您知道有什么方法可以删除存储在Core Data中的所有条目吗?我的schema应该保持不变;我只想把它重置为空白。


Edit

我希望以编程方式做到这一点,这样用户就可以基本上按下重置按钮。


当前回答

龙道9+ Swift 2

删除所有实体中的所有对象

func clearCoreDataStore() {
    let entities = managedObjectModel.entities
    for entity in entities {
        let fetchRequest = NSFetchRequest(entityName: entity.name!)
        let deleteReqest = NSBatchDeleteRequest(fetchRequest: fetchRequest)
        do {
            try context.executeRequest(deleteReqest)
        } catch {
            print(error)
        }
    }
}

其他回答

作为一个快速参考,以节省在其他地方搜索-删除后重新创建持久存储可以用:

if (![persistentStoreCoordinator addPersistentStoreWithType:NSSQLiteStoreType configuration:nil URL:storeURL options:nil error:&error]) {
// do something with the error
}

下面这个版本可以删除每个表中的每条记录。

斯威夫特4

static func resetDatabase() {
    do {
        try dataStore.persistentStoreCoordinator.managedObjectModel.entities.forEach { (entity) in
            if let name = entity.name {
                let fetch = NSFetchRequest<NSFetchRequestResult>(entityName: name)
                let request = NSBatchDeleteRequest(fetchRequest: fetch)
                try mainContext.execute(request)
            }
        }

        try mainContext.save()
    } catch {
        print("error resenting the database: \(error.localizedDescription)")
    }
}

Swift 5.1解决方案

public static func reset() {
    let coordinator = _persistentContainer.persistentStoreCoordinator
    for store in coordinator.persistentStores where store.url != nil {
        try? coordinator.remove(store)
        try? FileManager.default.removeItem(atPath: store.url!.path)
    }
}

使用这个

+(NSArray *)fetchDataFromEntity:(NSString *)entityName context:(NSManagedObjectContext *)context
{
    NSFetchRequest * fetchRequest =[[NSFetchRequest alloc] init];
    NSEntityDescription * CategoriesEntity = [NSEntityDescription entityForName:entityName inManagedObjectContext:context];
    [fetchRequest setEntity:CategoriesEntity];

    NSError * error;
    NSInteger count = [context countForFetchRequest:fetchRequest error:&error];

    if (count && count>0) {

        NSArray * fetchedObjects = [context executeFetchRequest:fetchRequest error:&error];
        if (fetchedObjects && fetchedObjects.count>0) {

            return fetchedObjects;
        }else
            return nil;

    }
    else
        return nil;
}
+ (void)deleteObjectsOfArray:(NSMutableArray*)ary context:(NSManagedObjectContext *)context {
    for (NSManagedObject * obj in ary) {
        [context deleteObject:obj];
    }
    NSError *saveError = nil;
    [context save:&saveError];
}
+ (void)deleteEntity:(NSString *)entityName context:(NSManagedObjectContext *)context {
    NSArray *listArray = [self fetchDataFromEntity:entityName context:context];
    [self deleteObjectsOfArray:[NSMutableArray arrayWithArray:listArray] context:context];
}

我采取了Grouchal的代码,为了加快速度,我使用了并发模式的枚举(NSEnumerationConcurrent),它比for循环快了一点(在我的应用程序中,我为测试人员添加了这个功能,以便他们可以清除数据和做测试用例,而不是删除和安装应用程序)

- (void)resetObjects
{
    [self deleteAllObjectsInEntity:@"Entity1"];
    [self deleteAllObjectsInEntity:@"Entity2"];
    [self deleteAllObjectsInEntity:@"Entity3"];
    [self deleteAllObjectsInEntity:@"Entity4"];
}

-(void) deleteAllObjectsInEntity:(NSString*) entityName
{
    MainDataContext *coreDataContext = [MainDataContext sharedInstance];
    NSManagedObjectContext *currentContext = coreDataContext.managedObjectContext;
    NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
    NSEntityDescription *entity = [NSEntityDescription entityForName:entityName inManagedObjectContext:currentContext];
    [fetchRequest setEntity:entity];

    NSError *error;
    NSArray *items = [currentContext executeFetchRequest:fetchRequest error:&error];

    [items enumerateObjectsWithOptions:NSEnumerationConcurrent usingBlock:^(NSManagedObject * obj, NSUInteger idx, BOOL *stop) {
        [currentContext deleteObject:obj];
    }];


    if (![currentContext save:&error]) {
        NSLog(@"Error deleting %@ - error:%@",entityName,error);
    }
}