我有以下gulpfile.js，我通过命令行gulp消息执行:
var gulp = require('gulp');
gulp.task('message', function() {
console.log("HTTP Server Started");
});
我得到以下错误消息:
[14:14:41] Using gulpfile ~\Documents\node\first\gulpfile.js
[14:14:41] Starting 'message'...
HTTP Server Started
[14:14:41] The following tasks did not complete: message
[14:14:41] Did you forget to signal async completion?
我在Windows 10系统上使用gulp 4。下面是gulp——version的输出:
[14:15:15] CLI version 0.4.0
[14:15:15] Local version 4.0.0-alpha.2
当前回答
在默认函数中添加done作为参数。这样就行了。
其他回答
在默认函数中添加done作为参数。这样就行了。
对于那些试图使用gulp进行本地部署的人，下面的代码将有所帮助
var gulp = require("gulp");
var yaml = require("js-yaml");
var path = require("path");
var fs = require("fs");
//Converts yaml to json
gulp.task("swagger", done => {
var doc = yaml.safeLoad(fs.readFileSync(path.join(__dirname,"api/swagger/swagger.yaml")));
fs.writeFileSync(
path.join(__dirname,"../yourjsonfile.json"),
JSON.stringify(doc, null, " ")
);
done();
});
//Watches for changes
gulp.task('watch', function() {
gulp.watch('api/swagger/swagger.yaml', gulp.series('swagger'));
});
基本上v3。X更简单，但是v4。X对同步和异步任务的这些方法是严格的。
async/await是理解工作流和问题的非常简单和有用的方法。
使用这个简单的方法
const gulp = require('gulp')
gulp.task('message',async function(){
return console.log('Gulp is running...')
})
解决方案很简单，但我概述了我所做的更改、我得到的错误、前后的gulpfile以及包版本——因此使它看起来很长。
除了遵循保存.scss文件时输出的错误外，我还通过遵循前面多个答案的方向解决了这个问题。
简而言之:
我改变了gulp-sass的输入方式——见(A) 我把所有函数都改成了ASYNC函数——参见(B)
(A) gulp-sass import的改动:
之前:var sass = require('gulp-sass) After: var sass = require('gulp-sass')(require('sass'));
简单地将函数转换为ASYNC -
我的gulpfile看起来像以前:
'use strict';
// dependencies
var gulp = require('gulp');
var sass = require('gulp-sass');
var minifyCSS = require('gulp-clean-css');
var uglify = require('gulp-uglify');
var rename = require('gulp-rename');
var changed = require('gulp-changed');
var SCSS_SRC = './src/Assets/scss/**/*.scss';
var SCSS_DEST = './src/Assets/css';
function compile_scss() {
return gulp.src(SCSS_SRC)
.pipe(sass().on('error', sass.logError))
.pipe(minifyCSS())
.pipe(rename({ suffix: '.min' }))
.pipe(changed(SCSS_DEST))
.pipe(gulp.dest(SCSS_DEST));
}
function watch_scss() {
gulp.watch(SCSS_SRC, compile_scss);
}
gulp.task('default', watch_scss); //Run tasks
exports.compile_scss = compile_scss;
exports.watch_scss = watch_scss;
我的gulpfile看起来像:
'use strict';
// dependencies
var gulp = require('gulp');
//var sass = require('gulp-sass');
var sass = require('gulp-sass')(require('sass'));
var minifyCSS = require('gulp-clean-css');
var uglify = require('gulp-uglify');
var rename = require('gulp-rename');
var changed = require('gulp-changed');
var SCSS_SRC = './src/Assets/scss/**/*.scss';
var SCSS_DEST = './src/Assets/css';
async function compile_scss() {
return gulp.src(SCSS_SRC)
.pipe(sass().on('error', sass.logError))
.pipe(minifyCSS())
.pipe(rename({ suffix: '.min' }))
.pipe(changed(SCSS_DEST))
.pipe(gulp.dest(SCSS_DEST));
}
async function watch_scss() {
gulp.watch(SCSS_SRC, compile_scss);
}
gulp.task('default', watch_scss); // Run tasks
exports.compile_scss = compile_scss;
exports.watch_scss = watch_scss;
包版本:
"gulp": "^4.0.2",
"gulp-changed": "^4.0.3",
"gulp-rename": "^2.0.0",
"gulp-uglify": "^3.0.2",
"gulp-clean-css": "^4.3.0",
"gulp-sass": "^5.0.0",
"sass": "^1.38.0"
我得到的错误:
Error in plugin "gulp-sass"
Message:
gulp-sass 5 does not have a default Sass compiler; please set one yourself.
Both the `sass` and `node-sass` packages are permitted.
For example, in your gulpfile:
var sass = require('gulp-sass')(require('sass'));
[14:00:37] The following tasks did not complete: default, compile_scss
[14:00:37] Did you forget to signal async completion?
所以我在Gulp 4中得到了相同的错误，但解决方案不同。我犯了一个错误: “你忘记给异步完成打信号了吗?” 但在错误之前，它还说: gulp-sass不再有默认的Sass编译器;请自己设置一个。” 一开始我完全错过了这部分。 所以我在gulfile.js中有这个:
const sass = require('gulp-sass')
这应该改为:
const sass = require('gulp-sass')(require('sass'));
现在它起作用了。
