背景

我刚刚把我的熊猫从0.11升级到0.13.0rc1。现在,应用程序弹出了许多新的警告。其中一个是这样的:

E:\FinReporter\FM_EXT.py:449: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_index,col_indexer] = value instead
  quote_df['TVol']   = quote_df['TVol']/TVOL_SCALE

我想知道这到底是什么意思?我需要改变什么吗?

如果我坚持使用quote_df['TVol'] = quote_df['TVol']/TVOL_SCALE,我应该如何暂停警告?

给出错误的函数

def _decode_stock_quote(list_of_150_stk_str):
    """decode the webpage and return dataframe"""

    from cStringIO import StringIO

    str_of_all = "".join(list_of_150_stk_str)

    quote_df = pd.read_csv(StringIO(str_of_all), sep=',', names=list('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefg')) #dtype={'A': object, 'B': object, 'C': np.float64}
    quote_df.rename(columns={'A':'STK', 'B':'TOpen', 'C':'TPCLOSE', 'D':'TPrice', 'E':'THigh', 'F':'TLow', 'I':'TVol', 'J':'TAmt', 'e':'TDate', 'f':'TTime'}, inplace=True)
    quote_df = quote_df.ix[:,[0,3,2,1,4,5,8,9,30,31]]
    quote_df['TClose'] = quote_df['TPrice']
    quote_df['RT']     = 100 * (quote_df['TPrice']/quote_df['TPCLOSE'] - 1)
    quote_df['TVol']   = quote_df['TVol']/TVOL_SCALE
    quote_df['TAmt']   = quote_df['TAmt']/TAMT_SCALE
    quote_df['STK_ID'] = quote_df['STK'].str.slice(13,19)
    quote_df['STK_Name'] = quote_df['STK'].str.slice(21,30)#.decode('gb2312')
    quote_df['TDate']  = quote_df.TDate.map(lambda x: x[0:4]+x[5:7]+x[8:10])
    
    return quote_df

更多错误消息

E:\FinReporter\FM_EXT.py:449: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_index,col_indexer] = value instead
  quote_df['TVol']   = quote_df['TVol']/TVOL_SCALE
E:\FinReporter\FM_EXT.py:450: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_index,col_indexer] = value instead
  quote_df['TAmt']   = quote_df['TAmt']/TAMT_SCALE
E:\FinReporter\FM_EXT.py:453: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_index,col_indexer] = value instead
  quote_df['TDate']  = quote_df.TDate.map(lambda x: x[0:4]+x[5:7]+x[8:10])

当前回答

对我来说奏效了:

import pandas as pd
# ...
pd.set_option('mode.chained_assignment', None)

其他回答

这应该可以工作:

quote_df.loc[:,'TVol'] = quote_df['TVol']/TVOL_SCALE

后续初学者问题/备注

也许这是对像我这样的初学者的澄清(我来自R,它的工作原理似乎有点不同)。以下看起来无害的功能代码不断产生SettingWithCopy警告,我不知道为什么。我已经阅读并理解了“链式索引”,但我的代码不包含任何:

def plot(pdb, df, title, **kw):
    df['target'] = (df['ogg'] + df['ugg']) / 2
    # ...

但是后来,太迟了,我查看了plot()函数被调用的地方:

    df = data[data['anz_emw'] > 0]
    pixbuf = plot(pdb, df, title)

所以"df"不是一个数据帧,而是一个对象,它以某种方式记住它是通过索引一个数据帧创建的(这是一个视图吗?)这将使plot()中的行,

 df['target'] = ...

相当于

 data[data['anz_emw'] > 0]['target'] = ...

这是链式索引。

不管怎么说,

def plot(pdb, df, title, **kw):
    df.loc[:,'target'] = (df['ogg'] + df['ugg']) / 2

固定它。

这可能只适用于NumPy,这意味着你可能需要导入它,但我为示例NumPy使用的数据在计算中不是必需的,但你可以简单地通过使用下面这一行代码来停止这个设置和复制警告消息:

np.warnings.filterwarnings('ignore')

对我来说,这个问题发生在下面一个简化的例子中。我也能够解决它(希望有一个正确的解决方案):

带有警告的旧代码:

def update_old_dataframe(old_dataframe, new_dataframe):
    for new_index, new_row in new_dataframe.iterrorws():
        old_dataframe.loc[new_index] = update_row(old_dataframe.loc[new_index], new_row)

def update_row(old_row, new_row):
    for field in [list_of_columns]:
        # line with warning because of chain indexing old_dataframe[new_index][field]
        old_row[field] = new_row[field]
    return old_row

输出old_row[field] = new_row[field]行的警告

因为update_row方法中的行实际上是Series类型,所以我将行替换为:

old_row.at[field] = new_row.at[field]

例如,用于访问/查找一个Series的方法。尽管两者都工作得很好,结果是相同的,这样我就不必禁用警告(=保留它们用于其他地方的其他链索引问题)。

有些人可能只是想压制这个警告:

class SupressSettingWithCopyWarning:
    def __enter__(self):
        pd.options.mode.chained_assignment = None

    def __exit__(self, *args):
        pd.options.mode.chained_assignment = 'warn'

with SupressSettingWithCopyWarning():
    #code that produces warning