有一个快速的方法来设置HTML文本输入(<input type=text />),只允许数字击键(加上'.')?


当前回答

JavaScript代码:

function validate(evt)
{
    if(evt.keyCode!=8)
    {
        var theEvent = evt || window.event;
        var key = theEvent.keyCode || theEvent.which;
        key = String.fromCharCode(key);
        var regex = /[0-9]|\./;
        if (!regex.test(key))
        {
            theEvent.returnValue = false;

            if (theEvent.preventDefault)
                theEvent.preventDefault();
            }
        }
    }

HTML代码:

<input type='text' name='price' value='0' onkeypress='validate(event)'/>

工作完美,因为退格键码是8,正则表达式不让它,所以这是一个简单的方法来绕过bug:)

其他回答

下面是emkey08的JavaScript Wiki答案的一个面向对象的重新实现,它使用了一个EventListener对象实现。(参见:MDN web docs EventListener)

在某种程度上,它可以防止为每个过滤后的输入元素重复匿名事件处理程序函数声明,同时仍然允许它通过可选的回调。

/** * Base input {@see Element} {@see EventListener} filter abstract class * * @implements EventListener */ class AbstractInputFilter { /** * Attach the input filter to the input {@see Element} * * @param inputElement The input {@see Element} to filter * @param isValid - The callback that determines if the input is valid. * @throws Error */ constructor(inputElement, isValid = null) { // Abstract class if (this.constructor === AbstractInputFilter) { throw new Error("Object of Abstract Class cannot be created"); } if (typeof isValid === "function") { this.isValid = isValid; } for (const event of ["input", "keydown", "keyup", "mousedown", "mouseup", "select", "contextmenu", "drop"]) { inputElement.addEventListener(event, this); } } /** * Checks the value is valid * * @callback isValid default call-back that will throw * an {Error} if not implemented by extending this * {AbstractInputFilter} class. * * @param value The value to check * @returns {boolean} * @throws Error */ isValid(value) { throw new Error('must be implemented by callback!'); } /** * Handles the {@see event} dispatched by * the {@see EventTarget} object from the input {@see Element} * to filter its contant while it is being filled. * * @param event the {@see event} dispatched by * the {@see EventTarget} input {@see Element} * @override */ handleEvent(event) { const inputElement = event.currentTarget; if (this.isValid(inputElement.value)) { inputElement.oldValue = inputElement.value; inputElement.oldSelectionStart = inputElement.selectionStart; inputElement.oldSelectionEnd = inputElement.selectionEnd; } else if (inputElement.hasOwnProperty("oldValue")) { inputElement.value = inputElement.oldValue; inputElement.setSelectionRange( inputElement.oldSelectionStart, inputElement.oldSelectionEnd); } else { this.value = ""; } } } /** * Generic Input element {@see EventListener} filter * * @extends AbstractInputFilter * It needs the {@see AbstractInputFilter~isValid} callback * to determine if the input is valid. */ class InputFilter extends AbstractInputFilter {} /** * Unsigned Integer Input element {@see EventListener} filter * @extends AbstractInputFilter */ class UIntInputFilter extends AbstractInputFilter { isValid(value) { return /^\d*$/.test(value); } } /** * Unsigned Float Input element {@see EventListener} filter * @extends AbstractInputFilter */ class UFloatInputFilter extends AbstractInputFilter { isValid(value) { return /^\d*\.?\d*$/.test(value); } } // Filter with pre-made InputFilters (re-use the filter) new UIntInputFilter(document.getElementById("UInt")); new UFloatInputFilter(document.getElementById("UFloat")); // Filter with custom callback filter anonymous function new InputFilter(document.getElementById("AlNum"), function(value) { return /^\w*$/.test(value); }); <label>Unsigned integer: </label><input id="UInt"><br/> <label>Unsigned float: </label><input id="UFloat"><br/> <label>AlphaNumeric (no special characters): </label><input id="AlNum">

jQuery的另一个简单方法:

$('.Numeric').bind('keydown',function(e){
    if (e.which < 48 || e.which > 57)
        return false;
    return true;
})

现在只需将每个输入类设置为Numeric,如下所示:

<input type="text" id="inp2" name="inp2" class='Numeric' />

2个解决方案:

使用表单验证器(例如jQuery验证插件)

在输入字段的onblur事件期间(即当用户离开字段时)执行检查,使用正则表达式:

<script type="text/javascript">
function testField(field) {
    var regExpr = new RegExp("^\d*\.?\d*$");
    if (!regExpr.test(field.value)) {
      // Case of error
      field.value = "";
    }
}

</script>

<input type="text" ... onblur="testField(this);"/>

我找不到一个明确的答案,它不会每次都遍历整个字符串,所以这里:

document.querySelectorAll("input").forEach(input => {
  input.addEventListener("input", e => {
    if (isNaN(Number(input.value[input.value.length-1])) && input.value[input.value.length-1] != '.') {
      input.value = input.value.slice(0, -1);
    }
  })
});

没有正则表达式,它会在每次输入时检查最后一个字符,如果它不是数字或句点,它就会切片。

使用这个DOM:

<input type = "text" onkeydown = "validate(event)"/>

还有这个脚本:

validate = function(evt)
{
    if ([8, 46, 37, 39, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 35, 36].indexOf(evt.keyCode || evt.which) == -1)
    {
        evt.returnValue = false;
        if(evt.preventDefault){evt.preventDefault();}
    }
}

...或者这个脚本,没有indexOf,使用两个for…

validate = function(evt)
{
    var CharValidate = new Array("08", "046", "039", "948", "235");
    var number_pressed = false;
    for (i = 0; i < 5; i++)
    {
        for (Ncount = 0; Ncount < parseInt(CharValidate[i].substring(0, 1)) + 1; Ncount++)
        {
            if ((evt.keyCode || evt.which) == parseInt(CharValidate[i].substring(1, CharValidate[i].lenght)) + Ncount)
            {
                number_pressed = true;
            }
        }
    }
    if (number_pressed == false)
    {
        evt.returnValue = false;
        if(evt.preventDefault){evt.preventDefault();}
    }
}

我使用onkeydown属性而不是onkeypress,因为onkeydown属性是在onkeypress属性之前检查的。问题出在谷歌Chrome浏览器上。

与属性“onkeypress”,标签将不可控与“preventDefault”谷歌chrome,然而,与属性“onkeydown”,标签变成可控!

9 . TAB =>的ASCII码

第一个脚本的代码比第二个脚本少,但是ASCII字符数组必须包含所有的键。

第二个脚本比第一个脚本大得多,但是数组并不需要所有的键。数组每个位置的第一位数字是每个位置将被读取的次数。对于每一个读数,都将加1到下一个读数。例如: NCount = 0

48 + NCount = 48

NCount + +

48 + NCount = 49

NCount + +

...

48 + NCount = 57 在数字键只有10(0 - 9)的情况下,但如果它们是100万个,那么创建一个包含所有这些键的数组就没有意义了。

ASCII代码:

8 ==>(退格); 46 =>(删除); 37 =>(左箭头); 39 =>(右箭头); 48 - 57 =>(数字); 36 => (home); 35 => (end);