谁能给我解释一下模板方法模式和策略模式的区别是什么?
据我所知,它们99%是一样的——唯一的区别是 模板方法模式有一个抽象类作为基础 类,而策略类使用已实现的接口 由每个具体的策略类。
然而,就客户端而言,它们是以完全相同的方式被消费的——这是正确的吗?
谁能给我解释一下模板方法模式和策略模式的区别是什么?
据我所知,它们99%是一样的——唯一的区别是 模板方法模式有一个抽象类作为基础 类,而策略类使用已实现的接口 由每个具体的策略类。
然而,就客户端而言,它们是以完全相同的方式被消费的——这是正确的吗?
当前回答
模板方法:
它是基于继承的 定义了不能被子类改变的算法框架。只有某些操作可以在子类中被重写 父类完全控制算法,只与具体类的某些步骤不同 绑定在编译时完成
Template_method结构:
策略:
它基于委托/组合 它通过修改方法行为来改变对象的内容 它用来在一系列算法之间切换 它通过在运行时完全将一种算法替换为另一种算法来改变对象在运行时的行为 绑定在运行时完成
战略结构:
为了更好地理解,请查看Template方法和策略文章。
相关文章:
在JDK模板设计模式中,找不到一个方法定义了一组要按顺序执行的方法
策略模式的真实例子
其他回答
模板模式:
模板方法是关于让子类重新定义算法的某些步骤,而不改变基类中定义的算法的主要结构和步骤。 模板模式通常使用继承,因此可以在基类中提供算法的泛型实现,如果需要,子类可以选择覆盖它。
public abstract class RobotTemplate {
/* This method can be overridden by a subclass if required */
public void start() {
System.out.println("Starting....");
}
/* This method can be overridden by a subclass if required */
public void getParts() {
System.out.println("Getting parts....");
}
/* This method can be overridden by a subclass if required */
public void assemble() {
System.out.println("Assembling....");
}
/* This method can be overridden by a subclass if required */
public void test() {
System.out.println("Testing....");
}
/* This method can be overridden by a subclass if required */
public void stop() {
System.out.println("Stopping....");
}
/*
* Template algorithm method made up of multiple steps, whose structure and
* order of steps will not be changed by subclasses.
*/
public final void go() {
start();
getParts();
assemble();
test();
stop();
}
}
/* Concrete subclass overrides template step methods as required for its use */
public class CookieRobot extends RobotTemplate {
private String name;
public CookieRobot(String n) {
name = n;
}
@Override
public void getParts() {
System.out.println("Getting a flour and sugar....");
}
@Override
public void assemble() {
System.out.println("Baking a cookie....");
}
@Override
public void test() {
System.out.println("Crunching a cookie....");
}
public String getName() {
return name;
}
}
注意在上面的代码中,go()算法步骤总是相同的,但是子类可能为执行特定步骤定义不同的配方。
策略模式:
策略模式是指让客户端在运行时选择具体的算法实现。所有算法都是隔离且独立的,但是实现了一个公共接口,并且没有在算法中定义特定步骤的概念。
/**
* This Strategy interface is implemented by all concrete objects representing an
* algorithm(strategy), which lets us define a family of algorithms.
*/
public interface Logging {
void write(String message);
}
/**
* Concrete strategy class representing a particular algorithm.
*/
public class ConsoleLogging implements Logging {
@Override
public void write(String message) {
System.out.println(message);
}
}
/**
* Concrete strategy class representing a particular algorithm.
*/
public class FileLogging implements Logging {
private final File toWrite;
public FileLogging(final File toWrite) {
this.toWrite = toWrite;
}
@Override
public void write(String message) {
try {
final FileWriter fos = new FileWriter(toWrite);
fos.write(message);
fos.close();
} catch (IOException e) {
System.out.println(e);
}
}
}
要获得完整的源代码,请查看我的github存储库。
You probably mean template method pattern. You are right, they serve very similar needs. I would say it is better to use template method in cases when you have a "template" algorithm having defined steps where subclasses override these steps to change some details. In case of strategy, you need to create an interface, and instead of inheritance you are using delegation. I would say it is a bit more powerful pattern and maybe better in accordance to DIP - dependency inversion principles. It is more powerful because you clearly define a new abstraction of strategy - a way of doing something, which does not apply to template method. So, if this abstraction makes sense - use it. However, using template method may give you simpler designs in simple cases, which is also important. Consider which words fit better: do you have a template algorithm? Or is the key thing here that you have an abstraction of strategy - new way of doing something
模板方法的例子:
Application.main()
{
Init();
Run();
Done();
}
这里你继承了application,并替换了init, run和done的操作。
策略的例子:
array.sort (IComparer<T> comparer)
在这里,当编写比较器时,您不继承数组。数组将比较算法委托给比较器。
我认为主要的区别是,有了模板,你需要一个算法来做一些事情,但让我们说,在算法的中间,你想要运行不同的行为,所以你可以发送一个接口的实现,使算法在运行时动态。
但是对于策略,你实际上有完全不同的算法执行而不仅仅是算法的一个变体,然后你选择运行哪个算法,但是模板你只有一个变体的算法。
最后,你可以实现你想要的,使用模板作为策略,反之亦然,但我看到了区别。
两者都非常相似,客户端代码以类似的方式使用它们。与上面最流行的答案不同,两者都允许在运行时选择算法。
The difference between the two is that while the strategy pattern allows different implementations to use completely different ways of the achieving the desired outcome, the template method pattern specifies an overarching algorithm (the "template" method) which is be used to achieve the result -- the only choice left to the specific implementations (sub-classes) are certain details of the said template method. This is done by having the the template method make call(s) to one or more abstract methods which are overridden (i.e. implemented) by the sub-classes, unlike the template method which itself is not abstract and not overridden by the sub-classes.
客户端代码使用抽象类类型的引用/指针调用模板方法,该引用/指针指向具体子类之一的实例,该实例可以在运行时确定,就像使用策略模式时一样。
它们都是不同的技术来达到相同的结果,所以问题是在什么时候使用哪一种。
If you are using a framework or library which you do not have access to the source code and you want to change some behaviors of a class, so you have to go for Template Method. That means inheritance simply. If you are developing a class and it is obvious that some parts of the logic needs to be implemented differently to handle various situations, take the Strategy pattern. Strategy is more SOLID than the Template Method. It covers both Dependency Inversion and Open/Close principles. So it is extendable and also easily testable. If you are developing a class and you do not know what changes will happen in the future, divide your logic into separate and single responsible functions as much as possible. Just that. (Neither Template Method nor Strategy).