我不知道这样做的函数,有人知道吗?


当前回答

我认为你应该首先定义你所有的路线,然后作为最后的路线添加

//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
  res.status(404).send('what???');
});

一个示例应用程序的工作:

app.js:

var express = require('express'),
    app = express.createServer();

app.use(express.static(__dirname + '/public'));

app.get('/', function(req, res){
  res.send('hello world');
});

//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
  res.send('what???', 404);
});

app.listen(3000, '127.0.0.1');

alfred@alfred-laptop:~/node/stackoverflow/6528876$ mkdir public
alfred@alfred-laptop:~/node/stackoverflow/6528876$ find .
alfred@alfred-laptop:~/node/stackoverflow/6528876$ echo "I don't find a function for that... Anyone knows?" > public/README.txt
alfred@alfred-laptop:~/node/stackoverflow/6528876$ cat public/README.txt 

.
./app.js
./public
./public/README.txt

alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/
hello world
alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/README.txt
I don't find a function for that... Anyone knows?

其他回答

覆盖express中的所有HTTP动词

为了覆盖所有HTTP动词和所有剩余路径,您可以使用:

app.all('*', cb)

最终的解决方案是这样的:

app.all('*', (req, res) =>{
    res.status(404).json({
        success: false,
        data: '404'
    })
})

你不应该忘记把路由器放在最后。 因为路由器的顺序很重要。

我发现这个例子很有帮助:

https://github.com/visionmedia/express/blob/master/examples/error-pages/index.js

所以,它实际上是这一部分:

// "app.router" positions our routes
// above the middleware defined below,
// this means that Express will attempt
// to match & call routes _before_ continuing
// on, at which point we assume it's a 404 because
// no route has handled the request.

app.use(app.router);

// Since this is the last non-error-handling
// middleware use()d, we assume 404, as nothing else
// responded.

// $ curl http://localhost:3000/notfound
// $ curl http://localhost:3000/notfound -H "Accept: application/json"
// $ curl http://localhost:3000/notfound -H "Accept: text/plain"

app.use(function(req, res, next) {
  res.status(404);

  // respond with html page
  if (req.accepts('html')) {
    res.render('404', { url: req.url });
    return;
  }

  // respond with json
  if (req.accepts('json')) {
    res.json({ error: 'Not found' });
    return;
  }

  // default to plain-text. send()
  res.type('txt').send('Not found');
});

在Express中,404响应不是错误的结果,因此错误处理程序中间件不会捕获它们。你所需要做的就是在堆栈的最底部(所有其他函数的下面)添加一个中间件函数来处理404响应:

app.use(function (req, res, next) {
// YOU CAN CREATE A CUSTOM EJS FILE TO SHOW CUSTOM ERROR MESSAGE
  res.status(404).render("404.ejs")
})

这种方法更简单,但它必须是所有路线之后的最后一件事。

app.use( (req, res) => {
    //render page not found 
    res.render('404')
})

首先,创建一个route js文件。接下来,创建一个错误。Ejs文件(如果您正在使用Ejs)。最后,在路由文件中添加以下代码

router.get('*', function(req, res){
    res.render('error');
});