我正在尝试转换格式为2009-09-12 20:57:19的时间戳,并将其转换为3分钟前用PHP。
我找到了一个有用的脚本来做这件事,但我认为它正在寻找一种不同的格式来用作时间变量。我想修改的脚本与此格式的工作是:
function _ago($tm,$rcs = 0) {
$cur_tm = time();
$dif = $cur_tm-$tm;
$pds = array('second','minute','hour','day','week','month','year','decade');
$lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);
for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]);
$no = floor($no);
if($no <> 1)
$pds[$v] .='s';
$x = sprintf("%d %s ",$no,$pds[$v]);
if(($rcs == 1)&&($v >= 1)&&(($cur_tm-$_tm) > 0))
$x .= time_ago($_tm);
return $x;
}
我认为在前几行脚本试图做的事情看起来像这样(不同的日期格式数学):
$dif = 1252809479 - 2009-09-12 20:57:19;
如何将我的时间戳转换成那种(unix?)格式?
我发现结果如下:
1年2个月0天0小时53分1秒
正因为如此,我实现了一个尊重复数的函数,删除空值,并有可能缩短输出:
function since($timestamp, $level=6) {
global $lang;
$date = new DateTime();
$date->setTimestamp($timestamp);
$date = $date->diff(new DateTime());
// build array
$since = array_combine(array('year', 'month', 'day', 'hour', 'minute', 'second'), explode(',', $date->format('%y,%m,%d,%h,%i,%s')));
// remove empty date values
$since = array_filter($since);
// output only the first x date values
$since = array_slice($since, 0, $level);
// build string
$last_key = key(array_slice($since, -1, 1, true));
$string = '';
foreach ($since as $key => $val) {
// separator
if ($string) {
$string .= $key != $last_key ? ', ' : ' ' . $lang['and'] . ' ';
}
// set plural
$key .= $val > 1 ? 's' : '';
// add date value
$string .= $val . ' ' . $lang[ $key ];
}
return $string;
}
看起来好多了:
1年2个月53分1秒
可以选择使用$level = 2来缩短它,如下所示:
1年2个月
如果你只需要它的英文版本,就删除$lang部分,或者编辑这个翻译来满足你的需要:
$lang = array(
'second' => 'Sekunde',
'seconds' => 'Sekunden',
'minute' => 'Minute',
'minutes' => 'Minuten',
'hour' => 'Stunde',
'hours' => 'Stunden',
'day' => 'Tag',
'days' => 'Tage',
'month' => 'Monat',
'months' => 'Monate',
'year' => 'Jahr',
'years' => 'Jahre',
'and' => 'und',
);
我修改了原来的函数一点(在我看来更有用,或更符合逻辑)。
// display "X time" ago, $rcs is precision depth
function time_ago ($tm, $rcs = 0) {
$cur_tm = time();
$dif = $cur_tm - $tm;
$pds = array('second','minute','hour','day','week','month','year','decade');
$lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);
for ($v = count($lngh) - 1; ($v >= 0) && (($no = $dif / $lngh[$v]) <= 1); $v--);
if ($v < 0)
$v = 0;
$_tm = $cur_tm - ($dif % $lngh[$v]);
$no = ($rcs ? floor($no) : round($no)); // if last denomination, round
if ($no != 1)
$pds[$v] .= 's';
$x = $no . ' ' . $pds[$v];
if (($rcs > 0) && ($v >= 1))
$x .= ' ' . $this->time_ago($_tm, $rcs - 1);
return $x;
}
一些语言显示时间之前有一些问题,例如阿拉伯语,有3种格式需要显示日期。
我在我的项目中使用这个函数,希望他们能帮助到别人(任何建议或改进我都会很感激:))
/**
*
* @param string $date1
* @param string $date2 the date that you want to compare with $date1
* @param int $level
* @param bool $absolute
*/
function app_date_diff( $date1, $date2, $level = 3, $absolute = false ) {
$date1 = date_create($date1);
$date2 = date_create($date2);
$diff = date_diff( $date1, $date2, $absolute );
$d = [
'invert' => $diff->invert
];
$diffs = [
'y' => $diff->y,
'm' => $diff->m,
'd' => $diff->d
];
$level_reached = 0;
foreach($diffs as $k=>$v) {
if($level_reached >= $level) {
break;
}
if($v > 0) {
$d[$k] = $v;
$level_reached++;
}
}
return $d;
}
/**
*
*/
function date_timestring( $periods, $format = 'latin', $separator = ',' ) {
$formats = [
'latin' => [
'y' => ['year','years'],
'm' => ['month','months'],
'd' => ['day','days']
],
'arabic' => [
'y' => ['سنة','سنتين','سنوات'],
'm' => ['شهر','شهرين','شهور'],
'd' => ['يوم','يومين','أيام']
]
];
$formats = $formats[$format];
$string = [];
foreach($periods as $period=>$value) {
if(!isset($formats[$period])) {
continue;
}
$string[$period] = $value.' ';
if($format == 'arabic') {
if($value == 2) {
$string[$period] = $formats[$period][1];
}elseif($value > 2 && $value <= 10) {
$string[$period] .= $formats[$period][2];
}else{
$string[$period] .= $formats[$period][0];
}
}elseif($format == 'latin') {
$string[$period] .= ($value > 1) ? $formats[$period][1] : $formats[$period][0];
}
}
return implode($separator, $string);
}
function timeago( $date ) {
$today = date('Y-m-d h:i:s');
$diff = app_date_diff($date,$today,2);
if($diff['invert'] == 1) {
return '';
}
unset($diff[0]);
$date_timestring = date_timestring($diff,'latin');
return 'About '.$date_timestring;
}
$date1 = date('Y-m-d');
$date2 = '2018-05-14';
$diff = timeago($date2);
echo $diff;