DateTime::diff很酷，但对于这种需要单个单元结果的计算来说很尴尬。手动减去时间戳效果更好:

$date1 = new DateTime('2020-09-01 01:00:00');
$date2 = new DateTime('2021-09-01 14:00:00');
$diff_mins = abs($date1->getTimestamp() - $date2->getTimestamp()) / 60;

用未来最大的1减去过去最大的1，然后除以60。

时间是Unix格式的，所以它们只是一个大数字，显示了从格林尼治时间1970年1月1日00:00:00开始的秒数

<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>

我想这对你有帮助

function calculate_time_span($date){
    $seconds  = strtotime(date('Y-m-d H:i:s')) - strtotime($date);

        $months = floor($seconds / (3600*24*30));
        $day = floor($seconds / (3600*24));
        $hours = floor($seconds / 3600);
        $mins = floor(($seconds - ($hours*3600)) / 60);
        $secs = floor($seconds % 60);

        if($seconds < 60)
            $time = $secs." seconds ago";
        else if($seconds < 60*60 )
            $time = $mins." min ago";
        else if($seconds < 24*60*60)
            $time = $hours." hours ago";
        else if($seconds < 24*60*60)
            $time = $day." day ago";
        else
            $time = $months." month ago";

        return $time;
}

function date_getFullTimeDifference( $start, $end )
{
$uts['start']      =    strtotime( $start );
        $uts['end']        =    strtotime( $end );
        if( $uts['start']!==-1 && $uts['end']!==-1 )
        {
            if( $uts['end'] >= $uts['start'] )
            {
                $diff    =    $uts['end'] - $uts['start'];
                if( $years=intval((floor($diff/31104000))) )
                    $diff = $diff % 31104000;
                if( $months=intval((floor($diff/2592000))) )
                    $diff = $diff % 2592000;
                if( $days=intval((floor($diff/86400))) )
                    $diff = $diff % 86400;
                if( $hours=intval((floor($diff/3600))) )
                    $diff = $diff % 3600;
                if( $minutes=intval((floor($diff/60))) )
                    $diff = $diff % 60;
                $diff    =    intval( $diff );
                return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
            }
            else
            {
                echo "Ending date/time is earlier than the start date/time";
            }
        }
        else
        {
            echo "Invalid date/time data detected";
        }
}

这就是我如何显示“xx次前”在php > 5.2 ..这里是DateTime对象的更多信息

//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate);    // output: 23 hrs ago

// Return the value of time different in "xx times ago" format
function ago($timestamp)
{

    $today = new DateTime(date('y-m-d h:i:s')); // [2]
    //$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
    $thatDay = new DateTime($timestamp);
    $dt = $today->diff($thatDay);

    if ($dt->y > 0){
        $number = $dt->y;
        $unit = "year";
    } else if ($dt->m > 0) {
        $number = $dt->m;
        $unit = "month";
    } else if ($dt->d > 0) {
        $number = $dt->d;
        $unit = "day";
    } else if ($dt->h > 0) {
        $number = $dt->h;
        $unit = "hour";
    } else if ($dt->i > 0) {
        $number = $dt->i;
        $unit = "minute";
    } else if ($dt->s > 0) {
        $number = $dt->s;
        $unit = "second";
    }
    
    $unit .= $number  > 1 ? "s" : "";
 
    $ret = $number." ".$unit." "."ago";
    return $ret;
}