我正在做一些SQL选择查询，并希望将我的UTC日期时间列转换为本地时间，以便在我的查询结果中显示为本地时间。注意，我不希望通过代码进行这种转换，而是当我对我的数据库进行手动和随机SQL查询时。
当前回答
对于任何仍然试图解决这个问题的人，这里有一个在SQL Server 2017中工作的概念证明
declare
@StartDate date = '2020-01-01'
;with cte_utc as
(
select
1 as i
,CONVERT(datetime, @StartDate) AS UTC
,datepart(weekday, CONVERT(datetime, @StartDate)) as Weekday
,datepart(month, CONVERT(datetime, @StartDate)) as [Month]
,datepart(YEAR, CONVERT(datetime, @StartDate)) as [Year]
union all
Select
i + 1
,dateadd(d, 1, utc)
,datepart(weekday, CONVERT(datetime, dateadd(d, 1, utc))) as Weekday
,datepart(month, CONVERT(datetime, dateadd(d, 1, utc))) as [Month]
,datepart(YEAR, CONVERT(datetime, dateadd(d, 1, utc))) as [Year]
from
cte_utc
where
(i + 1) < 32767
), cte_utc_dates as
(
select
*,
DENSE_RANK()OVER(PARTITION BY [Year], [Month], [Weekday] ORDER BY Utc) WeekDayIndex
from
cte_utc
), cte_hours as (
select 0 as [Hour]
union all
select [Hour] + 1 from cte_hours where [Hour] < 23
)
select
d.*
, DATEADD(hour, h.Hour, d.UTC) AS UtcTime
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Central Standard Time') CST
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time') EST
from
cte_utc_dates d, cte_hours h
where
([Month] = 3 and [Weekday] = 1 and WeekDayIndex = 2 )-- dst start
or
([Month] = 11 and [Weekday] = 1 and WeekDayIndex = 1 )-- dst end
order by
utc
OPTION (MAXRECURSION 32767)
GO
其他回答
我使用switchoffset将utc时间转换为本地时间。时区偏移可以通过使用datename(tzoffset,systemdatetimeoffset())来确定。同样地，如果您想获得经过的时间，则使用getutcdate将时间保持为datediff函数的utc时间。
select
,[Field1]
,Format(SWITCHOFFSET([MyDateOnUTC],DATENAME(TZOFFSET, SYSDATETIMEOFFSET())),'MM/dd/yyyy hh:mm:ss tt') UtcToLocalTime
,datediff(minute,[ClaimedOnUTC],getutcdate()) ElapsedMinutes
from dbo.my_table
我没有发现任何这些示例有助于将日期时间存储为UTC到指定时区(不是服务器的时区，因为Azure SQL数据库以UTC运行)中的日期时间。我是这样处理的。它并不优雅，但它很简单，无需维护其他表就能给出正确答案:
select CONVERT(datetime, SWITCHOFFSET(dateTimeField, DATEPART(TZOFFSET,
dateTimeField AT TIME ZONE 'Eastern Standard Time')))
如果你需要一个转换而不是你的服务器位置，这里有一个函数，允许你传递一个标准偏移量，并考虑美国夏令时:
-- =============================================
-- Author: Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
-- based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
@UTC datetime,
@StandardOffset int
)
RETURNS datetime
AS
BEGIN
declare
@DST datetime,
@SSM datetime, -- Second Sunday in March
@FSN datetime -- First Sunday in November
-- get DST Range
set @SSM = datename(year,@UTC) + '0314'
set @SSM = dateadd(hour,2,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
set @FSN = datename(year,@UTC) + '1107'
set @FSN = dateadd(second,-1,dateadd(hour,2,dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))
-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
set @StandardOffset = @StandardOffset + 1
-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)
-- return converted datetime
return @DST
END
GO
作为一个警告-如果你要使用以下(注意毫秒而不是分钟):
SELECT DATEADD(ms, DATEDIFF(ms, GETUTCDATE(), GETDATE()), MyTable.UtcColumn)
AS ColumnInLocalTime
FROM MyTable
请记住，DATEDIFF部分并不总是返回相同的数字。所以不要用它来将DateTimes精确到毫秒。
使用新的SQL Server 2016机会:
CREATE FUNCTION ToLocalTime(@dtUtc datetime, @timezoneId nvarchar(256))
RETURNS datetime
AS BEGIN
return @dtUtc AT TIME ZONE 'UTC' AT TIME ZONE @timezoneId
/* -- second way, faster
return SWITCHOFFSET(@dtUtc , DATENAME(tz, @dtUtc AT TIME ZONE @timezoneId))
*/
/* -- third way
declare @dtLocal datetimeoffset
set @dtLocal = @dtUtc AT TIME ZONE @timezoneId
return dateadd(minute, DATEPART (TZoffset, @dtLocal), @dtUtc)
*/
END
GO
但clr程序的工作速度快5倍:'-(
请注意，一个时区的偏移量可以更改为冬季时间或夏季时间。例如
select cast('2017-02-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
select cast('2017-08-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
结果:
2017-02-08 09:00:00.000 -05:00
2017-08-08 09:00:00.000 -04:00
你不能只是添加常数偏移量。
