我的Angular代码出了什么问题?我得到以下错误:

无法读取BrowserDomAdapter.removeClass中未定义的属性“remove”

<ol>
  <li *ngClass="{active: step==='step1'}" (click)="step='step1'">Step1</li>
  <li *ngClass="{active: step==='step2'}" (click)="step='step2'">Step2</li>
  <li *ngClass="{active: step==='step3'}" (click)="step='step3'">Step3</li>
</ol>

当前回答

可以使用以下语法使类成为动态的。在Angular 2 plus中,你可以通过多种方式做到这一点:

[ngClass]="{'active': arrayData.length && arrayData[0]?.booleanProperty}"
[ngClass]="{'active': step}"
[ngClass]="step== 'step1'?'active':''"
[ngClass]="step? 'active' : ''"

其他回答

Angular version 2+提供了几种有条件地添加类的方法:

1型

    [class.my_class] = "step === 'step1'"

两个类型

    [ngClass]="{'my_class': step === 'step1'}"

并有多种选择:

    [ngClass]="{'my_class': step === 'step1', 'my_class2' : step === 'step2' }"

三个类型

    [ngClass]="{1 : 'my_class1', 2 : 'my_class2', 3 : 'my_class4'}[step]"

四个类型

    [ngClass]="step == 'step1' ? 'my_class1' : 'my_class2'"

您可以在文档页上找到这些示例

该指令有三种不同的操作方式,这取决于表达式的计算结果是三种类型中的哪一种:

If the expression evaluates to a string, the string should be one or more space-delimited class names. If the expression evaluates to an object, then for each key-value pair of the object with a truthy value the corresponding key is used as a class name. If the expression evaluates to an array, each element of the array should either be a string as in type 1 or an object as in type 2. This means that you can mix strings and objects together in an array to give you more control over what CSS classes appear. See the code below for an example of this.

    [class.class_one] = "step === 'step1'"

    [ngClass]="{'class_one': step === 'step1'}"

对于多个选项:

    [ngClass]="{'class_one': step === 'step1', 'class_two' : step === 'step2' }" 

    [ngClass]="{1 : 'class_one', 2 : 'class_two', 3 : 'class_three'}[step]"

    [ngClass]="step == 'step1' ? 'class_one' : 'class_two'"

Angular提供了多种有条件地添加类的方法:

第一个方法

Active是您的类名

[class.active]="step === 'step1'"

第二种方式

Active是您的类名

[ngClass]="{'active': step=='step1'}"

第三条道路

通过使用三元运算符class1和class2是你的类名

[ngClass]="(step=='step1')?'class1':'class2'"

这对我来说很管用:

[ngClass]="{'active': dashboardComponent.selected_menu == 'profile'}"

这个例子有点大,但是触发一个类而不是输入内联是我首选的方法。 通过这种方式,您可以在元素中添加尽可能多的可能性。 对于那些想要将多个[ngClass]绑定到单个元素的人来说,可能有一种方法。

<span class="inline-flex items-center font-medium" [ngClass]="addClass">{{ badge.text }}</span>

import { ChangeDetectionStrategy, Component, Input } from '@angular/core';

type Badge = {
    size?: 'basic' | 'large';
    shape?: 'basic' | 'rounded';
    color?: 'gray' | 'red' | 'yellow' | 'green' | 'blue' | 'indigo' | 'purple' | 'pink';
    dot?: boolean;
    removeButton?: false;
    text?: string;
}

@Component({
    selector: 'bio-badge',
    templateUrl: './badge.component.html',
    styleUrls: ['./badge.component.scss'],
    changeDetection: ChangeDetectionStrategy.OnPush,
})
export class BioBadgeComponent {
    @Input() badge!: Badge;
    get addClass() {
        return {
            'px-2.5 py-0.5 text-sx': this.badge.size === 'basic',
            'px-3 py-0.5 text-sm': this.badge.size === 'large',
            'rounded-full': this.badge.shape === 'basic',
            'rounded': this.badge.shape === 'rounded',
            'bg-gray-100 text-gray-800': this.badge.color === 'gray',
            'bg-red-100 text-red-800': this.badge.color === 'red',
            'bg-yellow-100 text-yellow-800': this.badge.color === 'yellow',
            'bg-green-100 text-green-800': this.badge.color === 'green',
            'bg-blue-100 text-blue-800': this.badge.color === 'blue',
            'bg-indigo-100 text-indigo-800': this.badge.color === 'indigo',
            'bg-purple-100 text-purple-800': this.badge.color === 'purple',
            'bg-pink-100 text-pink-800': this.badge.color === 'pink',
        }
    }
}