这是一个Objective-C类别，它支持现有UILabel中的可点击链接。attributedText字符串，利用现有的NSLinkAttributeName属性。

@interface UILabel (GSBClickableLinks) <UIGestureRecognizerDelegate>
@property BOOL enableLinks;
@end

#import <objc/runtime.h>
static const void *INDEX;
static const void *TAP;

@implementation UILabel (GSBClickableLinks)

- (void)setEnableLinks:(BOOL)enableLinks
{
    UITapGestureRecognizer *tap = objc_getAssociatedObject(self, &TAP); // retreive tap
    if (enableLinks && !tap) { // add a gestureRegonzier to the UILabel to detect taps
        tap = [UITapGestureRecognizer.alloc initWithTarget:self action:@selector(openLink)];
        tap.delegate = self;
        [self addGestureRecognizer:tap];
        objc_setAssociatedObject(self, &TAP, tap, OBJC_ASSOCIATION_RETAIN_NONATOMIC); // save tap
    }
    self.userInteractionEnabled = enableLinks; // note - when false UILAbel wont receive taps, hence disable links
}

- (BOOL)enableLinks
{
    return (BOOL)objc_getAssociatedObject(self, &TAP); // ie tap != nil
}

// First check whether user tapped on a link within the attributedText of the label.
// If so, then the our label's gestureRecogizer will subsequently fire, and open the corresponding NSLinkAttributeName.
// If not, then the tap will get passed along, eg to the enclosing UITableViewCell...
// Note: save which character in the attributedText was clicked so that we dont have to redo everything again in openLink.
- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
    if (gestureRecognizer != objc_getAssociatedObject(self, &TAP)) return YES; // dont block other gestures (eg swipe)

    // Re-layout the attributedText to find out what was tapped
    NSTextContainer *textContainer = [NSTextContainer.alloc initWithSize:self.frame.size];
    textContainer.lineFragmentPadding = 0;
    textContainer.maximumNumberOfLines = self.numberOfLines;
    textContainer.lineBreakMode = self.lineBreakMode;
    NSLayoutManager *layoutManager = NSLayoutManager.new;
    [layoutManager addTextContainer:textContainer];
    NSTextStorage *textStorage = [NSTextStorage.alloc initWithAttributedString:self.attributedText];
    [textStorage addLayoutManager:layoutManager];

    NSUInteger index = [layoutManager characterIndexForPoint:[gestureRecognizer locationInView:self]
                                             inTextContainer:textContainer
                    fractionOfDistanceBetweenInsertionPoints:NULL];
    objc_setAssociatedObject(self, &INDEX, @(index), OBJC_ASSOCIATION_RETAIN_NONATOMIC); // save index

    return (BOOL)[self.attributedText attribute:NSLinkAttributeName atIndex:index effectiveRange:NULL]; // tapped on part of a link?
}

- (void)openLink
{
    NSUInteger index = [objc_getAssociatedObject(self, &INDEX) unsignedIntegerValue]; // retrieve index
    NSURL *url = [self.attributedText attribute:NSLinkAttributeName atIndex:index effectiveRange:NULL];
    if (url && [UIApplication.sharedApplication canOpenURL:url]) [UIApplication.sharedApplication openURL:url];
}

@end 

这将通过一个UILabel子类(即没有objc_getAssociatedObject的混乱)来完成，但如果你像我一样，你更喜欢避免不必要的(第三方)子类，只是为了给现有的UIKit类添加一些额外的功能。此外，这有一个漂亮的地方，它添加了任何现有的UILabel的点击链接，例如现有的UITableViewCells!

我已经试着让它尽可能的最小化侵入性通过使用现有的NSLinkAttributeName属性在NSAttributedString中已经可用。所以很简单:

NSURL *myURL = [NSURL URLWithString:@"http://www.google.com"];
NSMutableAttributedString *myString = [NSMutableAttributedString.alloc initWithString:@"This string has a clickable link: "];
[myString appendAttributedString:[NSAttributedString.alloc initWithString:@"click here" attributes:@{NSLinkAttributeName:myURL}]];
...
myLabel.attributedText = myString;
myLabel.enableLinks = YES; // yes, that's all! :-)

基本上，它通过添加一个UIGestureRecognizer到你的UILabel来工作。最难的工作是在gestureRecognizerShouldBegin:中完成的，它会重新布局attributedText字符串，以找出被点击的字符。如果这个字符是NSLinkAttributeName的一部分，那么手势识别器将随后触发，检索相应的URL(从NSLinkAttributeName值)，并打开每个通常的[UIApplication。sharedApplication openURL:url进程。

注意:通过在gestureRecognizerShouldBegin:中执行所有这些操作，如果你没有碰巧点击标签中的链接，事件就会被传递。因此，例如，你的UITableViewCell将捕获点击链接，但其他行为正常(选择单元格，取消选择，滚动，…)。

我把它放在了GitHub仓库里。 改编自Kai Burghardt的SO帖子。

我遵循这个版本，

斯威夫特4:

import Foundation

class AELinkedClickableUILabel: UILabel {

    typealias YourCompletion = () -> Void

    var linkedRange: NSRange!
    var completion: YourCompletion?

    @objc func linkClicked(sender: UITapGestureRecognizer){

        if let completionBlock = completion {

            let textView = UITextView(frame: self.frame)
            textView.text = self.text
            textView.attributedText = self.attributedText
            let index = textView.layoutManager.characterIndex(for: sender.location(in: self),
                                                              in: textView.textContainer,
                                                              fractionOfDistanceBetweenInsertionPoints: nil)

            if linkedRange.lowerBound <= index && linkedRange.upperBound >= index {

                completionBlock()
            }
        }
    }

/**
 *  This method will be used to set an attributed text specifying the linked text with a
 *  handler when the link is clicked
 */
    public func setLinkedTextWithHandler(text:String, link: String, handler: @escaping ()->()) -> Bool {

        let attributextText = NSMutableAttributedString(string: text)
        let foundRange = attributextText.mutableString.range(of: link)

        if foundRange.location != NSNotFound {
            self.linkedRange = foundRange
            self.completion = handler
            attributextText.addAttribute(NSAttributedStringKey.link, value: text, range: foundRange)
            self.isUserInteractionEnabled = true
            self.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(linkClicked(sender:))))
            return true
        }
        return false
    }
}

电话的例子:

button.setLinkedTextWithHandler(text: "This website (stackoverflow.com) is awesome", link: "stackoverflow.com") 
{
    // show popup or open to link
}

UITextView支持OS3.0中的数据检测器，而UILabel不支持。

如果你在UITextView上启用了数据检测器，并且你的文本包含url、电话号码等，它们将以链接的形式出现。

从iOS 15开始，SwiftUI内置支持Markdown标记语言，因此Markdown中的文本:

Text("You can [click this link](https://www.example.com) to visit the website.")

或者作为一个使用SwiftUI的最简单的例子，你可以这样做:

        HStack() {
            Text("Open the")
                .foregroundColor(.black)
            Link(destination: URL(string: "https://www.example.com/TOS.html")!) {
                Text("link")
                    .foregroundColor(.blue)
                    .underline()
            }
            Text("in browser")
                .foregroundColor(.black)
        }

对于完全自定义的链接，你需要使用UIWebView -你可以拦截调用，这样当链接被按下时，你可以转到应用程序的其他部分。

这里是一个Swift实现，它是尽可能少的，还包括触摸反馈。警告:

你必须在NSAttributedStrings中设置字体 你只能使用NSAttributedStrings! 你必须确保你的链接不能自动换行(使用不间断的空格:"\u{a0}") 设置文本后，不能更改lineBreakMode或numberolines 通过添加带有.link键的属性来创建链接

.

public class LinkLabel: UILabel {
    private var storage: NSTextStorage?
    private let textContainer = NSTextContainer()
    private let layoutManager = NSLayoutManager()
    private var selectedBackgroundView = UIView()

    override init(frame: CGRect) {
        super.init(frame: frame)
        textContainer.lineFragmentPadding = 0
        layoutManager.addTextContainer(textContainer)
        textContainer.layoutManager = layoutManager
        isUserInteractionEnabled = true
        selectedBackgroundView.isHidden = true
        selectedBackgroundView.backgroundColor = UIColor(white: 0, alpha: 0.3333)
        selectedBackgroundView.layer.cornerRadius = 4
        addSubview(selectedBackgroundView)
    }

    public required convenience init(coder: NSCoder) {
        self.init(frame: .zero)
    }

    public override func layoutSubviews() {
        super.layoutSubviews()
        textContainer.size = frame.size
    }

    public override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        super.touchesBegan(touches, with: event)
        setLink(for: touches)
    }

    public override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
        super.touchesMoved(touches, with: event)
        setLink(for: touches)
    }

    private func setLink(for touches: Set<UITouch>) {
        if let pt = touches.first?.location(in: self), let (characterRange, _) = link(at: pt) {
            let glyphRange = layoutManager.glyphRange(forCharacterRange: characterRange, actualCharacterRange: nil)
            selectedBackgroundView.frame = layoutManager.boundingRect(forGlyphRange: glyphRange, in: textContainer).insetBy(dx: -3, dy: -3)
            selectedBackgroundView.isHidden = false
        } else {
            selectedBackgroundView.isHidden = true
        }
    }

    public override func touchesCancelled(_ touches: Set<UITouch>, with event: UIEvent?) {
        super.touchesCancelled(touches, with: event)
        selectedBackgroundView.isHidden = true
    }

    public override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
        super.touchesEnded(touches, with: event)
        selectedBackgroundView.isHidden = true

        if let pt = touches.first?.location(in: self), let (_, url) = link(at: pt) {
            UIApplication.shared.open(url)
        }
    }

    private func link(at point: CGPoint) -> (NSRange, URL)? {
        let touchedGlyph = layoutManager.glyphIndex(for: point, in: textContainer)
        let touchedChar = layoutManager.characterIndexForGlyph(at: touchedGlyph)
        var range = NSRange()
        let attrs = attributedText!.attributes(at: touchedChar, effectiveRange: &range)
        if let urlstr = attrs[.link] as? String {
            return (range, URL(string: urlstr)!)
        } else {
            return nil
        }
    }

    public override var attributedText: NSAttributedString? {
        didSet {
            textContainer.maximumNumberOfLines = numberOfLines
            textContainer.lineBreakMode = lineBreakMode
            if let txt = attributedText {
                storage = NSTextStorage(attributedString: txt)
                storage!.addLayoutManager(layoutManager)
                layoutManager.textStorage = storage
                textContainer.size = frame.size
            }
        }
    }
}