我有一个MS SQL Server 2008 Express系统,其中包含一个数据库,我想“复制和重命名”(用于测试目的),但我不知道一个简单的方法来实现这一点。
我注意到在R2版本的SQL Server中有一个复制数据库向导,但遗憾的是我无法升级。
我们讨论的数据库大约是1g。 我试图恢复我想复制到一个新数据库的数据库的备份,但没有运气。
我有一个MS SQL Server 2008 Express系统,其中包含一个数据库,我想“复制和重命名”(用于测试目的),但我不知道一个简单的方法来实现这一点。
我注意到在R2版本的SQL Server中有一个复制数据库向导,但遗憾的是我无法升级。
我们讨论的数据库大约是1g。 我试图恢复我想复制到一个新数据库的数据库的备份,但没有运气。
当前回答
<!doctype html >
<head>
<title>Copy Database</title>
</head>
<body>
<?php
$servername = "localhost:xxxx";
$user1 = "user1";
$pw1 = "pw1";
$db1 = "db1";
$conn1 = new mysqli($servername,$user1,$pw1,$db1);
if($conn1->connect_error) {
die("Conn1 failed: " . $conn1->connect_error);
}
$user2 = "user2";
$pw2 = "pw2";
$db2 = "db2";
$conn2 = new mysqli($servername,$user2,$pw2,$db2);
if($conn2->connect_error) {
die("Conn2 failed: " . $conn2->connect_error);
}
$sqlDB1 = "SELECT * FROM table1";
$resultDB1 = $conn1->query($sqlDB1);
if($resultDB1->num_rows > 0) {
while($row = $resultDB1->fetch_assoc()) {
$sqlDB2 = "INSERT INTO table2 (col1, col2) VALUES ('" . $row["tableRow1"] . "','" . $row["tableRow2"] . "')";
$resultDB2 = $conn2->query($sqlDB2);
}
}else{
echo "0 results";
}
$conn1->close();
$conn2->close();
?>
</body>
其他回答
使用MS SQL Server 2012,您需要执行3个基本步骤:
First, generate .sql file containing only the structure of the source DB right click on the source DB and then Tasks then Generate Scripts follow the wizard and save the .sql file locally Second, replace the source DB with the destination one in the .sql file Right click on the destination file, select New Query and Ctrl-H or (Edit - Find and replace - Quick replace) Finally, populate with data Right click on the destination DB, then select Tasks and Import Data Data source drop down set to ".net framework data provider for SQL server" + set the connection string text field under DATA ex: Data Source=Mehdi\SQLEXPRESS;Initial Catalog=db_test;User ID=sa;Password=sqlrpwrd15 do the same with the destination check the table you want to transfer or check box besides "source: ..." to check all of them
你完成了。
<!doctype html >
<head>
<title>Copy Database</title>
</head>
<body>
<?php
$servername = "localhost:xxxx";
$user1 = "user1";
$pw1 = "pw1";
$db1 = "db1";
$conn1 = new mysqli($servername,$user1,$pw1,$db1);
if($conn1->connect_error) {
die("Conn1 failed: " . $conn1->connect_error);
}
$user2 = "user2";
$pw2 = "pw2";
$db2 = "db2";
$conn2 = new mysqli($servername,$user2,$pw2,$db2);
if($conn2->connect_error) {
die("Conn2 failed: " . $conn2->connect_error);
}
$sqlDB1 = "SELECT * FROM table1";
$resultDB1 = $conn1->query($sqlDB1);
if($resultDB1->num_rows > 0) {
while($row = $resultDB1->fetch_assoc()) {
$sqlDB2 = "INSERT INTO table2 (col1, col2) VALUES ('" . $row["tableRow1"] . "','" . $row["tableRow2"] . "')";
$resultDB2 = $conn2->query($sqlDB2);
}
}else{
echo "0 results";
}
$conn1->close();
$conn2->close();
?>
</body>
您可以尝试分离数据库,在命令提示符下将文件复制到新的名称,然后附加两个db。
在SQL:
USE master;
GO
EXEC sp_detach_db
@dbname = N'OriginalDB';
GO
在命令提示符下(为了这个例子,我简化了文件路径):
copy c:\OriginalDB.mdf c:\NewDB.mdf
copy c:\OriginalDB.ldf c:\NewDB.ldf
还是用SQL:
USE master;
GO
CREATE DATABASE OriginalDB
ON (FILENAME = 'C:\OriginalDB.mdf'),
(FILENAME = 'C:\OriginalDB.ldf')
FOR ATTACH;
GO
CREATE DATABASE NewDB
ON (FILENAME = 'C:\NewDB.mdf'),
(FILENAME = 'C:\NewDB.ldf')
FOR ATTACH;
GO
解决方案,基于这条评论:https://stackoverflow.com/a/22409447/2399045。 只需设置:DB名称,临时文件夹,DB文件文件夹。 运行后,您将拥有名称为“sourceDBName_yyyy-mm-dd”格式的DB副本。
-- Settings --
-- New DB name will have name = sourceDB_yyyy-mm-dd
declare @sourceDbName nvarchar(50) = 'MyDbName';
declare @tmpFolder nvarchar(50) = 'C:\Temp\'
declare @sqlServerDbFolder nvarchar(100) = 'C:\Databases\'
-- Execution --
declare @sourceDbFile nvarchar(50);
declare @sourceDbFileLog nvarchar(50);
declare @destinationDbName nvarchar(50) = @sourceDbName + '_' + (select convert(varchar(10),getdate(), 121))
declare @backupPath nvarchar(400) = @tmpFolder + @destinationDbName + '.bak'
declare @destMdf nvarchar(100) = @sqlServerDbFolder + @destinationDbName + '.mdf'
declare @destLdf nvarchar(100) = @sqlServerDbFolder + @destinationDbName + '_log' + '.ldf'
SET @sourceDbFile = (SELECT top 1 files.name
FROM sys.databases dbs
INNER JOIN sys.master_files files
ON dbs.database_id = files.database_id
WHERE dbs.name = @sourceDbName
AND files.[type] = 0)
SET @sourceDbFileLog = (SELECT top 1 files.name
FROM sys.databases dbs
INNER JOIN sys.master_files files
ON dbs.database_id = files.database_id
WHERE dbs.name = @sourceDbName
AND files.[type] = 1)
BACKUP DATABASE @sourceDbName TO DISK = @backupPath
RESTORE DATABASE @destinationDbName FROM DISK = @backupPath
WITH REPLACE,
MOVE @sourceDbFile TO @destMdf,
MOVE @sourceDbFileLog TO @destLdf
原来我试图从备份中错误地进行恢复。
最初我创建了一个新数据库,然后尝试在这里恢复备份。 我本应该做的,也是最终有效的,是打开恢复对话框,并在目标字段中输入新数据库的名称。
因此,简而言之,从备份中恢复是有效的。
谢谢大家的反馈和建议