经过多次测试，这是我发现的最好的方法:)

Set<User> test = httpService.get(url).toResponseSet(User[].class);

这就是你所需要的

public <T> Set<T> toResponseSet(Class<T[]> setType) {
    HttpEntity<?> body = new HttpEntity<>(objectBody, headers);
    ResponseEntity<T[]> response = template.exchange(url, method, body, setType);
    return Sets.newHashSet(response.getBody());
}

这里提到了3种检索对象列表的方法。所有这些都将完美地工作

@RequestMapping(value = "/emp2", produces = "application/json")
public List<Employee> getEmp2()
{
    HttpHeaders headers = new HttpHeaders();
    headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
    HttpEntity<String> entity = new HttpEntity<String>(headers);
    ResponseEntity<List<Employee>> response = restTemplate.exchange(
            "http://hello-server/rest/employees", HttpMethod.GET,entity, 
    new ParameterizedTypeReference<List<Employee>>() {});
    return response.getBody();
}

(或)

@RequestMapping(value = "/emp3", produces = "application/json")
public List<Employee> getEmp3()
{
    Employee[] empArray = restTemplate.getForObject("http://hello-server/rest/employees", Employee[].class);
    List<Employee> emp= Arrays.asList(empArray);
    return emp;
}

(或)

    @RequestMapping(value = "/emp4", produces = "application/json")
public Employee[] getEmp4()
{
    ResponseEntity<Employee[]> responseEntity = restTemplate.getForEntity("http://hello-server/rest/employees", Employee[].class);
    Employee[] empList = responseEntity.getBody();
    //MediaType contentType = responseEntity.getHeaders().getContentType();
    //HttpStatus statusCode = responseEntity.getStatusCode();
    return  empList;
}

Employee.class

public class Employee {

private Integer id;
private String name;
private String Designation;
private String company;

//getter setters and toString()

}

作为一个通用模块，Page<?>对象可以被模块反序列化，就像JodaModule, Log4jJsonModule等。参考我的回答。使用Pageable字段测试端点时出现JsonMappingException

首先定义一个对象来保存返回数组的实体。如。

@JsonIgnoreProperties(ignoreUnknown = true)
public class Rate {
    private String name;
    private String code;
    private Double rate;
    // add getters and setters
}

然后你可以使用该服务并通过以下方式获得一个强类型列表:

ResponseEntity<List<Rate>> rateResponse =
        restTemplate.exchange("https://bitpay.com/api/rates",
                    HttpMethod.GET, null, new ParameterizedTypeReference<List<Rate>>() {
            });
List<Rate> rates = rateResponse.getBody();

上面的其他解决方案也可以工作，但我喜欢得到一个强类型列表，而不是Object[]。

我从这个帖子https://jira.spring.io/browse/SPR-8263找到了工作。

基于这篇文章，你可以返回一个类似这样的列表:

ResponseEntity<? extends ArrayList<User>> responseEntity = restTemplate.getForEntity(restEndPointUrl, (Class<? extends ArrayList<User>>)ArrayList.class, userId);

你可以为每个条目创建POJO，

class BitPay{
private String code;
private String name;
private double rate;
}

然后使用BitPay列表的ParameterizedTypeReference，你可以使用:

RestTemplate restTemplate = new RestTemplate();
ResponseEntity<List<Employee>> response = restTemplate.exchange(
  "https://bitpay.com/api/rates",
  HttpMethod.GET,
  null,
  new ParameterizedTypeReference<List<BitPay>>(){});
List<Employee> employees = response.getBody();