我怎么用echo来做呢?

perl -E 'say "=" x 100'

当前回答

建议的Python解决方案的更优雅的替代方案可能是:

python -c 'print "="*(1000)'

其他回答

for i in {1..100}
do
  echo -n '='
done
echo

我的答案有点复杂,可能并不完美,但对于那些希望输出大数字的人来说,我能够在3秒内完成大约1000万。

repeatString(){
    # argument 1: The string to print
    # argument 2: The number of times to print
    stringToPrint=$1
    length=$2

    # Find the largest integer value of x in 2^x=(number of times to repeat) using logarithms
    power=`echo "l(${length})/l(2)" | bc -l`
    power=`echo "scale=0; ${power}/1" | bc`

    # Get the difference between the length and 2^x
    diff=`echo "${length} - 2^${power}" | bc`

    # Double the string length to the power of x
    for i in `seq "${power}"`; do 
        stringToPrint="${stringToPrint}${stringToPrint}"
    done

    #Since we know that the string is now at least bigger than half the total, grab however many more we need and add it to the string.
    stringToPrint="${stringToPrint}${stringToPrint:0:${diff}}"
    echo ${stringToPrint}
}

我猜这个问题的最初目的是仅用shell的内置命令来完成这个任务。因此,for循环和printfs是合法的,而下面的rep、perl和jot则不是。但是,下面的命令

$((COLUMNS/2))

例如,打印的窗户完全线 \/\/\/\/\/\/\/\/\/\/\/\/

问题是关于如何使用echo:

echo -e ''$_{1..100}'\b='

这将与perl -E 'say "=" x 100'完全相同,但只使用echo。

Python无处不在,在任何地方都能正常工作。

import sys;Print ('*' * int(sys.argv[1]))"" = " 100

Character和count作为单独的参数传递。