最简单的答案并不总是在底部，但这一次是，并且可以在上面的评论中看到。 使用您自己的“AT TIME ZONE”来捕获列/数据字段的TzOffset，而不是当前的SYSDATETIME。 在下面的数据中，2个查询，一个关于feb数据(DST是关闭的，在阿姆斯特丹的冬天)+1差异 第二次查询阿姆斯特丹4月份的数据，所以+2小时的差异。

    select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring
   ,  receiveTimeUTC
   ,  CONVERT(datetime,  SWITCHOFFSET(CONVERT(datetimeoffset,  receiveTimeUTC),  DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
   ,  CONVERT(datetime,  SWITCHOFFSET(CONVERT(datetimeoffset,  receiveTimeUTC),  DATENAME(TzOffset, receiveTimeUTC  AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
       from sensordetails order by id

    select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring, receiveTimeUTC
,  CONVERT(datetime,  SWITCHOFFSET(CONVERT(datetimeoffset,  receiveTimeUTC),  DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
,  CONVERT(datetime,  SWITCHOFFSET(CONVERT(datetimeoffset,  receiveTimeUTC),  DATENAME(TzOffset, receiveTimeUTC  AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
       from sensordetails order by id desc

结果:

所以这是一个T-SQL (SQL Server Answer)，不需要函数的storedproc。

这很简单。试试这个Azure SQL Server:

SELECT YourDateTimeColumn AT TIME ZONE 'Eastern Standard Time' FROM YourTable

对于本地SQL Server:

SELECT CONVERT(datetime2, SWITCHOFFSET(CONVERT(datetimeoffset, gETDATE()), DATENAME(TzOffset, gETDATE() AT TIME ZONE 'Eastern Standard Time'))) FROM YourTable

这可以在没有函数的情况下完成。下面的代码将把UTC时间转换为考虑夏令时的山地时间。相应地调整所有的-6和-7数字到您的时区(即对于EST，您将分别调整为-4和-5)

--Adjust a UTC value, in the example the UTC field is identified as UTC.Field, to account for daylight savings time when converting out of UTC to Mountain time.
CASE
    --When it's between March and November, it is summer time which is -6 from UTC
    WHEN MONTH ( UTC.Field ) > 3 AND MONTH ( UTC.Field ) < 11 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    --When its March and the day is greater than the 14, you know it's summer (-6)
    WHEN MONTH ( UTC.Field ) = 3
        AND DATEPART ( DAY , UTC.Field ) >= 14 
        THEN
            --However, if UTC is before 9am on that Sunday, then it's before 2am Mountain which means it's still Winter daylight time.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 2am mountain time so it's winter, -7 hours for Winter daylight time
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise -6 because it'll be after 2am making it Summer daylight time
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    WHEN MONTH ( UTC.Field ) = 3
        AND ( DATEPART ( WEEKDAY , UTC.Field ) + 7 ) <= DATEPART ( day , UTC.Field ) 
        THEN 
            --According to the date, it's moved onto Summer daylight, but we need to account for the hours leading up to 2am if it's Sunday
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 9am UTC is before 2am Mountain so it's winter Daylight, -7 hours
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise, it's summer daylight, -6 hours
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    --When it's November and the weekday is greater than the calendar date, it's still Summer so -6 from the time
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) > DATEPART ( DAY , UTC.Field ) 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) <= DATEPART ( DAY , UTC.Field ) 
            --If the weekday is less than or equal to the calendar day it's Winter daylight but we need to account for the hours leading up to 2am.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '8:00'
                    --If it's before 8am UTC and it's Sunday in the logic outlined, then it's still Summer daylight, -6 hours
                    THEN DATEADD ( HOUR , -6 , UTC.Field )
                --Otherwise, adjust for Winter daylight at -7
                ELSE DATEADD ( HOUR , -7 , UTC.Field )
            END
    --If the date doesn't fall into any of the above logic, it's Winter daylight, -7
    ELSE
        DATEADD ( HOUR , -7 , UTC.Field )
END

罗恩的回答有一个错误。它使用当地时间凌晨2:00，其中需要UTC等效值。我没有足够的声望分数来评论Ron的回答，所以更正版本如下:

-- =============================================
-- Author:      Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
--              based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
    @UTC datetime,
    @StandardOffset int
)
RETURNS datetime
AS
BEGIN

declare 
    @DST datetime,
    @SSM datetime, -- Second Sunday in March
    @FSN datetime  -- First Sunday in November
-- get DST Range
set @SSM = datename(year,@UTC) + '0314' 
set @SSM = dateadd(hour,2 - @StandardOffset,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
set @FSN = datename(year,@UTC) + '1107'
set @FSN = dateadd(second,-1,dateadd(hour,2 - (@StandardOffset + 1),dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))

-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
    set @StandardOffset = @StandardOffset + 1

-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)

-- return converted datetime
return @DST

END

对于任何仍然试图解决这个问题的人，这里有一个在SQL Server 2017中工作的概念证明

 declare
    @StartDate date = '2020-01-01'

;with cte_utc as
(
    select 
         1 as i
        ,CONVERT(datetime, @StartDate) AS UTC
        ,datepart(weekday, CONVERT(datetime, @StartDate)) as Weekday
        ,datepart(month, CONVERT(datetime, @StartDate)) as [Month]
        ,datepart(YEAR, CONVERT(datetime, @StartDate)) as [Year]
        
    union all

    Select
         i + 1
        ,dateadd(d, 1, utc)
        ,datepart(weekday, CONVERT(datetime, dateadd(d, 1, utc))) as Weekday
        ,datepart(month, CONVERT(datetime, dateadd(d, 1, utc))) as [Month]
        ,datepart(YEAR, CONVERT(datetime, dateadd(d, 1, utc))) as [Year]
    from    
        cte_utc
    where
        (i + 1) < 32767

), cte_utc_dates as 
(
    select 
        *,
        DENSE_RANK()OVER(PARTITION BY [Year], [Month], [Weekday] ORDER BY Utc) WeekDayIndex
    from
        cte_utc

), cte_hours as (
    select 0 as [Hour]
    union all
    select [Hour] + 1 from cte_hours where [Hour] < 23
)

select
    d.*
    , DATEADD(hour, h.Hour, d.UTC) AS UtcTime
    ,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Central Standard Time') CST
    ,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time') EST
from
    cte_utc_dates d, cte_hours h
where
    ([Month] = 3 and [Weekday] = 1 and WeekDayIndex = 2 )-- dst start
    or 
    ([Month] = 11 and [Weekday] = 1 and WeekDayIndex = 1 )-- dst end
order by
    utc
OPTION (MAXRECURSION 32767)

GO

对于Azure SQL和@@Version >= SQL Server 2016用户，下面是一个使用AT TIME ZONE的简单函数。

CREATE FUNCTION [dbo].[Global_Convert_UTCTimeTo_LocalTime]
(
   @LocalTimeZone        VARCHAR(50),
   @UTCDateTime          DATETIME
)
RETURNS DATETIME
AS
BEGIN
   DECLARE @ConvertedDateTime DATETIME;

   SELECT @ConvertedDateTime = @UTCDateTime AT TIME ZONE 'UTC' AT TIME ZONE @LocalTimeZone
   RETURN @ConvertedDateTime

END
GO

对于@LocalTimeZone可以采用的值类型，请转到此链接或转到KEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Time Zones