使用switch语句的直通特性。匹配的case会一直运行，直到找到break(或者switch语句的结尾)，所以你可以这样写:

switch (varName)
{
   case "afshin":
   case "saeed":
   case "larry": 
       alert('Hey');
       break;

   default: 
       alert('Default case');
}

这在常规JavaScript中工作:

function theTest(val) {
  var answer = "";
  switch( val ) {
    case 1: case 2: case 3:
      answer = "Low";
      break;
    case 4: case 5: case 6:
      answer = "Mid";
      break;
    case 7: case 8: case 9:
      answer = "High";
      break;
    default:
      answer = "Massive or Tiny?";
  }
  return answer;
}

theTest(9);

在Node.js中，你可以这样做:

data = "10";
switch(data){
    case "1": case "2": case "3": // Put multiple cases on the same
                                  // line to save vertical space.
        console.log("small");
        break;

    case "10": case "11": case "12":
        console.log("large");
        break;

    default:
        console.log("strange");
        break;
}

这使得代码在某些情况下更加紧凑。

我是这样使用的:

switch (true){
     case /Pressure/.test(sensor): 
     {
        console.log('Its pressure!');
        break;
     }

     case /Temperature/.test(sensor): 
     {
        console.log('Its temperature!');
        break;
     }
}

上述方法的问题在于，每次调用具有开关的函数时，都必须重复上述几种情况。更可靠的解决方案是使用地图或字典。

这里有一个例子:

// The Map, divided by concepts var dictionary = { timePeriod: { 'month': [1, 'monthly', 'mensal', 'mês'], 'twoMonths': [2, 'two months', '2 months', 'bimestral', 'bimestre'], 'trimester': [3, 'trimesterly', 'quarterly', 'trimestral'], 'semester': [4, 'semesterly', 'semestral', 'halfyearly'], 'year': [5, 'yearly', 'annual', 'ano'] }, distance: { 'km': [1, 'kms', 'kilometre', 'kilometers', 'kilometres'], 'mile': [2, 'mi', 'miles'], 'nordicMile': [3, 'Nordic mile', 'mil (10 km)', 'Scandinavian mile'] }, fuelAmount: { 'ltr': [1, 'l', 'litre', 'Litre', 'liter', 'Liter'], 'gal (imp)': [2, 'imp gallon', 'imperial gal', 'gal (UK)'], 'gal (US)': [3, 'US gallon', 'US gal'], 'kWh': [4, 'KWH'] } }; // This function maps every input to a certain defined value function mapUnit (concept, value) { for (var key in dictionary[concept]) { if (key === value || dictionary[concept][key].indexOf(value) !== -1) { return key } } throw Error('Uknown "'+value+'" for "'+concept+'"') } // You would use it simply like this mapUnit("fuelAmount", "ltr") // => ltr mapUnit("fuelAmount", "US gal") // => gal (US) mapUnit("fuelAmount", 3) // => gal (US) mapUnit("distance", "kilometre") // => km // Now you can use the switch statement safely without the need // to repeat the combinations every time you call the switch var foo = 'monthly' switch (mapUnit ('timePeriod', foo)) { case 'month': console.log('month') break case 'twoMonths': console.log('twoMonths') break case 'trimester': console.log('trimester') break case 'semester': console.log('semester') break case 'year': console.log('year') break default: throw Error('error') }

一些有趣的方法。对我来说，最好的解决方法是使用。find。

通过在find函数中使用合适的名称，可以指示多个情况是什么。

switch (varName)
{
   case ["afshin", "saeed", "larry"].find(firstName => firstName === varName):
       alert('Hey');
       break;

   default:
       alert('Default case');
       break;
}

其他答案更适合给定的例子，但如果你有多种情况，对我来说，这是最好的方法。