我正在尝试转换格式为2009-09-12 20:57:19的时间戳,并将其转换为3分钟前用PHP。

我找到了一个有用的脚本来做这件事,但我认为它正在寻找一种不同的格式来用作时间变量。我想修改的脚本与此格式的工作是:

function _ago($tm,$rcs = 0) {
    $cur_tm = time(); 
    $dif = $cur_tm-$tm;
    $pds = array('second','minute','hour','day','week','month','year','decade');
    $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);

    for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]);
        $no = floor($no);
        if($no <> 1)
            $pds[$v] .='s';
        $x = sprintf("%d %s ",$no,$pds[$v]);
        if(($rcs == 1)&&($v >= 1)&&(($cur_tm-$_tm) > 0))
            $x .= time_ago($_tm);
        return $x;
    }

我认为在前几行脚本试图做的事情看起来像这样(不同的日期格式数学):

$dif = 1252809479 - 2009-09-12 20:57:19;

如何将我的时间戳转换成那种(unix?)格式?


当前回答

这其实是我找到的一个更好的解决方案。使用jQuery,但它的工作完美。此外,它会自动刷新类似于SO和Facebook的方式,所以你不需要刷新页面就能看到更新。

这个插件将读取<time>标签中的datetime attr,并为您填写它。

e.g. "4 minutes ago" or "about 1 day ago

http://timeago.yarp.com/

其他回答

直接回答这个问题…你可以用…

strtotime()

https://www.php.net/manual/en/function.strtotime.php

$dif = time() - strtotime("2009-09-12 20:57:19");

E.G:

echo round(((( time() - strtotime("2021-08-01 21:57:50") )/60)/60)/24).' day(s) ago';

结果:1天前

function time_elapsed_string($ptime)
{
    $etime = time() - $ptime;

    if ($etime < 1)
    {
        return '0 seconds';
    }

    $a = array( 365 * 24 * 60 * 60  =>  'year',
                 30 * 24 * 60 * 60  =>  'month',
                      24 * 60 * 60  =>  'day',
                           60 * 60  =>  'hour',
                                60  =>  'minute',
                                 1  =>  'second'
                );
    $a_plural = array( 'year'   => 'years',
                       'month'  => 'months',
                       'day'    => 'days',
                       'hour'   => 'hours',
                       'minute' => 'minutes',
                       'second' => 'seconds'
                );

    foreach ($a as $secs => $str)
    {
        $d = $etime / $secs;
        if ($d >= 1)
        {
            $r = round($d);
            return $r . ' ' . ($r > 1 ? $a_plural[$str] : $str) . ' ago';
        }
    }
}

下面是一个非常简单和非常有效的解决方案。

function timeElapsed($originalTime){

        $timeElapsed=time()-$originalTime;

        /*
          You can change the values of the following 2 variables 
          based on your opinion. For 100% accuracy, you can call
          php's cal_days_in_month() and do some additional coding
          using the values you get for each month. After all the
          coding, your final answer will be approximately equal to
          mine. That is why it is okay to simply use the average
          values below.
        */
        $averageNumbDaysPerMonth=(365.242/12);
        $averageNumbWeeksPerMonth=($averageNumbDaysPerMonth/7);

        $time1=(((($timeElapsed/60)/60)/24)/365.242);
        $time2=floor($time1);//Years
        $time3=($time1-$time2)*(365.242);
        $time4=($time3/$averageNumbDaysPerMonth);
        $time5=floor($time4);//Months
        $time6=($time4-$time5)*$averageNumbWeeksPerMonth;
        $time7=floor($time6);//Weeks
        $time8=($time6-$time7)*7;
        $time9=floor($time8);//Days
        $time10=($time8-$time9)*24;
        $time11=floor($time10);//Hours
        $time12=($time10-$time11)*60;
        $time13=floor($time12);//Minutes
        $time14=($time12-$time13)*60;
        $time15=round($time14);//Seconds

        $timeElapsed=$time2 . 'yrs ' . $time5 . 'months ' . $time7 . 
                     'weeks ' . $time9 .  'days ' . $time11 . 'hrs '
                     . $time13 . 'mins and ' . $time15 . 'secs.';

        return $timeElapsed;

}

回显时间已用(1201570814);

样例输出:

6年4个月3周4天12小时40分36秒。

我修改了原来的函数一点(在我看来更有用,或更符合逻辑)。

// display "X time" ago, $rcs is precision depth
function time_ago ($tm, $rcs = 0) {
  $cur_tm = time(); 
  $dif = $cur_tm - $tm;
  $pds = array('second','minute','hour','day','week','month','year','decade');
  $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);

  for ($v = count($lngh) - 1; ($v >= 0) && (($no = $dif / $lngh[$v]) <= 1); $v--);
    if ($v < 0)
      $v = 0;
  $_tm = $cur_tm - ($dif % $lngh[$v]);

  $no = ($rcs ? floor($no) : round($no)); // if last denomination, round

  if ($no != 1)
    $pds[$v] .= 's';
  $x = $no . ' ' . $pds[$v];

  if (($rcs > 0) && ($v >= 1))
    $x .= ' ' . $this->time_ago($_tm, $rcs - 1);

  return $x;
}

我通常使用它来找出当前和传递的日期时间戳之间的差异

输出

//If difference is greater than 7 days
7 June 2019

// if difference is greater than 24 hours and less than 7 days
1 days ago
6 days ago

1 hour ago
23 hours ago

1 minute ago
58 minutes ago

1 second ago
20 seconds ago

CODE

//return current date time
function getCurrentDateTime(){
    //date_default_timezone_set("Asia/Calcutta");
    return date("Y-m-d H:i:s");
}
function getDateString($date){
    $dateArray = date_parse_from_format('Y/m/d', $date);
    $monthName = DateTime::createFromFormat('!m', $dateArray['month'])->format('F');
    return $dateArray['day'] . " " . $monthName  . " " . $dateArray['year'];
}

function getDateTimeDifferenceString($datetime){
    $currentDateTime = new DateTime(getCurrentDateTime());
    $passedDateTime = new DateTime($datetime);
    $interval = $currentDateTime->diff($passedDateTime);
    //$elapsed = $interval->format('%y years %m months %a days %h hours %i minutes %s seconds');
    $day = $interval->format('%a');
    $hour = $interval->format('%h');
    $min = $interval->format('%i');
    $seconds = $interval->format('%s');

    if($day > 7)
        return getDateString($datetime);
    else if($day >= 1 && $day <= 7 ){
        if($day == 1) return $day . " day ago";
        return $day . " days ago";
    }else if($hour >= 1 && $hour <= 24){
        if($hour == 1) return $hour . " hour ago";
        return $hour . " hours ago";
    }else if($min >= 1 && $min <= 60){
        if($min == 1) return $min . " minute ago";
        return $min . " minutes ago";
    }else if($seconds >= 1 && $seconds <= 60){
        if($seconds == 1) return $seconds . " second ago";
        return $seconds . " seconds ago";
    }
}