目前的文档只讨论了获取路由参数,而不是实际的路由段。
例如,如果我想找到当前路由的父,这是怎么可能的?
目前的文档只讨论了获取路由参数,而不是实际的路由段。
例如,如果我想找到当前路由的父,这是怎么可能的?
当前回答
使用这个
import { Router, NavigationEnd } from '@angular/router';
constructor(private router: Router) {
router.events.filter(event => event instanceof NavigationEnd)
.subscribe(event => {
console.log(event);
});
}
主要是。ts进口
import 'rxjs/add/operator/filter';
EDIT
现代的方式
import {filter} from 'rxjs/operators';
router.events.pipe(
filter(event => event instanceof NavigationEnd)
)
.subscribe(event => {
console.log(event);
});
其他回答
import { Router, NavigationEnd } from "@angular/router";
constructor(private router: Router) {
// Detect current route
router.events.subscribe(val => {
if (val instanceof NavigationEnd) {
console.log(val.url);
}
});
}
给那些还在寻找这个的人。在Angular 2上。有几种方法。
constructor(private router: Router, private activatedRoute: ActivatedRoute){
// string path from root to current route. i.e /Root/CurrentRoute
router.url
// just the fragment of the current route. i.e. CurrentRoute
activatedRoute.url.value[0].path
// same as above with urlSegment[]
activatedRoute.url.subscribe((url: urlSegment[])=> console.log(url[0].path))
// same as above
activatedRoute.snapshot.url[0].path
// the url fragment from the parent route i.e. Root
// since the parent is an ActivatedRoute object, you can get the same using
activatedRoute.parent.url.value[0].path
}
引用:
https://angular.io/docs/ts/latest/api/router/index/ActivatedRoute-interface.html https://angular.io/docs/ts/latest/api/router/index/Router-class.html https://angular.io/docs/ts/latest/guide/router.html
在Angular2 Rc1中,你可以注入一个routessegment,然后将它传递给.navigate()方法:
constructor(private router:Router,private segment:RouteSegment) {}
ngOnInit() {
this.router.navigate(["explore"],this.segment)
}
Angular 2 rc2
router.urlTree.contains(router.createUrlTree(['/home']))
对我来说,在AuthGuardService实现CanActivate访问当前路由时,接受的答案不工作,因为路由还没有完全处理。我在这里回答了同样的问题(https://stackoverflow.com/a/68541653/1479486),但如果你只是想从这里复制粘贴,这是我的解决方案:
const finalUrl = this.router.getCurrentNavigation()?.finalUrl;
const isLoginPage = finalUrl?.root.children['primary'].segments[0]?.path === 'login';