这是一个很好的宏，可以为NSMutableArray或NSArray工作:

#define reverseArray(__theArray) {\
    if ([__theArray isKindOfClass:[NSMutableArray class]]) {\
        if ([(NSMutableArray *)__theArray count] > 1) {\
            NSUInteger i = 0;\
            NSUInteger j = [(NSMutableArray *)__theArray count]-1;\
            while (i < j) {\
                [(NSMutableArray *)__theArray exchangeObjectAtIndex:i\
                                                withObjectAtIndex:j];\
                i++;\
                j--;\
            }\
        }\
    } else if ([__theArray isKindOfClass:[NSArray class]]) {\
        __theArray = [[NSArray alloc] initWithArray:[[(NSArray *)__theArray reverseObjectEnumerator] allObjects]];\
    }\
}

要使用，只需调用:reverseArray(myArray);

NSMutableArray *objMyObject = [NSMutableArray arrayWithArray:[self reverseArray:objArrayToBeReversed]];

// Function reverseArray 
-(NSArray *) reverseArray : (NSArray *) myArray {   
    return [[myArray reverseObjectEnumerator] allObjects];
}

要获得数组的反向副本，请参阅danielpunkass使用reverseObjectEnumerator的解决方案。

为了反转一个可变数组，你可以在你的代码中添加以下类别:

@implementation NSMutableArray (Reverse)

- (void)reverse {
    if ([self count] <= 1)
        return;
    NSUInteger i = 0;
    NSUInteger j = [self count] - 1;
    while (i < j) {
        [self exchangeObjectAtIndex:i
                  withObjectAtIndex:j];

        i++;
        j--;
    }
}

@end

反向数组并循环遍历它:

[[[startArray reverseObjectEnumerator] allObjects] enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    ...
}];

反向枚举数组的最有效方法:

使用enumerateObjectsWithOptions:NSEnumerationReverse usingBlock。使用@JohannesFahrenkrug上面的基准测试，这比[[array reverseObjectEnumerator] allObjects]快8倍;:

NSDate *methodStart = [NSDate date];

[anArray enumerateObjectsWithOptions:NSEnumerationReverse usingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    //
}];

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

一些基准

1. reverseObjectEnumerator allObjects

这是最快的方法:

NSArray *anArray = @[@"aa", @"ab", @"ac", @"ad", @"ae", @"af", @"ag",
        @"ah", @"ai", @"aj", @"ak", @"al", @"am", @"an", @"ao", @"ap", @"aq", @"ar", @"as", @"at",
        @"au", @"av", @"aw", @"ax", @"ay", @"az", @"ba", @"bb", @"bc", @"bd", @"bf", @"bg", @"bh",
        @"bi", @"bj", @"bk", @"bl", @"bm", @"bn", @"bo", @"bp", @"bq", @"br", @"bs", @"bt", @"bu",
        @"bv", @"bw", @"bx", @"by", @"bz", @"ca", @"cb", @"cc", @"cd", @"ce", @"cf", @"cg", @"ch",
        @"ci", @"cj", @"ck", @"cl", @"cm", @"cn", @"co", @"cp", @"cq", @"cr", @"cs", @"ct", @"cu",
        @"cv", @"cw", @"cx", @"cy", @"cz"];

NSDate *methodStart = [NSDate date];

NSArray *reversed = [[anArray reverseObjectEnumerator] allObjects];

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

结果:executionTime = 0.000026

2. 迭代一个reverseObjectEnumerator对象

这要慢1.5到2.5倍:

NSDate *methodStart = [NSDate date];
NSMutableArray *array = [NSMutableArray arrayWithCapacity:[anArray count]];
NSEnumerator *enumerator = [anArray reverseObjectEnumerator];
for (id element in enumerator) {
    [array addObject:element];
}
NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

结果:executionTime = 0.000071

3.sortedArrayUsingComparator

这要慢30到40倍(这里没有意外):

NSDate *methodStart = [NSDate date];
NSArray *reversed = [anArray sortedArrayUsingComparator: ^(id obj1, id obj2) {
    return [anArray indexOfObject:obj1] < [anArray indexOfObject:obj2] ? NSOrderedDescending : NSOrderedAscending;
}];

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

结果:executionTime = 0.001100

因此，当谈到速度和易用性时，[[anArray reverseObjectEnumerator] allObjects显然是赢家。