我有“我爱Suzi和Marry”,我想把“Suzi”改成“Sara”。
firstString="I love Suzi and Marry"
secondString="Sara"
预期的结果:
firstString="I love Sara and Marry"
我有“我爱Suzi和Marry”,我想把“Suzi”改成“Sara”。
firstString="I love Suzi and Marry"
secondString="Sara"
预期的结果:
firstString="I love Sara and Marry"
当前回答
这完全可以用bash字符串操作完成:
first="I love Suzy and Mary"
second="Sara"
first=${first/Suzy/$second}
这只会取代第一个事件;要将它们全部替换,请将第一个斜杠加倍:
first="Suzy, Suzy, Suzy"
second="Sara"
first=${first//Suzy/$second}
# first is now "Sara, Sara, Sara"
其他回答
使用AWK:
firstString="I love Suzi and Marry"
echo "$firstString" | awk '{gsub("Suzi","Sara"); print}'
试试这个:
ls *.ext | awk '{print "mv "$1" "$1".newext"}' | sed "s/.ext.newext/.newext/" | parallel {}
纯POSIX shell方法,与Roman Kazanovskyi基于sed的答案不同,它不需要外部工具,只需要shell自己的本地参数展开。注意,长文件名被最小化,所以代码更适合一行:
f="I love Suzi and Marry"
s=Sara
t=Suzi
[ "${f%$t*}" != "$f" ] && f="${f%$t*}$s${f#*$t}"
echo "$f"
输出:
I love Sara and Marry
工作原理:
Remove Smallest Suffix Pattern. "${f%$t*}" returns "I love" if the suffix $t "Suzi*" is in $f "I love Suzi and Marry". But if t=Zelda, then "${f%$t*}" deletes nothing, and returns the whole string "I love Suzi and Marry". This is used to test if $t is in $f with [ "${f%$t*}" != "$f" ] which will evaluate to true if the $f string contains "Suzi*" and false if not. If the test returns true, construct the desired string using Remove Smallest Suffix Pattern ${f%$t*} "I love" and Remove Smallest Prefix Pattern ${f#*$t} "and Marry", with the 2nd string $s "Sara" in between.
因为我不能添加评论。为了使示例更具可读性,可以这样写
full_string="I love Suzy and Mary"
search_string="Suzy"
replace_string="Sara"
my_string=${full_string/$search_string/$replace_string}
or
my_string=${full_string/Suzy/Sarah}
试试这个:
sed "s/Suzi/$secondString/g" <<<"$firstString"