https?:\/{2}(?:[\/-\w.]|(?:%[\da-fA-F]{2}))+

您可以使用此模式来检测url。

下面是概念的证明

RegExr: URL检测器

关于眼睑问题，他的回答是“这是基于我对URI规范的阅读。”谢谢眼睑，你的是我寻求的完美的解决方案，因为它是基于URI规范!出色的工作。：）

我不得不做了两个修改。第一个在PHP (v5.2.10)中使用preg_match()函数使regexp正确匹配IP地址url的方法。

我不得不在管道周围的“IP Address”上方的行中添加一组括号:

)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#

不知道为什么。

我还将顶级域名的最小长度从3个字母减少到2个字母，以支持.co。英国和类似国家。

最后的代码:

/^(https?|ftp):\/\/(?#                                      protocol
)(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+(?#         username
)(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?(?#      password
)@)?(?#                                                     auth requires @
)((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*(?#             domain segments AND
)[a-z][a-z0-9-]*[a-z0-9](?#                                 top level domain  OR
)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#
    )(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])(?#             IP address
))(:\d+)?(?#                                                port
))(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*(?# path
)(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)(?#      query string
)?)?)?(?#                                                   path and query string optional
)(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?(?#      fragment
)$/i

这个修改后的版本没有根据URI规范进行检查，所以我不能保证它的合规性，它被修改为处理本地网络环境中的URL和两位tld以及其他类型的Web URL，并在我使用的PHP设置中更好地工作。

作为PHP代码:

define('URL_FORMAT', 
'/^(https?):\/\/'.                                         // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'.         // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'.      // password
'@)?(?#'.                                                  // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'.                      // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'.                                 // top level domain  OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'.                 // IP address
')(:\d+)?'.                                                // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'.      // query string
'?)?)?'.                                                   // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'.      // fragment
'$/i');

下面是一个PHP测试程序，它使用正则表达式验证各种url:

<?php

define('URL_FORMAT',
'/^(https?):\/\/'.                                         // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'.         // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'.      // password
'@)?(?#'.                                                  // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'.                      // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'.                                 // top level domain  OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'.                 // IP address
')(:\d+)?'.                                                // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'.      // query string
'?)?)?'.                                                   // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'.      // fragment
'$/i');

/**
 * Verify the syntax of the given URL. 
 * 
 * @access public
 * @param $url The URL to verify.
 * @return boolean
 */
function is_valid_url($url) {
  if (str_starts_with(strtolower($url), 'http://localhost')) {
    return true;
  }
  return preg_match(URL_FORMAT, $url);
}


/**
 * String starts with something
 * 
 * This function will return true only if input string starts with
 * niddle
 * 
 * @param string $string Input string
 * @param string $niddle Needle string
 * @return boolean
 */
function str_starts_with($string, $niddle) {
      return substr($string, 0, strlen($niddle)) == $niddle;
}


/**
 * Test a URL for validity and count results.
 * @param url url
 * @param expected expected result (true or false)
 */

$numtests = 0;
$passed = 0;

function test_url($url, $expected) {
  global $numtests, $passed;
  $numtests++;
  $valid = is_valid_url($url);
  echo "URL Valid?: " . ($valid?"yes":"no") . " for URL: $url. Expected: ".($expected?"yes":"no").". ";
  if($valid == $expected) {
    echo "PASS\n"; $passed++;
  } else {
    echo "FAIL\n";
  }
}

echo "URL Tests:\n\n";

test_url("http://localserver/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("http://www.google.com", true);
test_url("http://www.google.co.uk/projects/my%20folder/test.php", true);
test_url("https://myserver.localdomain", true);
test_url("http://192.168.1.120/projects/index.php", true);
test_url("http://192.168.1.1/projects/index.php", true);
test_url("http://projectpier-server.localdomain/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("https://2.4.168.19/project-pier?c=test&a=b", true);
test_url("https://localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);
test_url("http://user:password@localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);

echo "\n$passed out of $numtests tests passed.\n\n";

?>

再次感谢regex的虚实!

这应该可以工作:

函数validateUrl(价值){ 返回/ ^ (http (s )?:\/\/.)?( www \)。? [-a-zA-Z0-9 @:%._\+~#=]{ 2256} \ [a - z] {2,6} \ b ([-a-zA-Z0-9 @:%_\+.~#?&//=]*)$/ gi.test(价值); ｝ console.log (validateUrl (' google.com '));/ /正确的 console.log (validateUrl (' www.google.com '));/ /正确的 console.log (validateUrl (' http://www.google.com '));/ /正确的 console.log (validateUrl (http: / www.google.com));/ /错误 console.log (validateUrl (' www.google.com/test '));/ /正确的

下面的正则表达式适用于我:

(http(s)?:\/\/.)?(ftp(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9@:%._\+~#=]{0,256}\.[a-z] 
{2,6}\b([-a-zA-Z0-9@:%_\+.~#?&//=]*)

匹配:

https://google.com t.me https://t.me ftp://google.com http://sm.tj http://bro.tj t.me/rshss https:google.com www.cool.com.au http://www.cool.com.au http://www.cool.com.au/ersdfs http://www.cool.com.au/ersdfs?dfd=dfgd@s=1 http://www.cool.com:81/index.html

改进的

检测像这样的url:

https://www.example.pl http://www.example.com www.example.pl example.com http://blog.example.com http://www.example.com/product http://www.example.com/products?id=1&page=2 http://www.example.com#up http://255.255.255.255 255.255.255.255 http:// www.site.com: 8008

正则表达式:

/^(?:http(s)?:\/\/)?[\w.-]+(?:\.[\w\.-]+)+[\w\-\._~:/?#[\]@!\$&'\(\)\*\+,;=.]+$/gm

Javascript现在有一个名为new URL()的URL构造函数。它允许您完全跳过REGEX。

/** * * The URL() constructor returns a newly created URL object representing * the URL defined by the parameters. * * https://developer.mozilla.org/en-US/docs/Web/API/URL/URL * */ let requestUrl = new URL('https://username:password@developer.mozilla.org:8080/en-US/docs/search.html?par1=abc&par2=123&par3=true#Recent'); let urlParts = { origin: requestUrl.origin, href: requestUrl.href, protocol: requestUrl.protocol, username: requestUrl.username, password: requestUrl.password, host: requestUrl.host, hostname: requestUrl.hostname, port: requestUrl.port, pathname: requestUrl.pathname, search: requestUrl.search, searchParams: { par1: String(requestUrl.searchParams.get('par1')), par2: Number(requestUrl.searchParams.get('par2')), par3: Boolean(requestUrl.searchParams.get('par3')), }, hash: requestUrl.hash }; console.log(urlParts);