如何检查给定的字符串是否是有效的URL地址?

我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。


当前回答

用这个吧,它对我有用

function validUrl(Url) {
    var myRegExp  =/^(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$/i;

    if (!RegExp.test(Url.value)) {
        $("#urlErrorLbl").removeClass('highlightNew');
        return false;
    } 

    $("#urlErrorLbl").addClass('highlightNew'); 
    return true; 
}

其他回答

下面的RegEx可以工作:

"@((((ht)|(f))tp[s]?://)|(www\.))([a-z][-a-z0-9]+\.)?([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+[/]?[a-z0-9._\/~#&=;%+?-]*@si"
        function validateURL(textval) {
            var urlregex = new RegExp(
            "^(http|https|ftp)\://([a-zA-Z0-9\.\-]+(\:[a-zA-Z0-9\.&%\$\-]+)*@)*((25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9])\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[0-9])|localhost|([a-zA-Z0-9\-]+\.)*[a-zA-Z0-9\-]+\.(com|edu|gov|int|mil|net|org|biz|arpa|info|name|pro|aero|coop|museum|[a-zA-Z]{2}))(\:[0-9]+)*(/($|[a-zA-Z0-9\.\,\?\'\\\+&%\$#\=~_\-]+))*$");
            return urlregex.test(textval);
        }

匹配 http://site.com/dir/file.php?var=moo | ftp://user:pass@site.com:21/file/dir

Non-Matches site。com | http://site.com/dir//

Regardless the broad question asked, I post this for anyone in the future who is looking for something simple... as I think validating a URL has no perfect regular expression that fit all needs, it depends on your requirements, i.e: in my case, I just needed to verify if a URL is in the form of domain.extension and I wanted to allow the www or any other subdomain like blog.domain.extension I don't care about http(s) as in my app I have a field which says "enter the URL" so it's obvious what that entered string is.

这是regEx:

/^(www\.|[a-zA-Z0-9](.*[a-zA-Z0-9])?\.)?((?!www)[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9])\.[a-z]{2,5}(:[0-9]{1,5})?$/i

这个regExp中的第一个块是:

(www \ | [a-zA-Z0-9] (. * [a-zA-Z0-9]) ? \。)?——>我们开始检查URL是否以www开头。[a-zA-Z0-9]或[a-zA-Z0-9] (. *) ?这意味着一个字母或数字+ (anyCharacter(0或多次)+另一个字母或数字),然后是一个点

注意(.*[a-zA-Z0-9])?\.)?我们翻译由(anyCharacter(0或多次)+另一个字母或数字) 是可选的(可以是或不是)这就是为什么我们将它分组在括号之间,后面跟着问号?

到目前为止我们讨论的整个块也放在括号之间,后面跟着?这意味着WWW或任何其他词(表示子域)都是可选的。

第二部分是:((? ! www) [a-zA-Z0-9] [a-zA-Z0-9 -] + [a-zA-Z0-9]) \。——>表示“域”部分,它可以是任何单词(www除外),以字母或数字开头+任何其他字母(包括破折号“-”)重复一次或多次,以任何字母或数字结尾,后面跟一个点。

最后一部分是[a-z]{2,}——>,它代表“扩展名”,它可以是任何字母重复2次或更多次,所以它可以是com, net, org, art基本上任何扩展名

关于眼睑问题,他的回答是“这是基于我对URI规范的阅读。”谢谢眼睑,你的是我寻求的完美的解决方案,因为它是基于URI规范!出色的工作。:)

我不得不做了两个修改。第一个在PHP (v5.2.10)中使用preg_match()函数使regexp正确匹配IP地址url的方法。

我不得不在管道周围的“IP Address”上方的行中添加一组括号:

)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#

不知道为什么。

我还将顶级域名的最小长度从3个字母减少到2个字母,以支持.co。英国和类似国家。

最后的代码:

/^(https?|ftp):\/\/(?#                                      protocol
)(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+(?#         username
)(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?(?#      password
)@)?(?#                                                     auth requires @
)((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*(?#             domain segments AND
)[a-z][a-z0-9-]*[a-z0-9](?#                                 top level domain  OR
)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#
    )(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])(?#             IP address
))(:\d+)?(?#                                                port
))(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*(?# path
)(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)(?#      query string
)?)?)?(?#                                                   path and query string optional
)(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?(?#      fragment
)$/i

这个修改后的版本没有根据URI规范进行检查,所以我不能保证它的合规性,它被修改为处理本地网络环境中的URL和两位tld以及其他类型的Web URL,并在我使用的PHP设置中更好地工作。

作为PHP代码:

define('URL_FORMAT', 
'/^(https?):\/\/'.                                         // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'.         // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'.      // password
'@)?(?#'.                                                  // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'.                      // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'.                                 // top level domain  OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'.                 // IP address
')(:\d+)?'.                                                // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'.      // query string
'?)?)?'.                                                   // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'.      // fragment
'$/i');

下面是一个PHP测试程序,它使用正则表达式验证各种url:

<?php

define('URL_FORMAT',
'/^(https?):\/\/'.                                         // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'.         // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'.      // password
'@)?(?#'.                                                  // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'.                      // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'.                                 // top level domain  OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'.                 // IP address
')(:\d+)?'.                                                // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'.      // query string
'?)?)?'.                                                   // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'.      // fragment
'$/i');

/**
 * Verify the syntax of the given URL. 
 * 
 * @access public
 * @param $url The URL to verify.
 * @return boolean
 */
function is_valid_url($url) {
  if (str_starts_with(strtolower($url), 'http://localhost')) {
    return true;
  }
  return preg_match(URL_FORMAT, $url);
}


/**
 * String starts with something
 * 
 * This function will return true only if input string starts with
 * niddle
 * 
 * @param string $string Input string
 * @param string $niddle Needle string
 * @return boolean
 */
function str_starts_with($string, $niddle) {
      return substr($string, 0, strlen($niddle)) == $niddle;
}


/**
 * Test a URL for validity and count results.
 * @param url url
 * @param expected expected result (true or false)
 */

$numtests = 0;
$passed = 0;

function test_url($url, $expected) {
  global $numtests, $passed;
  $numtests++;
  $valid = is_valid_url($url);
  echo "URL Valid?: " . ($valid?"yes":"no") . " for URL: $url. Expected: ".($expected?"yes":"no").". ";
  if($valid == $expected) {
    echo "PASS\n"; $passed++;
  } else {
    echo "FAIL\n";
  }
}

echo "URL Tests:\n\n";

test_url("http://localserver/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("http://www.google.com", true);
test_url("http://www.google.co.uk/projects/my%20folder/test.php", true);
test_url("https://myserver.localdomain", true);
test_url("http://192.168.1.120/projects/index.php", true);
test_url("http://192.168.1.1/projects/index.php", true);
test_url("http://projectpier-server.localdomain/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("https://2.4.168.19/project-pier?c=test&a=b", true);
test_url("https://localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);
test_url("http://user:password@localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);

echo "\n$passed out of $numtests tests passed.\n\n";

?>

再次感谢regex的虚实!

https?:\/{2}(?:[\/-\w.]|(?:%[\da-fA-F]{2}))+

您可以使用此模式来检测url。

下面是概念的证明

RegExr: URL检测器