function date_getFullTimeDifference( $start, $end )
{
$uts['start']      =    strtotime( $start );
        $uts['end']        =    strtotime( $end );
        if( $uts['start']!==-1 && $uts['end']!==-1 )
        {
            if( $uts['end'] >= $uts['start'] )
            {
                $diff    =    $uts['end'] - $uts['start'];
                if( $years=intval((floor($diff/31104000))) )
                    $diff = $diff % 31104000;
                if( $months=intval((floor($diff/2592000))) )
                    $diff = $diff % 2592000;
                if( $days=intval((floor($diff/86400))) )
                    $diff = $diff % 86400;
                if( $hours=intval((floor($diff/3600))) )
                    $diff = $diff % 3600;
                if( $minutes=intval((floor($diff/60))) )
                    $diff = $diff % 60;
                $diff    =    intval( $diff );
                return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
            }
            else
            {
                echo "Ending date/time is earlier than the start date/time";
            }
        }
        else
        {
            echo "Invalid date/time data detected";
        }
}

用未来最大的1减去过去最大的1，然后除以60。

时间是Unix格式的，所以它们只是一个大数字，显示了从格林尼治时间1970年1月1日00:00:00开始的秒数

以下是答案:

$to_time = strtotime("2008-12-13 10:42:00");
$from_time = strtotime("2008-12-13 10:21:00");
echo round(abs($to_time - $from_time) / 60,2). " minute";

这是一个简单的一行代码:

$start = new DateTime('yesterday');
$end = new DateTime('now');
$diffInMinutes = iterator_count(new \DatePeriod($start, new \DateInterval('PT1M'), $end));

<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>

减去这些次数，再除以60。

下面是一个计算从2019/02/01 10:23:45经过的时间(以分钟为单位)的例子:

$diff_time=(strtotime(date("Y/m/d H:i:s"))-strtotime("2019/02/01 10:23:45"))/60;