我有一个大对象要转换成JSON并发送。然而,它具有圆形结构。我想丢弃任何存在的循环引用,并发送任何可以字符串化的引用。我该怎么做?

谢谢

var obj = {
  a: "foo",
  b: obj
}

我想将对象字符串化为:

{"a":"foo"}

当前回答

使用带有自定义替换符的JSON.stringify。例如:

// Demo: Circular reference
var circ = {};
circ.circ = circ;

// Note: cache should not be re-used by repeated calls to JSON.stringify.
var cache = [];
JSON.stringify(circ, (key, value) => {
  if (typeof value === 'object' && value !== null) {
    // Duplicate reference found, discard key
    if (cache.includes(value)) return;

    // Store value in our collection
    cache.push(value);
  }
  return value;
});
cache = null; // Enable garbage collection

本例中的替换符并非100%正确(取决于您对“重复”的定义)。在以下情况下,将丢弃一个值:

var a = {b:1}
var o = {};
o.one = a;
o.two = a;
// one and two point to the same object, but two is discarded:
JSON.stringify(o, ...);

但概念是:使用自定义替换器,并跟踪解析的对象值。

作为es6中编写的实用函数:

// safely handles circular references
JSON.safeStringify = (obj, indent = 2) => {
  let cache = [];
  const retVal = JSON.stringify(
    obj,
    (key, value) =>
      typeof value === "object" && value !== null
        ? cache.includes(value)
          ? undefined // Duplicate reference found, discard key
          : cache.push(value) && value // Store value in our collection
        : value,
    indent
  );
  cache = null;
  return retVal;
};

// Example:
console.log('options', JSON.safeStringify(options))

其他回答

superserial完全序列化JavaScript对象。

https://github.com/denostack/superserial

用法:

const serializer = new Serializer();

const nodes = [{ self: null as any, siblings: [] as any[] }, {
  self: null as any,
  siblings: [] as any[],
}];
nodes[0].self = nodes[0];
nodes[0].siblings = nodes;
nodes[1].self = nodes[1];
nodes[1].siblings = nodes;

const serialized = serializer.serialize(nodes);

console.log(serialized);

输出:

[$1,$2];{"self":$1,"siblings":$0};{"self":$2,"siblings":$0}

使用带有自定义替换符的JSON.stringify。例如:

// Demo: Circular reference
var circ = {};
circ.circ = circ;

// Note: cache should not be re-used by repeated calls to JSON.stringify.
var cache = [];
JSON.stringify(circ, (key, value) => {
  if (typeof value === 'object' && value !== null) {
    // Duplicate reference found, discard key
    if (cache.includes(value)) return;

    // Store value in our collection
    cache.push(value);
  }
  return value;
});
cache = null; // Enable garbage collection

本例中的替换符并非100%正确(取决于您对“重复”的定义)。在以下情况下,将丢弃一个值:

var a = {b:1}
var o = {};
o.one = a;
o.two = a;
// one and two point to the same object, but two is discarded:
JSON.stringify(o, ...);

但概念是:使用自定义替换器,并跟踪解析的对象值。

作为es6中编写的实用函数:

// safely handles circular references
JSON.safeStringify = (obj, indent = 2) => {
  let cache = [];
  const retVal = JSON.stringify(
    obj,
    (key, value) =>
      typeof value === "object" && value !== null
        ? cache.includes(value)
          ? undefined // Duplicate reference found, discard key
          : cache.push(value) && value // Store value in our collection
        : value,
    indent
  );
  cache = null;
  return retVal;
};

// Example:
console.log('options', JSON.safeStringify(options))

我为LoggingUtilities类创建了以下方法。以下方法获取源和目标对象,并通过给定的maxLevel将源分配给目标。

  static assignObjectByLevel(
    sourceObject: any,
    targetObject: any,
    currentLevel: number = 0,
    maxLevel: number = 3,
    showUndefinedValues = false
  ): any {
    if (currentLevel >= maxLevel) {
      return;
    }

    const objQueue = [];
    for (const key in sourceObject) {
      if (sourceObject.hasOwnProperty(key)) {
        const value = sourceObject[key];
        if (typeof value === "object") {
          objQueue.push({ key, value });
        } else {
          targetObject[key] = value;
        }
      } else {
        if (showUndefinedValues) {
          targetObject[key] = "undefined/null";
        }
      }
    }

    while (objQueue.length > 0) {
      const objVal = objQueue.pop();
      currentLevel++;
      targetObject[objVal.key] = {};
      this.assignObjectByLevel(
        objVal.value,
        targetObject[objVal.key],
        currentLevel,
        maxLevel,
        false
      );
    }
  }

用法示例:

   const logObjParam = {
      level1: "value1",
      level2: {
        value2: "value2",
        level3: {
          value3: "value3",
          level4: {
            value4: " value4",
            level5: {
              value5: " value5",
            },
          },
        },
      },
    };

 let logObj = {};
 this.assignObjectByLevel(logObjParam, logObj);

结果:

{
  "level1": "value1",
  "level2": {
    "value2": "value2",
    "level3": {
      "value3": "value3",
      "level4": {}
    }
  }
}

使用带有替换符的JSON.stringify方法。有关详细信息,请阅读本文档。http://msdn.microsoft.com/en-us/library/cc836459%28v=vs.94%29.aspx

var obj = {
  a: "foo",
  b: obj
}

var replacement = {"b":undefined};

alert(JSON.stringify(obj,replacement));

找出用循环引用填充替换数组的方法。您可以使用typeof方法来查找属性的类型是否为“object”(引用),并使用精确的等式检查(==)来验证循环引用。

此解决方案修复了用户2451227报告的接受答案问题(当o={};JSON.stringify([o,o],getCircularReplacer()))。

函数newCircularReplacer(){常量seenValues=[]返回循环替换器函数circleReplacer(键,值){if(typeof value=='object'&&value!==null&&object.keys(value).length){常量堆栈大小=参见值长度if(堆栈大小){for(设n=stackSize-1;参见nValues[n][key]!==value;--n)seenValues.pop()//清除过期的引用if(参见nValues.includes(value))返回'[Circular]'}参见值push(value)}返回值}}设o={a:1}o.b=o//循环参考控制台日志(JSON.stringify(o,newCircularReplacer())//{a:1,b:[Circular]}✅)o={}a=[o,o]//非循环参考控制台日志(JSON.stringify(a,newCircularReplacer())//[{},{}]✅)