什么是最好的方法转换格式的字符串' 1月2日,2010年'到一个日期在Java?
最后,我希望将月、日和年分解为整数,以便我可以使用
Date date = new Date();
date.setMonth()..
date.setYear()..
date.setDay()..
date.setlong currentTime = date.getTime();
将日期转换为时间。
什么是最好的方法转换格式的字符串' 1月2日,2010年'到一个日期在Java?
最后,我希望将月、日和年分解为整数,以便我可以使用
Date date = new Date();
date.setMonth()..
date.setYear()..
date.setDay()..
date.setlong currentTime = date.getTime();
将日期转换为时间。
当前回答
此外,SimpleDateFormat对于某些客户端技术(如GWT)是不可用的。
使用Calendar.getInstance()是个好主意,您的要求是比较两个日期;长时间约会。
其他回答
在Java 8中,我们获得了一个新的日期/时间API (JSR 310)。
下面的方法可以用来解析Java 8中的日期而不依赖于Joda-Time:
String str = "January 2nd, 2010";
// if we 2nd even we have changed in pattern also it is not working please workout with 2nd
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM Q, yyyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse(str, formatter);
// access date fields
int year = date.getYear(); // 2010
int day = date.getDayOfMonth(); // 2
Month month = date.getMonth(); // JANUARY
int monthAsInt = month.getValue(); // 1
LocalDate是表示日期(没有时间)的标准Java 8类。如果要解析包含日期和时间信息的值,则应该使用LocalDateTime。对于带时区的值,请使用ZonedDateTime。两者都提供了类似于LocalDate的parse()方法:
LocalDateTime dateWithTime = LocalDateTime.parse(strWithDateAndTime, dateTimeFormatter);
ZonedDateTime zoned = ZonedDateTime.parse(strWithTimeZone, zoneFormatter);
DateTimeFormatter Javadoc中的格式化字符列表:
All letters 'A' to 'Z' and 'a' to 'z' are reserved as pattern letters.
The following pattern letters are defined:
Symbol Meaning Presentation Examples
------ ------- ------------ -------
G era text AD; Anno Domini; A
u year year 2004; 04
y year-of-era year 2004; 04
D day-of-year number 189
M/L month-of-year number/text 7; 07; Jul; July; J
d day-of-month number 10
Q/q quarter-of-year number/text 3; 03; Q3; 3rd quarter
Y week-based-year year 1996; 96
w week-of-week-based-year number 27
W week-of-month number 4
E day-of-week text Tue; Tuesday; T
e/c localized day-of-week number/text 2; 02; Tue; Tuesday; T
F week-of-month number 3
a am-pm-of-day text PM
h clock-hour-of-am-pm (1-12) number 12
K hour-of-am-pm (0-11) number 0
k clock-hour-of-am-pm (1-24) number 0
H hour-of-day (0-23) number 0
m minute-of-hour number 30
s second-of-minute number 55
S fraction-of-second fraction 978
A milli-of-day number 1234
n nano-of-second number 987654321
N nano-of-day number 1234000000
V time-zone ID zone-id America/Los_Angeles; Z; -08:30
z time-zone name zone-name Pacific Standard Time; PST
O localized zone-offset offset-O GMT+8; GMT+08:00; UTC-08:00;
X zone-offset 'Z' for zero offset-X Z; -08; -0830; -08:30; -083015; -08:30:15;
x zone-offset offset-x +0000; -08; -0830; -08:30; -083015; -08:30:15;
Z zone-offset offset-Z +0000; -0800; -08:00;
试试这个
String date = get_pump_data.getString("bond_end_date");
DateFormat format = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date datee = (Date)format.parse(date);
您可以使用SimpleDateformat更改日期字符串
sdf = new SimpleDateFormat("yyyy-MM-dd"); String strDate = "2000-01-01"; Date Date = sdf.parse(strDate);
来源链接
为安卓
.getTime Calendar.getInstance () ()
Thu Jul 26 15:54:13 GMT+05:30 2018
Use
String oldDate = "Thu Jul 26 15:54:13 GMT+05:30 2018";
DateFormat format = new SimpleDateFormat("EEE LLL dd HH:mm:ss Z yyyy");
Date updateLast = format.parse(oldDate);
此外,SimpleDateFormat对于某些客户端技术(如GWT)是不可用的。
使用Calendar.getInstance()是个好主意,您的要求是比较两个日期;长时间约会。