = docId.split(":");
            final String type = split[0];

            Uri contentUri = null;
            if ("image".equals(type)) {
                contentUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
            } else if ("video".equals(type)) {
                contentUri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
            } else if ("audio".equals(type)) {
                contentUri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
            } else {
                contentUri = MediaStore.Files.getContentUri("external");
            }

            final String selection = "_id=?";
            final String[] selectionArgs = new String[] {
                    split[1]
            };

            return getDataColumn(context, contentUri, selection, selectionArgs);
        }
    }
    // MediaStore (and general)
    else if ("content".equalsIgnoreCase(uri.getScheme())) {
        return getDataColumn(context, uri, null, null);
    }
    // File
    else if ("file".equalsIgnoreCase(uri.getScheme())) {
        return uri.getPath();
    }

    return null;
}

只是对第一个答案进行了简单的更新:mActivity.managedQuery()现在已弃用。我已经用新方法更新了代码。

private String getRealPathFromURI(Uri contentUri) {
    String[] proj = { MediaStore.Images.Media.DATA };
    CursorLoader loader = new CursorLoader(mContext, contentUri, proj, null, null, null);
    Cursor cursor = loader.loadInBackground();
    int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
    cursor.moveToFirst();
    String result = cursor.getString(column_index);
    cursor.close();
    return result;
}

Android开发源码

这是我的例子获取文件名，从URI file://…内容://... .这是为我工作，不仅与Android MediaStore，而且与第三方应用程序，如EzExplorer。

public static String getFileNameByUri(Context context, Uri uri)
{
    String fileName="unknown";//default fileName
    Uri filePathUri = uri;
    if (uri.getScheme().toString().compareTo("content")==0)
    {      
        Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
        if (cursor.moveToFirst())
        {
            int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
            filePathUri = Uri.parse(cursor.getString(column_index));
            fileName = filePathUri.getLastPathSegment().toString();
        }
    }
    else if (uri.getScheme().compareTo("file")==0)
    {
        fileName = filePathUri.getLastPathSegment().toString();
    }
    else
    {
        fileName = fileName+"_"+filePathUri.getLastPathSegment();
    }
    return fileName;
}

尝试从Uri获取图像文件路径

public void getImageFilePath(Context context, Uri uri) {

    Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
    cursor.moveToFirst();
    String image_id = cursor.getString(0);
    image_id = image_id.substring(image_id.lastIndexOf(":") + 1);
    cursor.close();
    cursor = context.getContentResolver().query(android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI, null, MediaStore.Images.Media._ID + " = ? ", new String[]{image_id}, null);
    cursor.moveToFirst();
    String path = cursor.getString(cursor.getColumnIndex(MediaStore.Images.Media.DATA));
    cursor.close();
    upLoadImageOrLogo(path);
}

简单易行。您可以像下面这样从URI执行此操作!

public void getContents(Uri uri)
{
    Cursor vidCursor = getActivity.getContentResolver().query(uri, null, null,
                                                              null, null);
    if (vidCursor.moveToFirst())
    {
        int column_index =
        vidCursor .getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        Uri filePathUri = Uri.parse(vidCursor .getString(column_index));
        String video_name =  filePathUri.getLastPathSegment().toString();
        String file_path=filePathUri.getPath();
        Log.i("TAG", video_name + "\b" file_path);
    }
}

完美地为我修复了这篇文章的代码:

  public static String getRealPathImageFromUri(Uri uri) {
        String fileName =null;
        if (uri.getScheme().equals("content")) {
            try (Cursor cursor = MyApplication.getInstance().getContentResolver().query(uri, null, null, null, null)) {
                if (cursor.moveToFirst()) {
                    fileName = cursor.getString(cursor.getColumnIndexOrThrow(ediaStore.Images.Media.DATA));
                }
            } catch (IllegalArgumentException e) {
                Log.e(mTag, "Get path failed", e);
            }
        }
        return fileName;
    }