如何检查给定的字符串是否是有效的URL地址?
我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。
如何检查给定的字符串是否是有效的URL地址?
我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。
当前回答
黑(http / \ /处事之道会(s) ?):地球,随便(www。)? a-zA-Z0-9 @:%._\+~#=]{ 地球,随便2,256出于美观。黑a-z铝可不,2、6出于美观\ b(黑-a-zA-Z0-9 @:%_\+.~#?&//=]*)
其他回答
我无法找到我正在寻找的正则表达式,所以我修改了一个正则表达式来满足我的要求,显然现在它似乎工作得很好。我的要求是:
匹配带有协议的url (www.gooogle.com) 使用查询参数和路径匹配url (http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e) 不要匹配有不可接受字符的url(例如。' '£),例如:(www.google.com/somthing"/somethingmore)
以下是我的想法,任何建议都很感激:
@Test
public void testWebsiteUrl(){
String regularExpression = "((http|ftp|https):\\/\\/)?[\\w\\-_]+(\\.[\\w\\-_]+)+([\\w\\-\\.,@?^=%&:/~\\+#]*[\\w\\-\\@?^=%&/~\\+#])?";
assertTrue("www.google.com".matches(regularExpression));
assertTrue("www.google.co.uk".matches(regularExpression));
assertTrue("http://www.google.com".matches(regularExpression));
assertTrue("http://www.google.co.uk".matches(regularExpression));
assertTrue("https://www.google.com".matches(regularExpression));
assertTrue("https://www.google.co.uk".matches(regularExpression));
assertTrue("google.com".matches(regularExpression));
assertTrue("google.co.uk".matches(regularExpression));
assertTrue("google.mu".matches(regularExpression));
assertTrue("mes.intnet.mu".matches(regularExpression));
assertTrue("cse.uom.ac.mu".matches(regularExpression));
assertTrue("http://www.google.com/path".matches(regularExpression));
assertTrue("http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e".matches(regularExpression));
assertTrue("http://www.google.com/?queryparam=123".matches(regularExpression));
assertTrue("http://www.google.com/path?queryparam=123".matches(regularExpression));
assertFalse("www..dr.google".matches(regularExpression));
assertFalse("www:google.com".matches(regularExpression));
assertFalse("https://www@.google.com".matches(regularExpression));
assertFalse("https://www.google.com\"".matches(regularExpression));
assertFalse("https://www.google.com'".matches(regularExpression));
assertFalse("http://www.google.com/path'".matches(regularExpression));
assertFalse("http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e'".matches(regularExpression));
assertFalse("http://www.google.com/?queryparam=123'".matches(regularExpression));
assertFalse("http://www.google.com/path?queryparam=12'3".matches(regularExpression));
}
我创建了一个类似于RFC3987和其他RFC文档提供的@eyelidlessness的正则表达式(PCRE)。@eyelidlessness和我的正则表达式之间的主要区别主要是可读性和URN支持。
下面的正则表达式是一个整体(而不是与PHP混合),所以它可以很容易地用于不同的语言(只要它们支持PCRE)
测试这个正则表达式最简单的方法是使用regex101,并使用适当的修饰符(gmx)复制粘贴下面的代码和测试字符串。
要在PHP中使用这个正则表达式,请将下面的正则表达式插入到以下代码中:
$regex = <<<'EOD'
// Put the regex here
EOD;
可以通过以下方式匹配不带方案的链路: 要匹配一个没有方案的链接(例如john.doe@gmail.com或www.google.com/pathtofile.php?query),替换此部分:
(?:
(?<scheme>
(?<urn>urn)|
(?&d_scheme)
)
:
)?
用这个:
(?:
(?<scheme>
(?<urn>urn)|
(?&d_scheme)
)
:
)?
但是请注意,通过替换它,regex并不是100%可靠。 使用gmx修饰符的Regex (PCRE)用于下面的多行测试字符串
(?(DEFINE)
# Definitions
(?<ALPHA>[\p{L}])
(?<DIGIT>[0-9])
(?<HEX>[0-9a-fA-F])
(?<NCCHAR>
(?&UNRESERVED)|
(?&PCT_ENCODED)|
(?&SUB_DELIMS)|
@
)
(?<PCHAR>
(?&UNRESERVED)|
(?&PCT_ENCODED)|
(?&SUB_DELIMS)|
:|
@|
\/
)
(?<UCHAR>
(?&UNRESERVED)|
(?&PCT_ENCODED)|
(?&SUB_DELIMS)|
:
)
(?<RCHAR>
(?&UNRESERVED)|
(?&PCT_ENCODED)|
(?&SUB_DELIMS)
)
(?<PCT_ENCODED>%(?&HEX){2})
(?<UNRESERVED>
((?&ALPHA)|(?&DIGIT)|[-._~])
)
(?<RESERVED>(?&GEN_DELIMS)|(?&SUB_DELIMS))
(?<GEN_DELIMS>[:\/?#\[\]@])
(?<SUB_DELIMS>[!$&'()*+,;=])
# URI Parts
(?<d_scheme>
(?!urn)
(?:
(?&ALPHA)
((?&ALPHA)|(?&DIGIT)|[+-.])*
(?=:)
)
)
(?<d_hier_part_slashes>
(\/{2})?
)
(?<d_authority>(?&d_userinfo)?)
(?<d_userinfo>(?&UCHAR)*)
(?<d_ipv6>
(?![^:]*::[^:]*::[^:]*)
(
(
((?&HEX){0,4})
:
){1,7}
((?&d_ipv4)|:|(?&HEX){1,4})
)
)
(?<d_ipv4>
((?&octet)\.){3}
(?&octet)
)
(?<octet>
(
25[]0-5]|
2[0-4](?&DIGIT)|
1(?&DIGIT){2}|
[1-9](?&DIGIT)|
(?&DIGIT)
)
)
(?<d_reg_name>(?&RCHAR)*)
(?<d_urn_name>(?&UCHAR)*)
(?<d_port>(?&DIGIT)*)
(?<d_path>
(
\/
((?&PCHAR)*)*
(?=\?|\#|$)
)
)
(?<d_query>
(
((?&PCHAR)|\/|\?)*
)?
)
(?<d_fragment>
(
((?&PCHAR)|\/|\?)*
)?
)
)
^
(?<link>
(?:
(?<scheme>
(?<urn>urn)|
(?&d_scheme)
)
:
)
(?(urn)
(?:
(?<namespace_identifier>[0-9a-zA-Z\-]+)
:
(?<namespace_specific_string>(?&d_urn_name)+)
)
|
(?<hier_part>
(?<slashes>(?&d_hier_part_slashes))
(?<authority>
(?:
(?<userinfo>(?&d_authority))
@
)?
(?<host>
(?<ipv4>\[?(?&d_ipv4)\]?)|
(?<ipv6>\[(?&d_ipv6)\])|
(?<domain>(?&d_reg_name))
)
(?:
:
(?<port>(?&d_port))
)?
)
(?<path>(?&d_path))?
)
(?:
\?
(?<query>(?&d_query))
)?
(?:
\#
(?<fragment>(?&d_fragment))
)?
)
)
$
测试字符串
# Valid URIs
ftp://cnn.example.com&story=breaking_news@10.0.0.1/top_story.htm
ftp://ftp.is.co.za/rfc/rfc1808.txt
http://www.ietf.org/rfc/rfc2396.txt
ldap://[2001:db8::7]/c=GB?objectClass?one
mailto:John.Doe@example.com
news:comp.infosystems.www.servers.unix
tel:+1-816-555-1212
telnet://192.0.2.16:80/
urn:isbn:0451450523
urn:oid:2.16.840
urn:isan:0000-0000-9E59-0000-O-0000-0000-2
urn:oasis:names:specification:docbook:dtd:xml:4.1.2
http://localhost/test/somefile.php?query=someval&variable=value#fragment
http://[2001:db8:a0b:12f0::1]/test
ftp://username:password@domain.com/path/to/file/somefile.html?queryVariable=value#fragment
https://subdomain.domain.com/path/to/file.php?query=value#fragment
https://subdomain.example.com/path/to/file.php?query=value#fragment
mailto:john.smith(comment)@example.com
mailto:user@[2001:DB8::1]
mailto:user@[255:192:168:1]
mailto:M.Handley@cs.ucl.ac.uk
http://localhost:4433/path/to/file?query#fragment
# Note that the example below IS a valid as it does follow RFC standards
localhost:4433/path/to/file
# These work with the optional scheme group although I'd suggest making the scheme mandatory as misinterpretations can occur
john.doe@gmail.com
www.google.com/pathtofile.php?query
[192a:123::192.168.1.1]:80/path/to/file.html?query#fragment
有趣的是,上面的答案都不能满足我的需要,所以我想我可以提供我的解决方案。我需要做到以下几点:
匹配http(s)://www.google.com, http://google.com, www.google.com和google.com 匹配Github降价风格的链接,如[谷歌](http://www.google.com) 匹配所有可能的域名扩展名,比如。com,或。io,或。guru等。基本上长度在2-6个字符之间 将所有内容分成适当的组,以便我可以根据需要访问每个部分。
解决办法是这样的:
/^(\[[A-z0-9 _]*\]\()?((?:(http|https):\/\/)?(?:[\w-]+\.)+[a-z]{2,6})(\))?$
这就满足了上述所有要求。如果需要,你可以选择添加ftp和file功能:
/^(\[[A-z0-9 _]*\]\()?((?:(http|https|ftp|file):\/\/)?(?:[\w-]+\.)+[a-z]{2,6})(\))?$
最佳正则表达式是这里最佳答案的组合!哈哈哈!我刚刚测试了它们,并把最好的放在一起!我稍微改变了一下,只有一个捕获组!我在这个页面的源代码中找到了637个url !只有几个假阳性!
((?:(?:https?|ftp)://)(?:\S+(?::\S*)?@|\d{1,3}(?:\.\d{1,3}){3}|(?:(?:[a-z\d\x{00a1}-\x{ffff}]+-?)*[a-z\d\x{00a1}-\x{ffff}]+)(?:\.(?:[a-z\d\x{00a1}-\x{ffff}]+-?)*[a-z\d\x{00a1}-\x{ffff}]+)*(?:\.[a-z\x{00a1}-\x{ffff}]{2,6}))(?::\d+)?(?:[^\s]*)|(?:(?:(?:[A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+(?::[0-9]+)?|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)(?:(?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[\w]*))?)|(?:(?:(?:(?:[A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)(?:(?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[\w]*))?))|(?:(?:(?:[\\w]+:)?//)?(?:(?:[\\d\\w]|%[a-fA-f\\d]{2,2})+(?::(?:[\\d\\w]|%[a-fA-f\\d]{2,2})+)?@)?(?:[\\d\\w][-\\d\\w]{0,253}[\\d\\w]\\.)+[\\w]{2,4}(?::[\\d]+)?(?:/(?:[-+_~.\\d\\w]|%[a-fA-f\\d]{2,2})*)*(?:\\?(?:&?(?:[-+_~.\\d\\w]|%[a-fA-f\\d]{2,2})=?)*)?(?:#(?:[-+_~.\\d\\w]|%[a-fA-f\\d]{2,2})*)?)|(?:https?:\/\/(?:[a-z0-9](?:[a-z0-9-]{0,61}[a-z0-9])?\.)+[a-z0-9][a-z0-9-]{0,61}[a-z0-9])(?::?\d*)\/?(?:[a-z_\/0-9\-#.]*)\??(?:[a-z_\/0-9\-#=&]*)|(?:(?:(?:https?:)?(?:\/?\/))(?:(?:[\d\w]|%[a-fA-f\d]{2,2})+(?::(?:[\d\w]|%[a-fA-f\d]{2,2})+)?@)?(?:[\d\w][-\d\w]{0,253}[\d\w]\.)+[\w]{2,63}(?::[\d]+)?(?:/(?:[-+_~.\d\w]|%[a-fA-f\d]{2,2})*)*(?:\?(?:&?(?:[-+_~.\d\w]|%[a-fA-f\d]{2,2})=?)*)?(?:#(?:[-+_~.\d\w]|%[a-fA-f\d]{2,2})*)?)|(?:(?:https?|ftp)://(?:www\d?|[a-zA-Z0-9]+)?\.[a-zA-Z0-9-]+(?:\:|\.)(?:[a-zA-Z0-9.]+|(?:\d+)?)(?:[/?:].*)?)|(?:\b(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{00a1}-\x{ffff}]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?\b))
我刚刚写了一篇博客文章,介绍了一个很好的解决方案,可以识别大多数常用格式的url,比如:
www.google.com http://www.google.com mailto: somebody@google.com somebody@google.com url www.url-with-querystring.com/ ? = has-querystring
使用的正则表达式是:
/((([A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)((?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[\w]*))?)/