值得注意的是

System.currentTimeMillis() has only millisecond accuracy at best. At worth its can be 16 ms on some windows systems. It has a lower cost that alternatives < 200 ns. System.nanoTime() is only micro-second accurate on most systems and can jump on windows systems by 100 microseconds (i.e sometimes it not as accurate as it appears) Calendar is a very expensive way to calculate time. (i can think of apart from XMLGregorianCalendar) Sometimes its the most appropriate solution but be aware you should only time long intervals.

用这个:

SimpleDateFormat format = new SimpleDateFormat("HH:mm");

Date d1 = format.parse(strStartTime);
Date d2 = format.parse(strEndTime);

long diff = d2.getTime() - d1.getTime();
long diffSeconds,diffMinutes,diffHours;

if (diff > 0) {
diffSeconds = diff / 1000 % 60;
diffMinutes = diff / (60 * 1000) % 60;
diffHours = diff / (60 * 60 * 1000);
}
else{
long diffpos = (24*((60 * 60 * 1000))) + diff;
diffSeconds = diffpos / 1000 % 60;
diffMinutes = diffpos / (60 * 1000) % 60;
diffHours = (diffpos / (60 * 60 * 1000));
}

(同样重要的是，例如，如果startTime是23:00,endTime是1:00，则持续时间为2:00。)

“else”部分可以得到正确的答案

如果你喜欢使用Java的日历API，你可以试试这个，

Date startingTime = Calendar.getInstance().getTime();
//later on
Date now = Calendar.getInstance().getTime();
long timeElapsed = now.getTime() - startingTime.getTime();

你的新类:

public class TimeWatch {    
    long starts;

    public static TimeWatch start() {
        return new TimeWatch();
    }

    private TimeWatch() {
        reset();
    }

    public TimeWatch reset() {
        starts = System.currentTimeMillis();
        return this;
    }

    public long time() {
        long ends = System.currentTimeMillis();
        return ends - starts;
    }

    public long time(TimeUnit unit) {
        return unit.convert(time(), TimeUnit.MILLISECONDS);
    }
}

用法:

    TimeWatch watch = TimeWatch.start();
    // do something
    long passedTimeInMs = watch.time();
    long passedTimeInSeconds = watch.time(TimeUnit.SECONDS);

之后，所经过的时间可以转换为任何你喜欢的格式，例如日历

Greetz, 查德

如果您从System.currentTimeMillis()获取时间戳，那么您的时间变量应该是长变量。

我发现这段代码在计时时很有用:

public class Et {
    public Et() {
    reset();
    }
    public void reset() {
    t0=System.nanoTime();
    }
    public long t0() {
        return t0;
    }
    public long dt() {
        return System.nanoTime()-t0();
    }
    public double etms() {
    return etms(dt());
    }
    @Override public String toString() {
        return etms()+" ms.";
    }
    public static double etms(long dt) {
        return dt/1000000.; // 1_000_000. breaks cobertura
    }
    private Long t0;
}