什么是最好的方法转换格式的字符串' 1月2日，2010年'到一个日期在Java?
最后，我希望将月、日和年分解为整数，以便我可以使用
Date date = new Date();
date.setMonth()..
date.setYear()..
date.setDay()..
date.setlong currentTime = date.getTime();
将日期转换为时间。
当前回答
我简陋的测试程序。我用它来摆弄格式化程序，查找我在日志文件中找到的长日期(但是谁把它们放在那里了……)
我的测试程序:
package be.test.package.time;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import java.util.TimeZone;
public class TimeWork {
public static void main(String[] args) {
TimeZone timezone = TimeZone.getTimeZone("UTC");
List<Long> longs = new ArrayList<>();
List<String> strings = new ArrayList<>();
//Formatting a date needs a timezone - otherwise the date get formatted to your system time zone.
//Use 24h format HH. In 12h format hh can be in range 0-11, which makes 12 overflow to 0.
DateFormat formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss.SSS");
formatter.setTimeZone(timezone);
Date now = new Date();
//Test dates
strings.add(formatter.format(now));
strings.add("01-01-1970 00:00:00.000");
strings.add("01-01-1970 00:00:01.000");
strings.add("01-01-1970 00:01:00.000");
strings.add("01-01-1970 01:00:00.000");
strings.add("01-01-1970 10:00:00.000");
strings.add("01-01-1970 12:00:00.000");
strings.add("01-01-1970 24:00:00.000");
strings.add("02-01-1970 00:00:00.000");
strings.add("01-01-1971 00:00:00.000");
strings.add("01-01-2014 00:00:00.000");
strings.add("31-12-1969 23:59:59.000");
strings.add("31-12-1969 23:59:00.000");
strings.add("31-12-1969 23:00:00.000");
//Test data
longs.add(now.getTime());
longs.add(-1L);
longs.add(0L); //Long date presentation at - midnight 1/1/1970 UTC - The timezone is important!
longs.add(1L);
longs.add(1000L);
longs.add(60000L);
longs.add(3600000L);
longs.add(36000000L);
longs.add(43200000L);
longs.add(86400000L);
longs.add(31536000000L);
longs.add(1388534400000L);
longs.add(7260000L);
longs.add(1417706084037L);
longs.add(-7260000L);
System.out.println("===== String to long =====");
//Show the long value of the date
for (String string: strings) {
try {
Date date = formatter.parse(string);
System.out.println("Formated date : " + string + " = Long = " + date.getTime());
} catch (ParseException e) {
e.printStackTrace();
}
}
System.out.println("===== Long to String =====");
//Show the date behind the long
for (Long lo : longs) {
Date date = new Date(lo);
String string = formatter.format(date);
System.out.println("Formated date : " + string + " = Long = " + lo);
}
}
}
测试结果:
===== String to long =====
Formated date : 05-12-2014 10:17:34.873 = Long = 1417774654873
Formated date : 01-01-1970 00:00:00.000 = Long = 0
Formated date : 01-01-1970 00:00:01.000 = Long = 1000
Formated date : 01-01-1970 00:01:00.000 = Long = 60000
Formated date : 01-01-1970 01:00:00.000 = Long = 3600000
Formated date : 01-01-1970 10:00:00.000 = Long = 36000000
Formated date : 01-01-1970 12:00:00.000 = Long = 43200000
Formated date : 01-01-1970 24:00:00.000 = Long = 86400000
Formated date : 02-01-1970 00:00:00.000 = Long = 86400000
Formated date : 01-01-1971 00:00:00.000 = Long = 31536000000
Formated date : 01-01-2014 00:00:00.000 = Long = 1388534400000
Formated date : 31-12-1969 23:59:59.000 = Long = -1000
Formated date : 31-12-1969 23:59:00.000 = Long = -60000
Formated date : 31-12-1969 23:00:00.000 = Long = -3600000
===== Long to String =====
Formated date : 05-12-2014 10:17:34.873 = Long = 1417774654873
Formated date : 31-12-1969 23:59:59.999 = Long = -1
Formated date : 01-01-1970 00:00:00.000 = Long = 0
Formated date : 01-01-1970 00:00:00.001 = Long = 1
Formated date : 01-01-1970 00:00:01.000 = Long = 1000
Formated date : 01-01-1970 00:01:00.000 = Long = 60000
Formated date : 01-01-1970 01:00:00.000 = Long = 3600000
Formated date : 01-01-1970 10:00:00.000 = Long = 36000000
Formated date : 01-01-1970 12:00:00.000 = Long = 43200000
Formated date : 02-01-1970 00:00:00.000 = Long = 86400000
Formated date : 01-01-1971 00:00:00.000 = Long = 31536000000
Formated date : 01-01-2014 00:00:00.000 = Long = 1388534400000
Formated date : 01-01-1970 02:01:00.000 = Long = 7260000
Formated date : 04-12-2014 15:14:44.037 = Long = 1417706084037
Formated date : 31-12-1969 21:59:00.000 = Long = -7260000
其他回答
这是一种困难的方法，而且这些Java .util. date setter方法自Java 1.1(1997)以来就已经弃用了。此外，自java引入以来，整个java.util. date类实际上已被弃用(不推荐)。Java 8(2014)中的时间API。
只需使用DateTimeFormatter与输入字符串匹配的模式格式化日期(本教程可在此处获得)。
在“January 2, 2010”作为输入字符串的特定情况下:
“January”是全文月份，因此使用MMMM模式 “2”是一个月中最短的一天，所以使用d模式。 “2010”是4位数字的年份，所以使用yyyy模式。
String string = "January 2, 2010";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM d, yyyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse(string, formatter);
System.out.println(date); // 2010-01-02
注意:如果你的格式模式碰巧也包含时间部分，那么使用localdatetime# parse(文本，格式化程序)而不是localdatetime# parse(文本，格式化程序)。并且，如果您的格式模式碰巧也包含时区，那么使用ZonedDateTime#parse(文本，格式化器)代替。
下面是javadoc的相关摘录，列出了所有可用的格式模式:
| Symbol | Meaning | Presentation | Examples |
|---|---|---|---|
G |
era | text | AD; Anno Domini; A |
u |
year | year | 2004; 04 |
y |
year-of-era | year | 2004; 04 |
D |
day-of-year | number | 189 |
M/L |
month-of-year | number/text | 7; 07; Jul; July; J |
d |
day-of-month | number | 10 |
Q/q |
quarter-of-year | number/text | 3; 03; Q3; 3rd quarter |
Y |
week-based-year | year | 1996; 96 |
w |
week-of-week-based-year | number | 27 |
W |
week-of-month | number | 4 |
E |
day-of-week | text | Tue; Tuesday; T |
e/c |
localized day-of-week | number/text | 2; 02; Tue; Tuesday; T |
F |
week-of-month | number | 3 |
a |
am-pm-of-day | text | PM |
h |
clock-hour-of-am-pm (1-12) | number | 12 |
K |
hour-of-am-pm (0-11) | number | 0 |
k |
clock-hour-of-am-pm (1-24) | number | 0 |
H |
hour-of-day (0-23) | number | 0 |
m |
minute-of-hour | number | 30 |
s |
second-of-minute | number | 55 |
S |
fraction-of-second | fraction | 978 |
A |
milli-of-day | number | 1234 |
n |
nano-of-second | number | 987654321 |
N |
nano-of-day | number | 1234000000 |
V |
time-zone ID | zone-id | America/Los_Angeles; Z; -08:30 |
z |
time-zone name | zone-name | Pacific Standard Time; PST |
O |
localized zone-offset | offset-O | GMT+8; GMT+08:00; UTC-08:00; |
X |
zone-offset 'Z' for zero | offset-X | Z; -08; -0830; -08:30; -083015; -08:30:15; |
x |
zone-offset | offset-x | +0000; -08; -0830; -08:30; -083015; -08:30:15; |
Z |
zone-offset | offset-Z | +0000; -0800; -08:00; |
请注意，它为更流行的模式提供了几个预定义的格式化程序。所以不用例如DateTimeFormatter。ofPattern("EEE, d MMM yyyy HH:mm:ss Z"， Locale.ENGLISH);;这是可能的，因为与SimpleDateFormat相反，它们是线程安全的。因此，如果有必要，您也可以定义自己的。
对于特定的输入字符串格式，您不需要使用显式的DateTimeFormatter:标准的ISO 8601日期，如2016-09-26T17:44:57Z，可以直接使用LocalDateTime#parse(text)进行解析，因为它已经使用了ISO_LOCAL_DATE_TIME格式化器。类似地，LocalDate#parse(text)解析一个没有时间组件的ISO日期(参见ISO_LOCAL_DATE)，而zoneeddatetime #parse(text)解析一个添加了偏移量和时区的ISO日期(参见iso_zoneed_date_time)。
Pre-Java 8
如果你还没有使用Java 8，或者被迫使用Java .util。日期，然后使用与输入字符串匹配的格式模式SimpleDateFormat格式化日期。
String string = "January 2, 2010";
DateFormat format = new SimpleDateFormat("MMMM d, yyyy", Locale.ENGLISH);
Date date = format.parse(string);
System.out.println(date); // Sat Jan 02 00:00:00 GMT 2010
注意显式Locale参数的重要性。如果省略它，那么它将使用默认的语言环境，而不一定是输入字符串的月份名中使用的英语。如果区域设置与输入字符串不匹配，那么即使格式模式看起来有效，您也会混淆地得到java.text.ParseException。
下面是javadoc的相关摘录，列出了所有可用的格式模式:
| Letter | Date or Time Component | Presentation | Examples |
|---|---|---|---|
G |
Era designator | Text | AD |
y |
Year | Year | 1996; 96 |
Y |
Week year | Year | 2009; 09 |
M/L |
Month in year | Month | July; Jul; 07 |
w |
Week in year | Number | 27 |
W |
Week in month | Number | 2 |
D |
Day in year | Number | 189 |
d |
Day in month | Number | 10 |
F |
Day of week in month | Number | 2 |
E |
Day in week | Text | Tuesday; Tue |
u |
Day number of week | Number | 1 |
a |
Am/pm marker | Text | PM |
H |
Hour in day (0-23) | Number | 0 |
k |
Hour in day (1-24) | Number | 24 |
K |
Hour in am/pm (0-11) | Number | 0 |
h |
Hour in am/pm (1-12) | Number | 12 |
m |
Minute in hour | Number | 30 |
s |
Second in minute | Number | 55 |
S |
Millisecond | Number | 978 |
z |
Time zone | General time zone | Pacific Standard Time; PST; GMT-08:00 |
Z |
Time zone | RFC 822 time zone | -0800 |
X |
Time zone | ISO 8601 time zone | -08; -0800; -08:00 |
注意，这些模式是区分大小写的，基于文本的四个字符或更多的模式表示完整的形式;否则，如果可能，则使用简短或缩写形式。所以，MMMMM或更多是不必要的。
下面是一些有效的SimpleDateFormat模式的例子，用于解析给定字符串的日期:
| Input string | Pattern |
|---|---|
| 2001.07.04 AD at 12:08:56 PDT | yyyy.MM.dd G 'at' HH:mm:ss z |
| Wed, Jul 4, '01 | EEE, MMM d, ''yy |
| 12:08 PM | h:mm a |
| 12 o'clock PM, Pacific Daylight Time | hh 'o''clock' a, zzzz |
| 0:08 PM, PDT | K:mm a, z |
| 02001.July.04 AD 12:08 PM | yyyyy.MMMM.dd GGG hh:mm aaa |
| Wed, 4 Jul 2001 12:08:56 -0700 | EEE, d MMM yyyy HH:mm:ss Z |
| 010704120856-0700 | yyMMddHHmmssZ |
| 2001-07-04T12:08:56.235-0700 | yyyy-MM-dd'T'HH:mm:ss.SSSZ |
| 2001-07-04T12:08:56.235-07:00 | yyyy-MM-dd'T'HH:mm:ss.SSSXXX |
| 2001-W27-3 | YYYY-'W'ww-u |
重要的一点是，SimpleDateFormat不是线程安全的。换句话说，永远不要将它声明为静态变量或实例变量并将其赋值，然后从不同的方法/线程重用它。您应该始终在方法的局部范围内创建全新的方法。
您可以使用SimpleDateformat更改日期字符串
sdf = new SimpleDateFormat("yyyy-MM-dd"); String strDate = "2000-01-01"; Date Date = sdf.parse(strDate);
在Java 8中，我们获得了一个新的日期/时间API (JSR 310)。
下面的方法可以用来解析Java 8中的日期而不依赖于Joda-Time:
String str = "January 2nd, 2010";
// if we 2nd even we have changed in pattern also it is not working please workout with 2nd
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM Q, yyyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse(str, formatter);
// access date fields
int year = date.getYear(); // 2010
int day = date.getDayOfMonth(); // 2
Month month = date.getMonth(); // JANUARY
int monthAsInt = month.getValue(); // 1
LocalDate是表示日期(没有时间)的标准Java 8类。如果要解析包含日期和时间信息的值，则应该使用LocalDateTime。对于带时区的值，请使用ZonedDateTime。两者都提供了类似于LocalDate的parse()方法:
LocalDateTime dateWithTime = LocalDateTime.parse(strWithDateAndTime, dateTimeFormatter);
ZonedDateTime zoned = ZonedDateTime.parse(strWithTimeZone, zoneFormatter);
DateTimeFormatter Javadoc中的格式化字符列表:
All letters 'A' to 'Z' and 'a' to 'z' are reserved as pattern letters.
The following pattern letters are defined:
Symbol Meaning Presentation Examples
------ ------- ------------ -------
G era text AD; Anno Domini; A
u year year 2004; 04
y year-of-era year 2004; 04
D day-of-year number 189
M/L month-of-year number/text 7; 07; Jul; July; J
d day-of-month number 10
Q/q quarter-of-year number/text 3; 03; Q3; 3rd quarter
Y week-based-year year 1996; 96
w week-of-week-based-year number 27
W week-of-month number 4
E day-of-week text Tue; Tuesday; T
e/c localized day-of-week number/text 2; 02; Tue; Tuesday; T
F week-of-month number 3
a am-pm-of-day text PM
h clock-hour-of-am-pm (1-12) number 12
K hour-of-am-pm (0-11) number 0
k clock-hour-of-am-pm (1-24) number 0
H hour-of-day (0-23) number 0
m minute-of-hour number 30
s second-of-minute number 55
S fraction-of-second fraction 978
A milli-of-day number 1234
n nano-of-second number 987654321
N nano-of-day number 1234000000
V time-zone ID zone-id America/Los_Angeles; Z; -08:30
z time-zone name zone-name Pacific Standard Time; PST
O localized zone-offset offset-O GMT+8; GMT+08:00; UTC-08:00;
X zone-offset 'Z' for zero offset-X Z; -08; -0830; -08:30; -083015; -08:30:15;
x zone-offset offset-x +0000; -08; -0830; -08:30; -083015; -08:30:15;
Z zone-offset offset-Z +0000; -0800; -08:00;
我简陋的测试程序。我用它来摆弄格式化程序，查找我在日志文件中找到的长日期(但是谁把它们放在那里了……)
我的测试程序:
package be.test.package.time;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import java.util.TimeZone;
public class TimeWork {
public static void main(String[] args) {
TimeZone timezone = TimeZone.getTimeZone("UTC");
List<Long> longs = new ArrayList<>();
List<String> strings = new ArrayList<>();
//Formatting a date needs a timezone - otherwise the date get formatted to your system time zone.
//Use 24h format HH. In 12h format hh can be in range 0-11, which makes 12 overflow to 0.
DateFormat formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss.SSS");
formatter.setTimeZone(timezone);
Date now = new Date();
//Test dates
strings.add(formatter.format(now));
strings.add("01-01-1970 00:00:00.000");
strings.add("01-01-1970 00:00:01.000");
strings.add("01-01-1970 00:01:00.000");
strings.add("01-01-1970 01:00:00.000");
strings.add("01-01-1970 10:00:00.000");
strings.add("01-01-1970 12:00:00.000");
strings.add("01-01-1970 24:00:00.000");
strings.add("02-01-1970 00:00:00.000");
strings.add("01-01-1971 00:00:00.000");
strings.add("01-01-2014 00:00:00.000");
strings.add("31-12-1969 23:59:59.000");
strings.add("31-12-1969 23:59:00.000");
strings.add("31-12-1969 23:00:00.000");
//Test data
longs.add(now.getTime());
longs.add(-1L);
longs.add(0L); //Long date presentation at - midnight 1/1/1970 UTC - The timezone is important!
longs.add(1L);
longs.add(1000L);
longs.add(60000L);
longs.add(3600000L);
longs.add(36000000L);
longs.add(43200000L);
longs.add(86400000L);
longs.add(31536000000L);
longs.add(1388534400000L);
longs.add(7260000L);
longs.add(1417706084037L);
longs.add(-7260000L);
System.out.println("===== String to long =====");
//Show the long value of the date
for (String string: strings) {
try {
Date date = formatter.parse(string);
System.out.println("Formated date : " + string + " = Long = " + date.getTime());
} catch (ParseException e) {
e.printStackTrace();
}
}
System.out.println("===== Long to String =====");
//Show the date behind the long
for (Long lo : longs) {
Date date = new Date(lo);
String string = formatter.format(date);
System.out.println("Formated date : " + string + " = Long = " + lo);
}
}
}
测试结果:
===== String to long =====
Formated date : 05-12-2014 10:17:34.873 = Long = 1417774654873
Formated date : 01-01-1970 00:00:00.000 = Long = 0
Formated date : 01-01-1970 00:00:01.000 = Long = 1000
Formated date : 01-01-1970 00:01:00.000 = Long = 60000
Formated date : 01-01-1970 01:00:00.000 = Long = 3600000
Formated date : 01-01-1970 10:00:00.000 = Long = 36000000
Formated date : 01-01-1970 12:00:00.000 = Long = 43200000
Formated date : 01-01-1970 24:00:00.000 = Long = 86400000
Formated date : 02-01-1970 00:00:00.000 = Long = 86400000
Formated date : 01-01-1971 00:00:00.000 = Long = 31536000000
Formated date : 01-01-2014 00:00:00.000 = Long = 1388534400000
Formated date : 31-12-1969 23:59:59.000 = Long = -1000
Formated date : 31-12-1969 23:59:00.000 = Long = -60000
Formated date : 31-12-1969 23:00:00.000 = Long = -3600000
===== Long to String =====
Formated date : 05-12-2014 10:17:34.873 = Long = 1417774654873
Formated date : 31-12-1969 23:59:59.999 = Long = -1
Formated date : 01-01-1970 00:00:00.000 = Long = 0
Formated date : 01-01-1970 00:00:00.001 = Long = 1
Formated date : 01-01-1970 00:00:01.000 = Long = 1000
Formated date : 01-01-1970 00:01:00.000 = Long = 60000
Formated date : 01-01-1970 01:00:00.000 = Long = 3600000
Formated date : 01-01-1970 10:00:00.000 = Long = 36000000
Formated date : 01-01-1970 12:00:00.000 = Long = 43200000
Formated date : 02-01-1970 00:00:00.000 = Long = 86400000
Formated date : 01-01-1971 00:00:00.000 = Long = 31536000000
Formated date : 01-01-2014 00:00:00.000 = Long = 1388534400000
Formated date : 01-01-1970 02:01:00.000 = Long = 7260000
Formated date : 04-12-2014 15:14:44.037 = Long = 1417706084037
Formated date : 31-12-1969 21:59:00.000 = Long = -7260000
我致力于将String解析为LocalDateTime。我把它留在这里作为例子
LocalDateTime d = LocalDateTime.parse("20180805 101010", DateTimeFormatter.ofPattern("yyyyMMdd HHmmss"));
我得到了
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