您知道有什么方法可以删除存储在Core Data中的所有条目吗?我的schema应该保持不变;我只想把它重置为空白。
Edit
我希望以编程方式做到这一点,这样用户就可以基本上按下重置按钮。
您知道有什么方法可以删除存储在Core Data中的所有条目吗?我的schema应该保持不变;我只想把它重置为空白。
Edit
我希望以编程方式做到这一点,这样用户就可以基本上按下重置按钮。
当前回答
龙道9+ Swift 2
删除所有实体中的所有对象
func clearCoreDataStore() {
let entities = managedObjectModel.entities
for entity in entities {
let fetchRequest = NSFetchRequest(entityName: entity.name!)
let deleteReqest = NSBatchDeleteRequest(fetchRequest: fetchRequest)
do {
try context.executeRequest(deleteReqest)
} catch {
print(error)
}
}
}
其他回答
作为一个快速参考,以节省在其他地方搜索-删除后重新创建持久存储可以用:
if (![persistentStoreCoordinator addPersistentStoreWithType:NSSQLiteStoreType configuration:nil URL:storeURL options:nil error:&error]) {
// do something with the error
}
下面这个版本可以删除每个表中的每条记录。
斯威夫特4
static func resetDatabase() {
do {
try dataStore.persistentStoreCoordinator.managedObjectModel.entities.forEach { (entity) in
if let name = entity.name {
let fetch = NSFetchRequest<NSFetchRequestResult>(entityName: name)
let request = NSBatchDeleteRequest(fetchRequest: fetch)
try mainContext.execute(request)
}
}
try mainContext.save()
} catch {
print("error resenting the database: \(error.localizedDescription)")
}
}
Swift 5.1解决方案
public static func reset() {
let coordinator = _persistentContainer.persistentStoreCoordinator
for store in coordinator.persistentStores where store.url != nil {
try? coordinator.remove(store)
try? FileManager.default.removeItem(atPath: store.url!.path)
}
}
使用这个
+(NSArray *)fetchDataFromEntity:(NSString *)entityName context:(NSManagedObjectContext *)context
{
NSFetchRequest * fetchRequest =[[NSFetchRequest alloc] init];
NSEntityDescription * CategoriesEntity = [NSEntityDescription entityForName:entityName inManagedObjectContext:context];
[fetchRequest setEntity:CategoriesEntity];
NSError * error;
NSInteger count = [context countForFetchRequest:fetchRequest error:&error];
if (count && count>0) {
NSArray * fetchedObjects = [context executeFetchRequest:fetchRequest error:&error];
if (fetchedObjects && fetchedObjects.count>0) {
return fetchedObjects;
}else
return nil;
}
else
return nil;
}
+ (void)deleteObjectsOfArray:(NSMutableArray*)ary context:(NSManagedObjectContext *)context {
for (NSManagedObject * obj in ary) {
[context deleteObject:obj];
}
NSError *saveError = nil;
[context save:&saveError];
}
+ (void)deleteEntity:(NSString *)entityName context:(NSManagedObjectContext *)context {
NSArray *listArray = [self fetchDataFromEntity:entityName context:context];
[self deleteObjectsOfArray:[NSMutableArray arrayWithArray:listArray] context:context];
}
我采取了Grouchal的代码,为了加快速度,我使用了并发模式的枚举(NSEnumerationConcurrent),它比for循环快了一点(在我的应用程序中,我为测试人员添加了这个功能,以便他们可以清除数据和做测试用例,而不是删除和安装应用程序)
- (void)resetObjects
{
[self deleteAllObjectsInEntity:@"Entity1"];
[self deleteAllObjectsInEntity:@"Entity2"];
[self deleteAllObjectsInEntity:@"Entity3"];
[self deleteAllObjectsInEntity:@"Entity4"];
}
-(void) deleteAllObjectsInEntity:(NSString*) entityName
{
MainDataContext *coreDataContext = [MainDataContext sharedInstance];
NSManagedObjectContext *currentContext = coreDataContext.managedObjectContext;
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:entityName inManagedObjectContext:currentContext];
[fetchRequest setEntity:entity];
NSError *error;
NSArray *items = [currentContext executeFetchRequest:fetchRequest error:&error];
[items enumerateObjectsWithOptions:NSEnumerationConcurrent usingBlock:^(NSManagedObject * obj, NSUInteger idx, BOOL *stop) {
[currentContext deleteObject:obj];
}];
if (![currentContext save:&error]) {
NSLog(@"Error deleting %@ - error:%@",entityName,error);
}
}