这并没有直接回答您的问题，但这里有一个通用函数，它将创建一个包含查询字符串参数的URL。参数(名称和值)被安全转义以包含在URL中。

function buildUrl(url, parameters){
  var qs = "";
  for(var key in parameters) {
    var value = parameters[key];
    qs += encodeURIComponent(key) + "=" + encodeURIComponent(value) + "&";
  }
  if (qs.length > 0){
    qs = qs.substring(0, qs.length-1); //chop off last "&"
    url = url + "?" + qs;
  }
  return url;
}

// example:
var url = "http://example.com/";

var parameters = {
  name: "George Washington",
  dob: "17320222"
};

console.log(buildUrl(url, parameters));
// => http://www.example.com/?name=George%20Washington&dob=17320222

不，我认为标准JavaScript没有内置这个功能，但Prototype JS有这个功能(当然大多数其他JS框架也有，但我不知道它们)，他们称之为序列化。

I can reccomend Prototype JS, it works quite okay. The only drawback I've really noticed it it's size (a few hundred kb) and scope (lots of code for ajax, dom, etc.). Thus if you only want a form serializer it's overkill, and strictly speaking if you only want it's Ajax functionality (wich is mainly what I used it for) it's overkill. Unless you're careful you may find that it does a little too much "magic" (like extending every dom element it touches with Prototype JS functions just to find elements) making it slow on extreme cases.

URLSearchParams API在所有现代浏览器中都可用。例如:

const params = new URLSearchParams({ var1:“价值”, var2:“value2”, 加勒比海盗:“foo”, })； console.log (params.toString ()); / /打印“var1 = value&var2 = value2&arr = foo”

这些答案是非常有用的，但我想添加另一个答案，这可能会帮助你建立完整的URL。 这可以帮助你连接基本url，路径，哈希和参数。

var url = buildUrl('http://mywebsite.com', {
        path: 'about',
        hash: 'contact',
        queryParams: {
            'var1': 'value',
            'var2': 'value2',
            'arr[]' : 'foo'
        }
    });
    console.log(url);

你可以通过npm https://www.npmjs.com/package/build-url下载

演示:

;(function () { 'use strict'; var root = this; var previousBuildUrl = root.buildUrl; var buildUrl = function (url, options) { var queryString = []; var key; var builtUrl; var caseChange; // 'lowerCase' parameter default = false, if (options && options.lowerCase) { caseChange = !!options.lowerCase; } else { caseChange = false; } if (url === null) { builtUrl = ''; } else if (typeof(url) === 'object') { builtUrl = ''; options = url; } else { builtUrl = url; } if(builtUrl && builtUrl[builtUrl.length - 1] === '/') { builtUrl = builtUrl.slice(0, -1); } if (options) { if (options.path) { var localVar = String(options.path).trim(); if (caseChange) { localVar = localVar.toLowerCase(); } if (localVar.indexOf('/') === 0) { builtUrl += localVar; } else { builtUrl += '/' + localVar; } } if (options.queryParams) { for (key in options.queryParams) { if (options.queryParams.hasOwnProperty(key) && options.queryParams[key] !== void 0) { var encodedParam; if (options.disableCSV && Array.isArray(options.queryParams[key]) && options.queryParams[key].length) { for(var i = 0; i < options.queryParams[key].length; i++) { encodedParam = encodeURIComponent(String(options.queryParams[key][i]).trim()); queryString.push(key + '=' + encodedParam); } } else { if (caseChange) { encodedParam = encodeURIComponent(String(options.queryParams[key]).trim().toLowerCase()); } else { encodedParam = encodeURIComponent(String(options.queryParams[key]).trim()); } queryString.push(key + '=' + encodedParam); } } } builtUrl += '?' + queryString.join('&'); } if (options.hash) { if(caseChange) builtUrl += '#' + String(options.hash).trim().toLowerCase(); else builtUrl += '#' + String(options.hash).trim(); } } return builtUrl; }; buildUrl.noConflict = function () { root.buildUrl = previousBuildUrl; return buildUrl; }; if (typeof(exports) !== 'undefined') { if (typeof(module) !== 'undefined' && module.exports) { exports = module.exports = buildUrl; } exports.buildUrl = buildUrl; } else { root.buildUrl = buildUrl; } }).call(this); var url = buildUrl('http://mywebsite.com', { path: 'about', hash: 'contact', queryParams: { 'var1': 'value', 'var2': 'value2', 'arr[]' : 'foo' } }); console.log(url);

可能有点多余，但我找到的最干净的方法是建立在这里的一些答案上:

const params: {
   key1: 'value1',
   key2: 'value2',
   key3: 'value3',
}

const esc = encodeURIComponent;
const query = Object.keys(params)
  .map(k => esc(k) + '=' + esc(params[k]))
  .join('&');

return fetch('my-url', {
  method: 'POST',
  headers: {'Content-Type': 'application/x-www-form-urlencoded'},
  body: query,
})

源

正如Stein所说，您可以使用http://www.prototypejs.org中的原型javascript库。 包括JS，这很简单，$('formName').serialize()将返回你想要的!