试试吧

RemoveItems.forEach((i, j) => {
    OriginalItems.splice((i - j), 1);
});

下面是另一个正确使用拼接的例子。本例将从'array'中删除'attribute'。

for (var i = array.length; i--;) {
    if (array[i] === 'attribute') {
        array.splice(i, 1);
    }
}

重新计算每次循环的长度，而不是一开始就重新计算，例如:

for (i = 0; i < Auction.auctions.length; i++) {
      auction = Auction.auctions[i];
      Auction.auctions[i]['seconds'] --;
      if (auction.seconds < 0) { 
          Auction.auctions.splice(i, 1);
          i--; //decrement
      }
}

这样就不会超过上界。

EDIT:在if语句中增加了一个减量。

举两个例子:

一个例子

// Remove from Listing the Items Checked in Checkbox for Delete
let temp_products_images = store.state.c_products.products_images
if (temp_products_images != null) {
    for (var l = temp_products_images.length; l--;) {
        // 'mark' is the checkbox field
        if (temp_products_images[l].mark == true) {
            store.state.c_products.products_images.splice(l,1);         // THIS WORKS
            // this.$delete(store.state.c_products.products_images,l);  // THIS ALSO WORKS
        }
    }
}

两个例子

// Remove from Listing the Items Checked in Checkbox for Delete
let temp_products_images = store.state.c_products.products_images
if (temp_products_images != null) {
    let l = temp_products_images.length
    while (l--)
    {
        // 'mark' is the checkbox field
        if (temp_products_images[l].mark == true) {
            store.state.c_products.products_images.splice(l,1);         // THIS WORKS
            // this.$delete(store.state.c_products.products_images,l);  // THIS ALSO WORKS
        }
    }
}

普通的for循环对我来说更熟悉，我只需要在每次从数组中删除一个项时递减索引

//5个正确，5个错误 Var arr1 =[假，假，真，真，假，真，假，真，真，假]; //从数组中删除false For (var I = 0;I < arr1.length;我+ +){ If (arr1[i] === false){ arr1。拼接(我,1); I——;//如果item被移除，则递减索引 ｝ ｝ Console.log (arr1);//应该是5个true

如果你正在使用ES6+ -为什么不直接使用数组。过滤方法?

Auction.auctions = Auction.auctions.filter((auction) => {
  auction['seconds'] --;
  return (auction.seconds > 0)
})  

注意，在过滤器迭代过程中修改数组元素只对对象有效，而对基元值数组无效。