在我的iPhone应用程序中,我用相机拍了一张照片,然后我想把它调整为290*390像素。我用这个方法来调整图像的大小:
UIImage *newImage = [image _imageScaledToSize:CGSizeMake(290, 390)
interpolationQuality:1];
它工作得很好,但它是一个没有记录的功能,所以我不能再在iPhone OS4上使用它了。
所以…调整UIImage大小最简单的方法是什么?
如果你只想要一个更小的图像,不关心确切的大小:
+ (UIImage *)imageWithImage:(UIImage *)image scaledToScale:(CGFloat)scale
{
UIGraphicsBeginImageContextWithOptions(self.size, YES, scale);
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextSetInterpolationQuality(context, kCGInterpolationHigh);
[self drawInRect:CGRectMake(0, 0, self.size.width, self.size.height)];
UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return newImage;
}
将比例设置为0.25f将从800万相机中获得816 * 612的图像。
这里有一个UIImage+Scale的分类。
快速解决方案的拉伸填充,方面填补和方面适合
extension UIImage {
enum ContentMode {
case contentFill
case contentAspectFill
case contentAspectFit
}
func resize(withSize size: CGSize, contentMode: ContentMode = .contentAspectFill) -> UIImage? {
let aspectWidth = size.width / self.size.width
let aspectHeight = size.height / self.size.height
switch contentMode {
case .contentFill:
return resize(withSize: size)
case .contentAspectFit:
let aspectRatio = min(aspectWidth, aspectHeight)
return resize(withSize: CGSize(width: self.size.width * aspectRatio, height: self.size.height * aspectRatio))
case .contentAspectFill:
let aspectRatio = max(aspectWidth, aspectHeight)
return resize(withSize: CGSize(width: self.size.width * aspectRatio, height: self.size.height * aspectRatio))
}
}
private func resize(withSize size: CGSize) -> UIImage? {
UIGraphicsBeginImageContextWithOptions(size, false, self.scale)
defer { UIGraphicsEndImageContext() }
draw(in: CGRect(x: 0.0, y: 0.0, width: size.width, height: size.height))
return UIGraphicsGetImageFromCurrentImageContext()
}
}
要使用,您可以执行以下操作:
let image = UIImage(named: "image.png")!
let newImage = image.resize(withSize: CGSize(width: 200, height: 150), contentMode: .contentAspectFill)
感谢abdullahselek最初的解决方案。
使用这个扩展
extension UIImage {
public func resize(size:CGSize, completionHandler:(resizedImage:UIImage, data:NSData?)->()) {
dispatch_async(dispatch_get_global_queue(QOS_CLASS_USER_INITIATED, 0), { () -> Void in
let newSize:CGSize = size
let rect = CGRectMake(0, 0, newSize.width, newSize.height)
UIGraphicsBeginImageContextWithOptions(newSize, false, 1.0)
self.drawInRect(rect)
let newImage = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
let imageData = UIImageJPEGRepresentation(newImage, 0.5)
dispatch_async(dispatch_get_main_queue(), { () -> Void in
completionHandler(resizedImage: newImage, data:imageData)
})
})
}
}
为什么这么复杂?我认为使用系统API可以达到同样的效果:
UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
scale:1/ratio
orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.
唯一的问题是你应该传递目标比率的倒数作为第二个参数,因为根据文档,第二个参数指定原始图像与新缩放图像的比率。
这是一个与Swift 3和Swift 4兼容的UIImage扩展,它可以将图像缩放到给定的大小
extension UIImage {
func scaledImage(withSize size: CGSize) -> UIImage {
UIGraphicsBeginImageContextWithOptions(size, false, 0.0)
defer { UIGraphicsEndImageContext() }
draw(in: CGRect(x: 0.0, y: 0.0, width: size.width, height: size.height))
return UIGraphicsGetImageFromCurrentImageContext()!
}
func scaleImageToFitSize(size: CGSize) -> UIImage {
let aspect = self.size.width / self.size.height
if size.width / aspect <= size.height {
return scaledImage(withSize: CGSize(width: size.width, height: size.width / aspect))
} else {
return scaledImage(withSize: CGSize(width: size.height * aspect, height: size.height))
}
}
}
示例使用
let image = UIImage(named: "apple")
let scaledImage = image.scaleImageToFitSize(size: CGSize(width: 45.0, height: 45.0))