只有一句话:

Object.entries(GoalProgressMeasurements).map(([key, value]) => ({id: key, value: value}))

多亏了波尔科夫尼科夫。我终于能够找到一个解决方案，将工作的大多数用例。

问题的有效解

type Descripted<T> = {
    [K in keyof T]: {
        readonly id: T[K];
        readonly description: string;
    }
}[keyof T]

/**
 * Helper to produce an array of enum descriptors.
 * @param enumeration Enumeration object.
 * @param separatorRegex Regex that would catch the separator in your enum key.
 */
export function enumToDescriptedArray<T>(enumeration: T, separatorRegex: RegExp = /_/g): Descripted<T>[] {
    return (Object.keys(enumeration) as Array<keyof T>)
        .filter(key => isNaN(Number(key)))
        .filter(key => typeof enumeration[key] === "number" || typeof enumeration[key] === "string")
        .map(key => ({
            id: enumeration[key],
            description: String(key).replace(separatorRegex, ' '),
        }));
}

例子:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

console.log(enumToDescriptedArray(GoalProgressMeasurements))
// Produces:
/*
[
    {id: 1, description: "Percentage"},
    {id: 2, description: "Numeric Target"},
    {id: 3, description: "Completed Tasks"},
    {id: 4, description: "Average Milestone Progress"},
    {id: 5, description: "Not Measured"}
]
*/

此外，我还使用了一个有用的util函数来将枚举对象映射到它拥有的可用值数组:

该映射器

type NonFunctional<T> = T extends Function ? never : T;

/**
 * Helper to produce an array of enum values.
 * @param enumeration Enumeration object.
 */
export function enumToArray<T>(enumeration: T): NonFunctional<T[keyof T]>[] {
    return Object.keys(enumeration)
        .filter(key => isNaN(Number(key)))
        .map(key => enumeration[key])
        .filter(val => typeof val === "number" || typeof val === "string");
}

用例工作

数字枚举

enum Colors1 {
    WHITE = 0,
    BLACK = 1
}
console.log(Object.values(Colors1)); // ['WHITE', 'BLACK', 0, 1]
console.log(enumToArray(Colors1));   // [0, 1]

字符串枚举

enum Colors2 {
    WHITE = "white",
    BLACK = "black"
}
console.log(Object.values(Colors2)); // ['white', 'black']
console.log(enumToArray(Colors2));   // ['white', 'black']

异构枚举

enum Colors4 {
    WHITE = "white",
    BLACK = 0
}
console.log(Object.values(Colors4)); // ["BLACK", "white", 0]
console.log(enumToArray(Colors4));   // ["white", 0]

与具有导出函数的命名空间合并的Enum

enum Colors3 {
    WHITE = "white",
    BLACK = "black"
}
namespace Colors3 {
    export function fun() {}
}
console.log(Object.values(Colors3)); // ['white', 'black', Function]
console.log(enumToArray(Colors3));   // ['white', 'black']

enum目标进度测量{ 百分比= 1， Numeric_Target = 2， Completed_Tasks = 3， average_milestone one_progress = 4， Not_Measured = 5 ｝ Const数组= [] for (const [key, value] of Object.entries(GoalProgressMeasurements)) { if (!Number. isnan (Number(key)) { 继续; ｝ 数组中。Push ({id:值，名称:键。Replace ('_'， ")}); ｝ console.log(数组);

我不认为顺序是可以保证的，否则就很容易切片Object的后半部分。条目的结果和映射来自那里。

上述答案的唯一(非常小的)问题是

字符串和数字之间有很多不必要的类型转换。 当一次迭代同样干净有效时，条目将迭代两次。

type StandardEnum = { [id: string]: number | string; [nu: number]: string;}

function enumToList<T extends StandardEnum> (enm: T) : { id: number; description: string }[] {
    return Object.entries(enm).reduce((accum, kv) => {
        if (typeof kv[1] === 'number') {
            accum.push({ id: kv[1], description: kv[0] })
        }
        return accum
    }, []) // if enum is huge, perhaps pre-allocate with new Array(entries.length / 2), however then push won't work, so tracking an index would also be required
}

枚举是运行时存在的真实对象。所以你可以这样反向映射:

let value = GoalProgressMeasurements.Not_Measured;
console.log(GoalProgressMeasurements[value]);
// => Not_Measured

基于此，您可以使用以下代码:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

let map: {id: number; name: string}[] = [];

for(var n in GoalProgressMeasurements) {
    if (typeof GoalProgressMeasurements[n] === 'number') {
        map.push({id: <any>GoalProgressMeasurements[n], name: n});
    }
}

console.log(map);

参考:https://www.typescriptlang.org/docs/handbook/enums.html

我很惊讶，在一个TypeScript线程中，没有人给出支持类型的有效TypeScript函数。下面是@user8363解决方案的变化:

const isStringNumber = (value: string) => isNaN(Number(value)) === false;

function enumToArray<T extends {}>(givenEnum: T) {
  return (Object.keys(givenEnum).filter(isStringNumber) as (keyof T)[]).map(
    (key) => givenEnum[key]
  );
}