得到:$ . GET (. .)

职位:$ . POST () . .

PUT/DELETE呢?


当前回答

这是一个更新的ajax调用,当你使用JSON与jQuery > 1.9:

$.ajax({
    url: '/v1/object/3.json',
    method: 'DELETE',
    contentType: 'application/json',
    success: function(result) {
        // handle success
    },
    error: function(request,msg,error) {
        // handle failure
    }
});

其他回答

简洁:

$.delete = function(url, data, callback, type){

  if ( $.isFunction(data) ){
    type = type || callback,
    callback = data,
    data = {}
  }

  return $.ajax({
    url: url,
    type: 'DELETE',
    success: callback,
    data: data,
    contentType: type
  });
}

CRUD

这可能更有道理

创建(POST)请求

function creat() {
  $.ajax({
    type: "POST",
    url: URL,
    contentType: "application/json",
    data: JSON.stringify(DATA1),
    success: function () {
      var msg = "create successful";
      console.log(msg);
      htmlOutput(msg);
    },
  });
}

READ()请求

// GET EACH ELEMENT (UNORDERED)
function read_all() {
  $.ajax({
    type: "GET",
    url: URL,
    success: function (res) {
      console.log("success!");
      console.log(res);
      htmlOutput(res);
    },
  });
}

// GET EACH ELEMENT BY JSON
function read_one() {
  $.ajax({
    type: "GET",
    url: URL,
    success: function (res) {
      $.each(res, function (index, element) {
        console.log("success");
        htmlOutput(element.name);
      });
    },
  });
}

更新(把)请求

function updat() {
  $.ajax({
    type: "PUT",
    url: updateURL,
    contentType: "application/json",
    data: JSON.stringify(DATA2),
    success: function () {
      var msg = "update successful";
      console.log(msg);
      htmlOutput(msg);
    },
  });
}

删除(删除)的请求

function delet() {
  $.ajax({
    type: "DELETE",
    url: deleteURL,
    success: function () {
      var msg = "delete successful";
      console.log(msg);
      htmlOutput(msg);
    },
  });
}

GitHub参考

从这里,你可以这样做:

/* Extend jQuery with functions for PUT and DELETE requests. */

function _ajax_request(url, data, callback, type, method) {
    if (jQuery.isFunction(data)) {
        callback = data;
        data = {};
    }
    return jQuery.ajax({
        type: method,
        url: url,
        data: data,
        success: callback,
        dataType: type
        });
}

jQuery.extend({
    put: function(url, data, callback, type) {
        return _ajax_request(url, data, callback, type, 'PUT');
    },
    delete_: function(url, data, callback, type) {
        return _ajax_request(url, data, callback, type, 'DELETE');
    }
});

它基本上只是一个复制的$.post()与方法参数调整。

你可以使用ajax方法:

$.ajax({
    url: '/script.cgi',
    type: 'DELETE',
    success: function(result) {
        // Do something with the result
    }
});

如果你想赚美元。将工作post到Laravel Route::delete或Route::put只需添加一个参数"_method"="delete"或"_method"="put"。

$.post("your/uri/here", {"arg1":"value1",...,"_method":"delete"}, function(data){}); ...

必须适用于其他框架

注:用Laravel 5.6和jQuery 3测试