不。Java中的所有异常都必须成为Java .lang的子类。虽然这可能不是一个好的实践，但你可以像这样捕获每种类型的异常:

try {
    //Stuff
} catch ( Throwable T ){
    //Doesn't matter what it was, I caught it.
}

有关更多信息，请参阅java.lang.Throwable文档。

如果您试图避免检查异常(必须显式处理的异常)，那么您将希望继承Error或RuntimeException类。

Two fundamental problems with exception handling in Java are that it uses the type of an exception to indicate whether action should be taken based upon it, and that anything which takes action based upon an exception (i.e. "catch"es it) is presumed to resolve the underlying condition. It would be useful to have a means by which an exception object could decide which handlers should execute, and whether the handlers that have executed so far have cleaned things up enough for the present method to satisfy its exit conditions. While this could be used to make "uncatchable" exceptions, two bigger uses would be to (1) make exceptions which will only be considered handled when they're caught by code that actually knows how to deal with them, and (2) allow for sensible handling of exceptions which occur in a finally block (if a FooException during a finally block during the unwinding of a BarException, both exceptions should propagate up the call stack; both should be catchable, but unwinding should continue until both have been caught). Unfortunately, I don't think there would be any way to make existing exception-handling code work that way without breaking things.

我没有尝试过这个，所以我不知道JVM是否会限制这样的东西，但也许你可以编译抛出ChuckNorrisException的代码，但在运行时提供ChuckNorrisException的类定义，它不扩展Throwable。

更新:

不管用。它生成一个验证错误:

Exception in thread "main" java.lang.VerifyError: (class: TestThrow, method: ma\
in signature: ([Ljava/lang/String;)V) Can only throw Throwable objects
Could not find the main class: TestThrow.  Program will exit.

更新2:

实际上，如果您禁用字节码验证器，您可以让它工作!(-Xverify:没有)

更新3:

对于那些在家跟随的人，这里是完整的脚本:

创建以下类:

public class ChuckNorrisException
    extends RuntimeException // <- Comment out this line on second compilation
{
    public ChuckNorrisException() { }
}

public class TestVillain {
    public static void main(String[] args) {
        try {
            throw new ChuckNorrisException();
        }
        catch(Throwable t) {
            System.out.println("Gotcha!");
        }
        finally {
            System.out.println("The end.");
        }
    }
}

编译类:

javac -cp . TestVillain.java ChuckNorrisException.java

Run:

java -cp . TestVillain
Gotcha!
The end.

注释掉"extends RuntimeException"，只重新编译ChuckNorrisException.java:

javac -cp . ChuckNorrisException.java

Run:

java -cp . TestVillain
Exception in thread "main" java.lang.VerifyError: (class: TestVillain, method: main signature: ([Ljava/lang/String;)V) Can only throw Throwable objects
Could not find the main class: TestVillain.  Program will exit.

未经验证运行:

java -Xverify:none -cp . TestVillain
The end.
Exception in thread "main"

是否有可能在java中构造一段代码，使假设的java.lang. chucknorrisexception无法捕获?

是的，这就是答案:设计你的java.lang.ChuckNorrisException，使它不是java.lang.Throwable的实例。为什么?从定义上讲，不可抛出的对象是不可捕获的，因为你永远不能捕获永远不能抛出的东西。

实际上，公认的答案并不是那么好，因为Java需要在没有验证的情况下运行，即代码在正常情况下无法工作。

AspectJ拯救了真正的解决方案!

异常类:

package de.scrum_master.app;

public class ChuckNorrisException extends RuntimeException {
    public ChuckNorrisException(String message) {
        super(message);
    }
}

方面:

package de.scrum_master.aspect;

import de.scrum_master.app.ChuckNorrisException;

public aspect ChuckNorrisAspect {
    before(ChuckNorrisException chuck) : handler(*) && args(chuck) {
        System.out.println("Somebody is trying to catch Chuck Norris - LOL!");
        throw chuck;
    }
}

示例应用程序:

package de.scrum_master.app;

public class Application {
    public static void main(String[] args) {
        catchAllMethod();
    }

    private static void catchAllMethod() {
        try {
            exceptionThrowingMethod();
        }
        catch (Throwable t) {
            System.out.println("Gotcha, " + t.getClass().getSimpleName() + "!");
        }
    }

    private static void exceptionThrowingMethod() {
        throw new ChuckNorrisException("Catch me if you can!");
    }
}

输出:

Somebody is trying to catch Chuck Norris - LOL!
Exception in thread "main" de.scrum_master.app.ChuckNorrisException: Catch me if you can!
    at de.scrum_master.app.Application.exceptionThrowingMethod(Application.java:18)
    at de.scrum_master.app.Application.catchAllMethod(Application.java:10)
    at de.scrum_master.app.Application.main(Application.java:5)

抛出的任何异常都必须扩展Throwable，因此总是可以捕获它。所以答案是否定的。

如果你想让它难以处理，你可以重写方法getCause()， getMessage()， getStackTrace()， toString()抛出另一个java.lang.ChuckNorrisException。