子查询可以从Outer查询访问列，因此可以使用这种方法跨列使用MAX等聚合。(不过，当涉及到大量列时可能更有用)

;WITH [Order] AS
(
SELECT 1 AS OrderId, 100 AS NegotiatedPrice, 110 AS SuggestedPrice UNION ALL
SELECT 2 AS OrderId, 1000 AS NegotiatedPrice, 50 AS SuggestedPrice
)
SELECT
       o.OrderId, 
       (SELECT MAX(price)FROM 
           (SELECT o.NegotiatedPrice AS price 
            UNION ALL SELECT o.SuggestedPrice) d) 
        AS MaxPrice 
FROM  [Order]  o

SELECT o.OrderID
CASE WHEN o.NegotiatedPrice > o.SuggestedPrice THEN
 o.NegotiatedPrice
ELSE
 o.SuggestedPrice
END AS Price

对于SQL Server 2012:

SELECT 
    o.OrderId, 
    IIF( o.NegotiatedPrice >= o.SuggestedPrice,
         o.NegotiatedPrice, 
         ISNULL(o.SuggestedPrice, o.NegiatedPrice) 
    )
FROM 
    Order o

我可能不会这样做，因为它比前面提到的CASE结构效率更低——除非您为两个查询都有覆盖索引。不管怎样，对于类似的问题，这都是一个有用的技巧:

SELECT OrderId, MAX(Price) as Price FROM (
   SELECT o.OrderId, o.NegotiatedPrice as Price FROM Order o
   UNION ALL
   SELECT o.OrderId, o.SuggestedPrice as Price FROM Order o
) as A
GROUP BY OrderId

在SQL Server 2012或更高版本中，您可以使用IIF和ISNULL(或COALESCE)的组合来获得最多2个值。 即使其中一个是NULL。

IIF(col1 >= col2, col1, ISNULL(col2, col1)) 

或者当两者都为NULL时，希望它返回0

IIF(col1 >= col2, col1, COALESCE(col2, col1, 0)) 

示例代码片段:

-- use table variable for testing purposes
declare @Order table 
(
  OrderId int primary key identity(1,1),
  NegotiatedPrice decimal(10,2),
  SuggestedPrice decimal(10,2)
);

-- Sample data
insert into @Order (NegotiatedPrice, SuggestedPrice) values
(0, 1),
(2, 1),
(3, null),
(null, 4);

-- Query
SELECT 
     o.OrderId, o.NegotiatedPrice, o.SuggestedPrice, 
     IIF(o.NegotiatedPrice >= o.SuggestedPrice, o.NegotiatedPrice, ISNULL(o.SuggestedPrice, o.NegotiatedPrice)) AS MaxPrice
FROM @Order o

结果:

OrderId NegotiatedPrice SuggestedPrice  MaxPrice
1       0,00            1,00            1,00
2       2,00            1,00            2,00
3       3,00            NULL            3,00
4       NULL            4,00            4,00

但如果需要多列中的最大值呢? 然后我建议在值的聚合上使用CROSS APPLY。

例子:

SELECT t.*
, ca.[Maximum]
, ca.[Minimum], ca.[Total], ca.[Average]
FROM SomeTable t
CROSS APPLY (
   SELECT 
    MAX(v.col) AS [Maximum], 
    MIN(v.col) AS [Minimum], 
    SUM(v.col) AS [Total], 
    AVG(v.col) AS [Average]
   FROM (VALUES (t.Col1), (t.Col2), (t.Col3), (t.Col4)) v(col)
) ca

这有一个额外的好处，它可以同时计算其他的东西。

我会使用kcrumley提供的解决方案 只需稍微修改它以处理null

create function dbo.HigherArgumentOrNull(@val1 int, @val2 int)
returns int
as
begin
  if @val1 >= @val2
    return @val1
  if @val1 < @val2
    return @val2

 return NULL
end

编辑 在Mark的评论后修改。正如他在3值逻辑x > NULL或x < NULL应该总是返回NULL。换句话说，未知的结果。