完全容易复制和粘贴代码构建从@ZacBowling的解决方案(https://stackoverflow.com/a/1535427/2298002)

这也将把用户带到你的应用程序设置，并允许他们立即启用

我还添加了一个解决方案，用于检查位置服务是否启用(以及带来的设置)

// check if notification service is enabled
+ (void)checkNotificationServicesEnabled
{
    if (![[UIApplication sharedApplication] isRegisteredForRemoteNotifications])
    {
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Notification Services Disabled!"
                                                            message:@"Yo don't mess around bro! Enabling your Notifications allows you to receive important updates"
                                                           delegate:self
                                                  cancelButtonTitle:@"Cancel"
                                                  otherButtonTitles:@"Settings", nil];

        alertView.tag = 300;

        [alertView show];

        return;
    }
}

// check if location service is enabled (ref: https://stackoverflow.com/a/35982887/2298002)
+ (void)checkLocationServicesEnabled
{
    //Checking authorization status
    if (![CLLocationManager locationServicesEnabled] || [CLLocationManager authorizationStatus] == kCLAuthorizationStatusDenied)
    {

        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Location Services Disabled!"
                                                            message:@"You need to enable your GPS location right now!!"
                                                           delegate:self
                                                  cancelButtonTitle:@"Cancel"
                                                  otherButtonTitles:@"Settings", nil];

        //TODO if user has not given permission to device
        if (![CLLocationManager locationServicesEnabled])
        {
            alertView.tag = 100;
        }
        //TODO if user has not given permission to particular app
        else
        {
            alertView.tag = 200;
        }

        [alertView show];

        return;
    }
}

// handle bringing user to settings for each
+ (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{

    if(buttonIndex == 0)// Cancel button pressed
    {
        //TODO for cancel
    }
    else if(buttonIndex == 1)// Settings button pressed.
    {
        if (alertView.tag == 100)
        {
            //This will open ios devices location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=LOCATION_SERVICES"]];
        }
        else if (alertView.tag == 200)
        {
            //This will open particular app location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
        }
        else if (alertView.tag == 300)
        {
            //This will open particular app location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
        }
    }
}

GLHF !

quantumpotato的问题:

类型是由

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];

可以使用

if (types & UIRemoteNotificationTypeAlert)

而不是

if (types == UIRemoteNotificationTypeNone) 

将允许你只检查通知是否启用(不用担心声音，徽章，通知中心等)。第一行代码(types & UIRemoteNotificationTypeAlert)如果“Alert Style”设置为“横幅”或“警报”将返回YES，如果“Alert Style”设置为“None”则返回NO，与其他设置无关。

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types & UIRemoteNotificationTypeAlert)
    // blah blah blah
{
    NSLog(@"Notification Enabled");
}
else
{
    NSLog(@"Notification not enabled");
}

这里我们从UIApplication获得UIRemoteNotificationType。它代表了这个应用程序在设置中的推送通知的状态，然后你可以很容易地检查它的类型

为了完成这个答案，它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西，它不会与开关工作，所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

我尝试使用@Shaheen ghassy提供的解决方案支持iOS 10及以上版本，但发现剥夺问题enabledRemoteNotificationTypes。所以，我找到的解决方案是使用isregisteredforremotenotification而不是enabledRemoteNotificationTypes，这在iOS 8中已弃用。下面是我最新的解决方案，对我来说非常有效:

- (BOOL)notificationServicesEnabled {
    BOOL isEnabled = NO;
    if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
        UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];

        if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
            isEnabled = NO;
        } else {
            isEnabled = YES;
        }
    } else {

        if ([[UIApplication sharedApplication] isRegisteredForRemoteNotifications]) {
            isEnabled = YES;
        } else{
            isEnabled = NO;
        }
    }
    return isEnabled;
}

我们可以很容易地调用这个函数，访问它的Bool值，并将其转换为字符串值:

NSString *str = [self notificationServicesEnabled] ? @"YES" : @"NO";

希望它也能帮助到其他人:) 快乐的编码。

iOS8+ (OBJECTIVE C)

#import <UserNotifications/UserNotifications.h>


[[UNUserNotificationCenter currentNotificationCenter]getNotificationSettingsWithCompletionHandler:^(UNNotificationSettings * _Nonnull settings) {

    switch (settings.authorizationStatus) {
          case UNAuthorizationStatusNotDetermined:{

            break;
        }
        case UNAuthorizationStatusDenied:{

            break;
        }
        case UNAuthorizationStatusAuthorized:{

            break;
        }
        default:
            break;
    }
}];