是否有一种方法可以在MySQL中使用PHP获取表的列名?


当前回答

调查:

mysql_query('DESCRIBE '.$table);

其他回答

这个怎么样:

SELECT @cCommand := GROUP_CONCAT( COLUMN_NAME ORDER BY column_name SEPARATOR ',\n')
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_SCHEMA = 'my_database' AND TABLE_NAME = 'my_table';

SET @cCommand = CONCAT( 'SELECT ', @cCommand, ' from my_database.my_table;');
PREPARE xCommand from @cCommand;
EXECUTE xCommand;

如果你喜欢的话,还有这个:

mysql_query('SHOW COLUMNS FROM tableName'); 

这对我很有效。

$sql = "desc MyTableName";
$result = @mysql_query($sql);
while($row = @mysql_fetch_array($result)){
    echo $row[0]."<br>";
}

您可以使用以下简单的命令获取整个表结构。

DESC TableName

或者您可以使用以下查询。

SHOW COLUMNS FROM TableName

我写了一个简单的php脚本,通过php获取表列: Show_table_columns.php

<?php
$db = 'Database'; //Database name
$host = 'Database_host'; //Hostname or Server ip
$user = 'USER'; //Database user
$pass = 'Password'; //Database user password
$con = mysql_connect($host, $user, $pass);
if ($con) {
    $link = mysql_select_db($db) or die("no database") . mysql_error();
    $count = 0;
    if ($link) {
        $sql = "
            SELECT column_name
            FROM   information_schema.columns
            WHERE  table_schema = '$db'
                   AND table_name = 'table_name'"; // Change the table_name your own table name
        $result = mysql_query($sql, $con);
        if (mysql_query($sql, $con)) {
            echo $sql . "<br> <br>";
            while ($row = mysql_fetch_row($result)) {
                echo "COLUMN " . ++$count . ": {$row[0]}<br>";
                $table_name = $row[0];
            }
            echo "<br>Total No. of COLUMNS: " . $count;
        } else {
            echo "Error in query.";
        }
    } else {
        echo "Database not found.";
    }
} else {
    echo "Connection Failed.";
}
?>

享受吧!