给定一个这样的字符串:

"The dog      has a long   tail, and it     is RED!"

什么样的jQuery或JavaScript魔法可以用来保持空间只有一个最大空间?

目标:

"The dog has a long tail, and it is RED!"

当前回答

let nameCorrection = function (str) {
  let strPerfect = str.replace(/\s+/g, " ").trim();
  let strSmall = strPerfect.toLowerCase();
  let arrSmall = strSmall.split(" ");
  let arrCapital = [];
  for (let x of arrSmall.values()) {
    arrCapital.push(x[0].toUpperCase() + x.slice(1));
  }

  let result = arrCapital.join(" ");
  console.log(result);
};
nameCorrection("Pradeep kumar dHital");

其他回答

var string = "The dog      has a long   tail, and it     is RED!";
var replaced = string.replace(/ +/g, " ");

或者如果你也想替换制表符:

var replaced = string.replace(/\s+/g, " ");

一种更健壮的方法:如果存在初始空格和尾随空格,则该方法也会删除它们。例如:

// NOTE the possible initial and trailing spaces
var str = "  The dog      has a long   tail, and it     is RED!  "

str = str.replace(/^\s+|\s+$|\s+(?=\s)/g, "");

// str -> "The dog has a long tail, and it is RED !"

你的例子没有这些空格,但它们也是一个非常常见的场景,而公认的答案只是把它们精简成单个空格,比如:“the…红色!,这不是您通常需要的。

var myregexp = new RegExp(/ {2,}/g);

str = str.replace(myregexp,' ');

我知道我迟到了,但我发现了一个很好的解决方案。

下面就是:

var myStr = myStr.replace(/[ ][ ]*/g, ' ');

我有一个方法,我叫它Derp方法因为没有更好的名字。

while (str.indexOf("  ") !== -1) {
    str = str.replace(/  /g, " ");
}

在JSPerf中运行它会得到一些令人惊讶的结果,它击败了一些更复杂的方法EDIT原始JSPerf链接http://jsperf.com/removing-multiple-spaces/3当时似乎已经死了