目前的文档只讨论了获取路由参数,而不是实际的路由段。

例如,如果我想找到当前路由的父,这是怎么可能的?


当前回答

如果你不能访问路由器,这是一个更简单的方法。url(例如,如果你使用skipLocationChange),你可以使用以下:

import { Location } from '@angular/common';    
constructor(private readonly location: Location) {}
    
ngOnInit(): void {
  console.log(this.location.path());
}

其他回答

给那些还在寻找这个的人。在Angular 2上。有几种方法。

constructor(private router: Router, private activatedRoute: ActivatedRoute){

   // string path from root to current route. i.e /Root/CurrentRoute
   router.url 

    // just the fragment of the current route. i.e. CurrentRoute
   activatedRoute.url.value[0].path

    // same as above with urlSegment[]
   activatedRoute.url.subscribe((url: urlSegment[])=> console.log(url[0].path))

   // same as above
   activatedRoute.snapshot.url[0].path

   // the url fragment from the parent route i.e. Root
   // since the parent is an ActivatedRoute object, you can get the same using 
   activatedRoute.parent.url.value[0].path
}

引用:

https://angular.io/docs/ts/latest/api/router/index/ActivatedRoute-interface.html https://angular.io/docs/ts/latest/api/router/index/Router-class.html https://angular.io/docs/ts/latest/guide/router.html

方法1:使用Angular: this.router.url

import { Component } from '@angular/core';

// Step 1: import the router 
import { Router } from '@angular/router';

@Component({
    template: 'The href is: {{href}}'
    /*
    Other component settings
    */
})
export class Component {
    public href: string = "";

    //Step 2: Declare the same in the constructure.
    constructor(private router: Router) {}

    ngOnInit() {
        this.href = this.router.url;
        // Do comparision here.....
        ///////////////////////////
        console.log(this.router.url);
    }
}

方法二:窗口。如果你不想使用路由器,就像我们在Javascript中做的那样

this.href= window.location.href;

新的V3路由器有一个url属性。

this.router.url === '/login'

在组件文件中:

import {ActivatedRouteSnapshot} from '@angular/router';

constructor(state: ActivatedRouteSnapshot) {
    console.log(state.path)
}

在路由文件中:

Angular 2 rc2

router.urlTree.contains(router.createUrlTree(['/home']))