给定一个这样的字符串:
"The dog has a long tail, and it is RED!"
什么样的jQuery或JavaScript魔法可以用来保持空间只有一个最大空间?
目标:
"The dog has a long tail, and it is RED!"
给定一个这样的字符串:
"The dog has a long tail, and it is RED!"
什么样的jQuery或JavaScript魔法可以用来保持空间只有一个最大空间?
目标:
"The dog has a long tail, and it is RED!"
当前回答
let nameCorrection = function (str) {
let strPerfect = str.replace(/\s+/g, " ").trim();
let strSmall = strPerfect.toLowerCase();
let arrSmall = strSmall.split(" ");
let arrCapital = [];
for (let x of arrSmall.values()) {
arrCapital.push(x[0].toUpperCase() + x.slice(1));
}
let result = arrCapital.join(" ");
console.log(result);
};
nameCorrection("Pradeep kumar dHital");
其他回答
var string = "The dog has a long tail, and it is RED!";
var replaced = string.replace(/ +/g, " ");
或者如果你也想替换制表符:
var replaced = string.replace(/\s+/g, " ");
一种更健壮的方法:如果存在初始空格和尾随空格,则该方法也会删除它们。例如:
// NOTE the possible initial and trailing spaces
var str = " The dog has a long tail, and it is RED! "
str = str.replace(/^\s+|\s+$|\s+(?=\s)/g, "");
// str -> "The dog has a long tail, and it is RED !"
你的例子没有这些空格,但它们也是一个非常常见的场景,而公认的答案只是把它们精简成单个空格,比如:“the…红色!,这不是您通常需要的。
var myregexp = new RegExp(/ {2,}/g);
str = str.replace(myregexp,' ');
我知道我迟到了,但我发现了一个很好的解决方案。
下面就是:
var myStr = myStr.replace(/[ ][ ]*/g, ' ');
我有一个方法,我叫它Derp方法因为没有更好的名字。
while (str.indexOf(" ") !== -1) {
str = str.replace(/ /g, " ");
}
在JSPerf中运行它会得到一些令人惊讶的结果,它击败了一些更复杂的方法EDIT原始JSPerf链接http://jsperf.com/removing-multiple-spaces/3当时似乎已经死了