如何从数组中删除空白元素?

我有下面的数组

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]

我想从数组中删除空白元素，并希望得到以下结果:

cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

有没有像compact这样不需要循环的方法?

当前回答

以下是对我有效的方法:

[1, "", 2, "hello", nil].reject(&:blank?)

输出:

[1, 2, "hello"]

其他回答

有很多方法可以做到这一点，其中之一是拒绝

noEmptyCities = cities.reject { |c| c.empty? }

你也可以用reject!，这将改变城市的位置。如果拒绝某项，它将返回cities作为返回值，如果没有拒绝，则返回nil。如果你不小心，这可能是一个陷阱(感谢ninja08在评论中指出这一点)。

使用拒绝:

>> cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].reject{ |e| e.empty? }
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

更新在拒绝和拒绝!

注意:我遇到了这个问题，并在irb控制台上用ruby-3.0.1检查了这些方法。我也检查了ruby文档，但没有提到这一点。我不确定从哪个ruby版本变化就在那里。非常感谢来自社区的任何帮助。

在ruby-3.0.1中，我们可以使用reject或reject!

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.reject{ |e| e.empty? }
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

或简写

cities.reject(&:empty?)
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

无论我们是否有一个空值，两者都会返回[]?

另一种方法:

> ["a","b","c","","","f","g"].keep_if{|some| some.present?}
=> ["a","b","c","f","g"]

 cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].delete_if {|c| c.empty? }

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